similar to: current.panel.limits() of lattice returning NaN limits - why?

Dear all, How can I make an index plot with lattice, that is plotting a vector simply against its particular index in the vector, i.e. something similar to y <- rnorm(10) plot(y) I don't want to specify the x's manually, as this could become cumbersome when having multiple panels. I tried something like library(lattice) mp <- function(x, y, ...) { x <- 1:length(y)

I have the following graphic where I drop unused factors in the x axis, however I cannot get the first point on the second panel. It seems shifted. Any ideas? The example is below: data <- data.frame( Room=as.factor(c(132,132,132,132,132,132,132,132,132,196,196)),

Is there anyway to label axes in 3D plots with mathematical expressions? In the code below, I want to replace "delta_yrsed" with what "\Delta \widehat{yrsed}" represents in TeX, but the [xyz]lab parameters of title3d appear to only accept character strings. require("rgl") fn.delta.yrsed <- function(dist, delta.dist,

I would like to make the print format of the axis value labels appear as ``nn%'' instead of just the numbers. Is there a way to do this? Also, the x axis value labels on my horizontal barplot are rotated 90 degrees (perpendicular to the axis) no matter what I do. I tried las=1 but that didn't work. Is this doable? Thanks. $platform [1] "i686-pc-linux-gnu" $arch [1]

Hi, I'm having trouble plotting populations as separate colors and points in the 3d scatterplot package. I have a column with 4 different population names and 3 columns with my data. I want to plot each population with a different color and pch. In addition, I want to use the type="h" in my plotting so that I can see the points clearly in my graph( for publication purposes).

I would like to create a 3d scatterplot that is interactive in the sense that I can spin it on its axes to better visualize some PCA results I have. What are the options in R? I've looked at RGL and perhaps it will suffice but it wasn't apparent from the documentation I found. Any demo scripts available for a package that will work? Mark -- Mark W. Kimpel MD ** Neuroinformatics **

Have made a stacked area plot, but now want to manipulate the x axis: make in even increments (50) in order to suppress the tick marks (forming solid bar under plot). However, the plot functions do not seem to work, and I cannot find documentation for use of xat in stackpoly. This is a time series of data covering 579 years, and has been successfully converted from zoo to matrix. Data plotting

Dear list, Sorry for asking this question, but has something changed in the syntax for bwplot in Lattice? In an old publication, I used > bwplot( VOTMS ~gender |type * group, data=merge(vot,words,by="ord"), nint=30, horizontal=F, layout=c(3,3), box.ratio=0.8) which produced a lovelly 3x3 lattice plot with one

Dear list, I have been struggling to find how I would go about changing the bakground colors of groups in a lattice barchart in a way so that the auto.key generated also does the right thing and pick it up for the key. I have used the "col" argument (which I guess is sent to par()) in a way so that the colors are like I would want them, but now I guess I need to know which part part of

Dear list, I'm working on a panel function where I would like to be able to visualise data grouped by the category of the data, and then also changes in summary descriptives from one condition to another in the same scatter plot. Like the figure attached, but with one polygon for each subset of the data set given by a second variable (with colours still coming from the variable specified in

Dear list, I have a two character vector with two different values in them (two each, that is). Naturally, when I use these vectors as grouping factors in a lattice plot, I get four panels. Now, one of the possible four combinations will never have data, so one panel will always be empty. So now my question is: can I force R / Lattice not to print it, and give me only the 3 filled panels? I have

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Hello, Is it possible to draw level lines on the surface of a bivariate function? In the following example, to draw surface and levels lines for a multivariate normal law, I use persp, trans3d, contourLines and lines, but if the lines are correctly drawn, some parts of them are, of course, visible even if they are drawn on a non visible "face". Any suggestion to avoid this problem

Hello, I'm using the rgl package and plotting a plot with it. I'd like to have all the axes values auto-hide, but I want to plot a series of characters instead of the values of the measurement for 2 of the axes. So in the end I will have one axis (z actually) behave per normal (auto-hide) and I'd like the other two axes to be custom character vectors that auto-hide. Example: x <-

Hugh, (Note I speak for myself only and not for R-core) Thanks for looking into this. I think it's great to have community members that are interested in contributing to R and helping it continue to get better. And I think, and my local experiments bear out, that using anyNA as a fastpass condition does allow us to get a significant speedup over what's in there now. To do so, though, I

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Hi, I'm having a bit of trouble with 'scales="free"' in the segplot() function of latticeExtra. Say we need panels for each year, showing only those counties that are represented in each one: ---<--------------------cut here---------------start------------------->--- library(latticeExtra) data(USCancerRates) uscr.w <- subset(USCancerRates, state ==

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Dear list, I have been working on a report with around 60 images in it, and everything has been fine, until now. I find that the image output that is produced by odfWeave produces images that are NOT readable by OpenOffice or NeoOffice. I get empty boxes with Read-Error written in them. While generating the file using odfWeave, I can see them being generated on the screen, and they all seem fine.

Dear list, Sorry for asking this very silly question on the list, but I seem to have made my life complicated by going into string manipulation in vectors. What I need is to get the last part of a sting (the two last tokens, separated by a space), and of course, this should be done for all strings in a vector, creating a new vector of exual size. So, a <- c(" %L H*L L*H H%",