similar to: How to make a nomogam and Calibration plot

Hi R experts, I am trying to do a prognostic model validation study, using cancer survival data. There are 2 data sets - 1500 cases used to develop a nomogram, and another of 800 cases used as an independent validation cohort. I have validated the nomogram in the original data (easy with the Design tools), and then want to show that it also has good results with the independent data using 60

*I've been trying for several weeks to install R-2.2.1 on a PC with an AMD Athlon 64 2800*+* processor running Mandriva 2006_64. After unpacking R-2.2.1.tar.gz I ran ./configure. However, configure stopped prematurely with the message *"configure:27295: WARNING: gfortran and gcc disagree on int and double configure:27297: error: Maybe change CFLAGS or FFLAGS?"* Altough

Dear R_Help: The following gives me a matrix with integer values. z= matrix(rep(10:1, each= 10), ncol= 10, byrow=TRUE)> str(z)?int [1:10, 1:10] 10 9 8 7 6 5 4 3 2 1 ... How do I specify that I want Float32 values instead. Thanks,Chris

Hi,R_Help! I have done something like this: >x<-seq(412,612,1) >plot(x,dpois(x,512),col="blue",type="l") >plot(x,dnorm(x,512,sd=sqrt(512)),col="red",type="l") And now,I want to plot the two lines in the same picture or with the same "plot" action? What should I do? And any advises? Thank you in advance! 仭仭仭仭仭仭仭仭仭仭仭仭仭仭仭仭伖併佇伹

Try this: > x <- file("C:\\Users\\Jim\\Downloads\\PV2-ch2 - R_Help.ANA",+ encoding = "UTF-16")> y <- readLines(x)> head(y)[1] "1\t36,74\t0" "2\t269,02\t-44" "1\t326,62\t29" "2\t354,52\t24" [5] "8\t390,75\t1838" "2\t395,11\t-1053"> > Thanks Jim Holtman *Data Munger Guru*

Hi all R users I did a logistic regression with my binary variable Y (0/1) and 2 explanatory variables. Now I try to draw my nomogram with predictive value. I visited the help of R but I have problem to understand well the example. When I use glm fonction, I have a problem, thus I use lrm. My code is: modele<-lrm(Y~L+P,data=donnee) fun<- function(x) plogis(x-modele$coef[1]+modele$coef[2])

The rms package includes the nomogram function, which generates a list object that can be passed to plot for graphical production of nomograms. I would like to remove the "linear predictor" line in the graph, which means (I suspect) removing it from the nomogram output object. I've looked at the nomogram output object, but it is not clear to me if or how it might be edited to

Dear volunteer: I am a graduate student of medcine in china.And now,I am devoting myself to constructing a nomograms of bladder cancer.I want to do it with R-project.However, I do not know how to construct a nomograms with R-project.I want to get yours help,thank you! I wish you can tell me the operating procedure of the R-project. And I apologize for my english,it is poor,sorry!

Dear Geskus, I want to develop a prediction model. I followed your paper and analysed thro' weighted coxph approach. I can develop nomogram based on the final model also. But I do not know how to do internal validation of the model and subsequently obtain calibration plot. Is it possible to use Wolbers et al Epid 2009 approach 9 (R code for internal validation and calibration) . It is

Hello, I am using Dr. Harrell's design package to make a nomogram. I was able to make a beautiful one without stratifying, however, I will need to stratify to meet PH assumptions. This is where I go wrong, but I'm not sure where. Non-Stratified Nomogram:

Hi, I am trying to construct a logistic regression model from my data (104 patients and 25 events). I build a full model consisting of five predictors with the use of penalization by rms package (lrm, pentrace etc) because of events per variable issue. Then, I tried to approximate the full model by step-down technique predicting L from all of the componet variables using ordinary least squares

Dear R-users, I have used the nomogram function from the rms package for a logistic regresison model made with lrm(). Everything works perfectly (r version 2.15.1 on a mac). My question is this: if my final model is not the one created by lrm, but I internally validated the model and 'shrunk' the regression coefficients and computed a new intercept, how can I build a nomogram using that

Hello, I am using Dr. Harrell's design package to make a nomogram. I was able to make a beautiful one. However, I want to change 5-year survival probability to 5-year failure probability. I couldn?t get hazard rate from Hazard(f1) because I used cph for the model. Here is my code: f1 <- cph(Surv(retime,dfs) ~ age+her2+t_stage+n_stage+er+grade+cytcyt+Cyt_PCDK2 , data=data11, surv=T,

The report on R_help about problems loading package irr (in a UTF-8 locale, it seemed) prompted me to look a little deeper. There are quite a few packages with Latin-1 chars in their .R files, and a couple in UTF-8. Apart from non-ASCII chars in comments, this is a problem as the code concerned cannot be represented in some locales R runs in (for example Japanese on Windows). It happens

Hi List, does anyone know of an implementation of spatially constrained clustering in R? This is where there is a vector of measurements for points on a plane and only neighbors can be clustered together. I have tried implementint in myself -- but if someone has alkready done it ! I have searched on the obvios terms "spatially constrained clustering" without any luck.

Dear R-users, I am a novice R-user with some experience in using the RMS package for taking nomograms after various survival models. This time, I am trying to plot a nomogram after a Random Effects Cox, implemented by the "coxme" package. My questions are: 1. Is it possible to take a nomogram directly after the coxme survival function? 2. If not is there a way to take the linear

I am a new user of R for Windows, enthusiast about the many functions of the Design and Hmisc libraries. I combined the results of a Cox regression model after multiple imputation (of missing values in some covariates). Now I got my vector of coefficients (and of standard errors). My question is: How could I use directly that vector to run programs such as 'nomogram', 'calibrate',

Dear list, I'm facing the following problem : A cox model with my sex variable interacting with several continuous variables : cph(S~sex*(x1+x2+x3)) And I'd like to make a nomogram. I know it's a bit tricky and one mights argue that nomogram is not a good a choice... I could use the parameter interact=list(sex=("male","female"),x1=c(a,b,c))... but with rcs or pol

Hello, I am constructing a nomogram using cph and nomogram commands in Dr. Harrell's Design/RMS package. The HR that I obtain for dichotomous and categorical variables are identical to those that I obtain using STATA stcox. However, the inter-quartile HR I obtain for continuous variables is obviously different, since STATA gives me HR for each unit (year, centimeter, etc) like coxph would

Hi, I would like to emphasize ("zoom") the zone of a nomogram where the probability are > 0.01 (nomogram built with nomogram, Design). As a consequence, I don't need to draw the part of the "Total points" axis with score < 60 equivalent in my case to a linear predictor < 4.5 - As far as I know, this is not possible with the arguments of the function. - Changing