similar to: plotting many unique colors with categorical data

Hi, I'm trying to create a heatmap with color ranges for different values in my matrix. For example: If x > 5 , use orange gradient if x < 1.5, use red gradient ..... Right now I have the following: orgPal<-brewer.pal(3,"Oranges") bluPal<-brewer.pal(3,"Blues") redPal<-brewer.pal(3,"Reds") grad <- ifelse(randMat >

After trying to find if there was a color picker in the FAQs and the help, I thought I would send a post here. I was overwhelmed with all the wonderful color choices R has predefined (discovered after typing in colors()) but can't figure out what they all (by name) look like. Is there a color picker or some other method to display all those colors next to the name? I think I can put together

Dear List, I am new to lattice plots, and am having problems with getting my plot to do what I want. Specifically: 1. I would like the legend to have the same symbols as the plot. I tried simpleKey but can't seem to get it to work with autoKey. Right now my plot has dots (pch=19) and my legend shows circles. 2. I have nine groups but xyplot seems to only be using seven colors, so two

Anyone who is interested in using optimal colour palettes should look at the work of Cindy Brewer: www.colorbrewer.org I have written code to use her colour schemes in R. It is included below. Perhaps someone may find this interesting enough to work into a package. Included also is a function showpalette, which was posted here a while back. I don't remember who wrote it. I have copied all

Hi, I was trying to make a density plot with 13 samples. To distinguish each sample, it would be good if each color is as different as possible from the other colors. I could use the built in function, but that does not do more than 8 colors and then goes back to recycling the cols. If I use a palette, then it is really difficult to distinguish between the colors. So, is there a way that I can

Dear all, This seems like a simple problem but i've searched the help files and tried various options but failed, so apologies in advance for asking what i'm sure is an easy thing to do! In short, I have displayed behavioural data using the TraMineR package such that there is a colour change between the transition of behaviours, however, all the methods that i have used thus far have

Hola, no me funciona: Te contesto lo mismo que le contesté a otro compañero de la lista, espero ser más claro. Les comparto la carpeta con la capa y los datos que estoy usando. https://www.dropbox.com/s/umy0evt3qm1wr4d/dissolve.zip Esto es lo que estoy haciendo: library(rgdal) library(maptools) library(sp) library(classInt) library(RColorBrewer) zm <- readOGR(?.?, ?zmdis?) data <-

I've found RColorBrewer useful for its qualitative palettes, but wished that it could generate more than 12 qualitative palettes (e.g. with Set3). Any suggestions for alternative color palette generators that can handle e.g. 18 distinctive colors? (I'm aware of using rainbow(), but this doesn't generate enough distinct colors when the number of palettes is large). Thanks, Andrew

Hi, I am plotting a policy function (result from a dynamic stochastic optimization problem, discretized approximation). The policy function maps from an 2 x 2 x 2 x 3 x B x F state space to a B x F state space (B and F are usually between 4-6, and represent domestic and foreign savings. The other variables are income (Y), inflation (Pi), domestic and foreign interest rates (R and Z)). I

Hola, Intento representar en un mapa participaciones porcentuales de los sectores económicos y no logro hacerlo con spplot. He intentado con spplot(zm, c(?part88?, ?part93?), cuts=4, col.regions=brewer.pal(4, ?Set3?)) Lo pude hacer utilizando el base graphics de R, definiendo: > plotvar88 <- zm$part88 > nclr <- 8 > plotclr <- brewer.pal(nclr, "PuOr") > plotclr

Dear all I am using color2D.maplot to map some matrixes to plot. everything works fine. It seems that when my matrix contains only the same value color2D.maplot returns the following error: color2D.matplot(estimatedsr,redrange=c(0,1),greenrange=c(0,.5),bluerange=c(0,.5),xlab="x",ylab="y",main=sprintf('Estimated'),show.legend=TRUE,show.values=TRUE) Error in rgb(reds,

Hi, I would have expected that I get always 3 colors as result which is not true: hcl.colors(3, alpha=c(0, 0.5, 1)) # 3 colors rainbow(3, alpha=c(0, 0.5, 1)) # 3 colors heat.colors(3, alpha=c(0, 0.5, 1)) # 3 colors terrain.colors(3, alpha=c(0, 0.5, 1)) # 6 colors cm.colors(3, alpha=c(0, 0.5, 1)) # 6 colors topo.colors(3, alpha=c(0, 0.5, 1)) # 9 colors R-Version and

I'm working with the following code below to generate a how do I set the h,c, and l values such that the significant, positive residuals appear different on a grayscale printer from significant grayscale residuals. The challenge as I see it is that one can only distinguish the positive and negative residuals with the hue/. Varying the chroma and the luminance only affect the

I'm looking for a scheme to generate a default color palette for plotting points, lines and text (on a white or transparent background) with from 2 to say 9 colors with the following constraints: - "red" is reserved for another purpose - colors should be highly distinct - avoid light colors (like "yellow"s) In RColorBrewer, most of the schemes are designed for area fill

Hola, El problema con la propuesta de Olivier es que los intervalos son diferentes para cada variable. La forma sencilla y rápida es: spplot(zm["part88"], col.regions=plotclr, at=class$brks) Pero para que quede más elegante hay que dar algunos pasos más: ## Intervalos en forma character op <- options(digits=4) tab <- print(class) options(op) intChar <- names(tab) ## Indice

Hello, I'm trying to make a 3d plot using rgl in which the size and color of each point corresponds to certain attributes of each data point. The color attribute, let's call it X, is scaled to go from 0 to 1. The rainbow(64,start=0.7,end=0.1) palette is perfect for what I want but I don't know how to take that palette and pick a color from it based on the value of X for a given data

Hi I want to create a vector of colors that are as different from one another as possible. ?rainbow states "Conceptually, all of these functions actually use (parts of) a line cut out of the 3-dimensional color space...". This suggests to me that the resulting colors are all placed on this "line" and are equi-distant along it. The resulting color palette is a range of

I want to get a lighter shade of a color...I have a lot of colored objects and want each one printed as a foreground against a slightly lighter background. I thought I could try something like changing the alpha channel by first converting it to rgb. But prior to trying that, I'm stuck with how to get the color after converting using col2rgb() to be interpreted again as a color, rather than

Hello: I have a tab delim file with 100 rows and 100 columns. I have numerical values in this table. What I want is to create an image color map with color gradation. my values range from -5 to 0. max value is 0. to acheive this, I need to convert my data.frame into matrix. I tried following : mydf <- read.table('mytable',sep='\t',header=T) mydf1 <- mydf[,2:100]

Hi all, I have posted similar questions regarding this topic, but I just can't seem to get over the hump and find a straightforward way to do this. I have attached my file as a reference. Basically, the attached file is a 5 degree by 5 degree grid of the the world (2592 cells), most of them are NA's. I just want to be able to plot this grid over a world map and color code the cells. For