similar to: limits on liniar model

I'm familiar with the quantile() command, but what if I have a specific number that I want to know its location in a vector? I know that in known distributions, (for example the normal distribution), there is pnorm and qnorm, but how can I do it with unknown vector? thanks in advance _________________________________________________________________ Walla! Mail - [1]Get

Hi, the subject isn't define well the problem, so i'll explain it in detail: i've got a csv.file with data on number of factors (every column got the name of the factor as header and the data below). on another csv file, i've got the factors sorted by their type. for example- c1=read.csv('C:/R/c1.csv', header= TRUE) urrDate A_XS b_XS c_XS

Hello I have a problem that i ant make a Bar plot like the one i have tried to illustrate below (made in paint); http://www.nabble.com/file/p21437080/LG5%2Bgraf%2Bredigeret.jpg http://www.nabble.com/file/p21437080/LG5%2Bgraf%2Bredigeret.JPG LG5+graf+redigeret.JPG Where each line represents a model; model1 = 0.58*x+12.65 model2 = 1.16*x+12.65 But i only want the bars and with y-values above

Hi, I'm having trouble as of about noon today. I noticed I wasn't getting any new messages in Thunderbird. I restarted it and still nothing. I looked at the log, and found nothing from dovecot for a long time (since perhaps noon today). I restarted dovecot, but still it didn't get me new mail. I finally removed dovecot.* in my Maildir folder and restarted dovecot. I'm

Hi All, I just upgraded to the new 1.1rc5 from 1.0 that I had been using and it advised me to increase the file descriptor limit. I'm not sure how to do this. There is a command built into tcsh that allows me to do this called limit, but sudo limit 4224 doesn't work, and usually dovecot is started from the rc.local file if I recall right, and I'm not sure how to set this up from

I have a dataset where I have missing times (11:00 and 16:00). I would like the outputs to include the missing time so that the final time vector looks like "realt" and has the previous time's value. Ex. If meas at time 15:30 is 0.45, then the meas for time 16:00 will also be 0.45. meas are the measurements and times are the times at which they were taken. meas<-runif(18)

Hi, is there a way to replicate a data.frame like you can replicate the entries of a vector (with the repeat-function)? I want to do this: x <- data.frame(x, x) (where x is a data.frame). but n times. And it should be as cpu / memory efficient as possible, since n is pretty big in my case. thanks for any suggestions!

Dear all, I have one problem and did not find any solution.(I have also attached the problem in text file because sometimes column spacing is not good in mail) I have a file(file.txt) attached with this mail.I am reading it using this code to make a data frame (file)- file=read.table("file.txt",fill=T,colClasses = "character",header=T) file looks like this- Chr Pos

Hi, how can I print "<=" (I mean the symbol of just one character) in the main title of a plot? for example: plot(1:10, main=paste("x <=", x)) where variable x is some number generated on the fly. Thanks John

Dear R-users I need to fit a nonlinear model to a piece of data. The model to be fitted uses past values of the input and the ouput - something like y(k) ~ f(y(k-1),y(k-2),u(k),u(k-1) ....) (k is time index). As far as I know I could use earth(MARS), nnet and etc but I am not sure how to deal with the past values since most, if not all, examples I saw formula does not take in account past

<div dir='rtl'><div> <div dir="rtl"> <div dir="ltr">Could be... But the wierd thing here is if I change the array to be of size 256 and the index to be 'unsigned char', seems like there is no way to access the 'size' field throught "y->ptr[index]" (in your example) but clang still performs the re-read: <a

Hi I''m new here, and pretty much new on the rails. I''m trying to set up my application to send emails (needed for salted hash login) but i keep getting errors. i''m sure port 25 is not blocked since i''m able to send mails through PHP scripts. my smtp settings in config/enviroment.rb are: # Include your app''s configuration here:

Hi guys, I need your help with the boxplot. I've to create a boxplot starting from a table (.csv) in which there are the result of a test. Each column is a question and the rows are the answer of the respondents (from 0 to 5). Some answer is missing and has been filled with NA. the table has been loaded in R with the function read.csv I created the boxplot with the function boxplot and all

Thanks Bill. Do you and others think that a link to this guide (or another)should be included in the Posting Guide and/or R FAQ? -- Bert On Tue, May 17, 2011 at 4:07 PM, <Bill.Venables at csiro.au> wrote: > Amen to all of that, Bert. ?Nicely put. ?The google style guide (not perfect, but a thoughtful contribution on these kinds of issues, has avoiding attach() as its very first line.

hi there! I have a couple phones connected to a sipura ata and if I go into *- IVR, I press options on the regular phones and it all works fine and dandy. then I connect an xten softphone, a new extension in my dialplan, I dial the ivr, * asks me to dial something to go through it, I press keys on xten, but nothing happens, * just times out through as if I did not press anything! is there some

I have a list called "tabs" that I would like to have the same structure as my list "eqSystem." The two look like they have the same format but they are different because when I look at their attributes, class(eqSystem[[1]]) is "call" but class(tabs[[1]]) is "formula". I want to have class(tabs[[1]]) as a call too. So what does "call" mean? And how

I have a data.frame "e" and would like to extract the 23rd column, remove any NA's and then remove any values >= 30. I can do it in steps such as this but have failed to figure out how to do it in a single line .... any suggestions? first <- e[,23] second <- first[!is.na(first)] third <- second[second<=30] thanks a bunch J -- Dr. Jim Maas University of East

Hello all, I'm running a parameter grid optimization ( ksvm, kernlab package) and the optimizer seems not to converge for certain parameters and stays in a infinity loop. Would it be possible to abort the execution after x-seconds and continue with the next parameter set? Which R function do need to use to accomplish this? I had a look at, try() etc. but they didn't seem so fit my

I am trying to run an ANOVA on my soil respiration data, but I keep getting residual sum of squares and mean square of zero. As I understand it that would mean that the model terms explain all of the variation in the response variable. That should be virtually impossible, should it not? Where do I begin troubleshooting such a problem? -- View this message in context:

Hi Dear All, Can someone give me a suggestion about which robust statistics are most appropriate for outlier detection in linear models, and is available with R ? Thanks for any idea. -- View this message in context: http://r.789695.n4.nabble.com/Robust-Statistics-for-Outlier-Detection-tp3438493p3438493.html Sent from the R help mailing list archive at Nabble.com.