similar to: Problem Fixed: axes label

Dear All, I am trying to put 10^-8 st km^-2day^-1 on x-axis of my plot. I tried using : ylab = expression(paste("st / ", plain(km)^2, " / day")) to see if I can at least get the unit before thinking about the power of 10 (10^-8). However, ylab = expression(paste("st / ", plain(km)^2, " / day")) didn't give the result I expected. The power 2 in km was

Dear all, Using the code I got from the link ( http://www.phaget4.org/R/image_matrix.html), I obtained a nice plot that suits me. However, adding axes labels proved difficult for me . I have succeeded in adding a few things to the plot function so as to get what a better plot. Other things work but ylab="days" did not reflect. It will be great if somebody can advice on how to add axes

Hi Ogbos, Here is your sample data plotted in roughly the same way as the image. You can get the hours to start at the bottom, but it will require more code. swe$hour<-as.numeric(sapply(strsplit(swe$time,":"),"[",1)) swe$FD<-sample(1:2,nrow(swe),TRUE) library(plotrix) clock24.plot(swe$count,swe$hour,rp.type="s",radial.lim=c(3000,4010),

Dear All, This problem is over. Clock24.plot did the job. Thanks to all those who assisted me. Ogbos On Apr 22, 2016 8:34 PM, "Ogbos Okike" <giftedlife2014 at gmail.com> wrote: > Dear All, > One hand. Many thanks!! The code run as soon as I loaded lubridate. > > Please can you guide me on how to relate this code to my actual data. > My actual data is looking like:

Good day all. This is to thank all those who have helped in fixing this problem. Starting with a text book was indeed a problem, however, that gave me a clue of what I was looking for. This, with your contributions added to other materials I got on the net, put me on the right track. Thank you so much. Warmest regards Ogbos On 31 January 2010 14:07, S Ellison <S.Ellison@lgc.co.uk> wrote:

?s 01:43 de 29/03/2024, Ogbos Okike escreveu: > Dear Rui, > Thanks again for resolving this. I have already started using the version > that works for me. > > But to clarify the second part, please let me paste the what I did and the > error message: > >> set.seed(2024) >> data <- data.frame( > + Date = sample(seq(Sys.Date() - 5, Sys.Date(), by = "1

Dear All, Many thanks for bailing me out. Ogbos On Apr 18, 2016 9:07 PM, "David Winsemius" <dwinsemius at comcast.net> wrote: > > > On Apr 18, 2016, at 10:44 AM, Ogbos Okike <giftedlife2014 at gmail.com> > wrote: > > > > Dear ALL, > > Thank you so much for your contributions. > > I have made some progress. Below is a simple script I

Note the edited subject line! I don't know why I typed it as it was before. This says that as.numeric(as.character(f)) will work regardless of the implementation, and I agree. It's the recommendation to use as.numeric(levels(f))[f] that has me wondering about section 2.3.1 of the language definition. I expect that this idiom is in widespread use, and perhaps the language definition

Great stuff! Both plotrix and plotCI do the same but what count most here is the idea of assigning NA to some of the ciw values. Following your code, I assign "ciw[c(1,2,4,5,6,7,9,11)]<-NA" and that left me with the three error bars I wanted to display. Many thanks and warmest regards Ogbos On 7 April 2010 00:28, Jim Lemon <jim@bitwrit.com.au> wrote: > On 04/07/2010 03:49

Hi Uwe, I am pleased to inform you that this problem has, following your hint, been resolved. I installed 64-bit version of R and I was alright. Thanks again for your time. Ogbos 2009/6/24 Uwe Ligges <ligges@statistik.tu-dortmund.de> > > > ogbos okike wrote: > >> Hi, >> I have a data of size 981.1MB(1028707715) and I intend to calculate the >> length of the

Hey, Thanks for your great inputs. While "index = apply(mat == 0, MARGIN = 1, any)" gives you an idea of the rows containing zero(s), "index<-data[!apply(data==0,MARGIN=1,any),]" does the actual job of removing the rows with zeros. Kind regards Ogbos On 9 March 2010 15:12, Paul Hiemstra <p.hiemstra@geo.uu.nl> wrote: > Dimitris Rizopoulos wrote: > >>

Pat Burns makes a good point. -Peter -------- Original Message -------- Subject: Re: [R] Using seq_len() vs 1:n Date: Fri, 12 Feb 2010 09:01:20 +0000 From: Patrick Burns <pburns at pburns.seanet.com> To: Peter Ehlers <ehlers at ucalgary.ca> References: <4B746AEF.10900 at ucalgary.ca> If you want your code to be compatible with S+, then 'seq_len' isn't going to work.

Hey Duncan, Thank so much for the site. Quite helpful. Containing everything and informing me that raster has got no older version. I have also installed the new R version and I am fine. Regards Ogbos On 5 October 2010 15:11, Duncan Murdoch <murdoch.duncan@gmail.com> wrote: > On 05/10/2010 9:00 AM, ogbos okike wrote: > >> Hello, >> The R version on my system is R version

Hi Ogbos, You can just use ISOdate. If you pass more values, it will process them: ISOdate(2018,01,22) [1] "2018-01-22 12:00:00 GMT" > ISOdate(2018,01,22,18,17) [1] "2018-01-22 18:17:00 GMT" Add something like: if(is.null(data$hour),data$hour<-12 then pass data$hour as it will default to the same value as if you hadn't passed it. Jim On Mon, Jan 22, 2018 at 6:01

Looks like you forgot to load the lubridate package library(lubridate) You are calling functions days(), hours(), minutes(), seconds(), and hour() which all come from that package. ------------------------------------- David L Carlson Department of Anthropology Texas A&M University College Station, TX 77840-4352 -----Original Message----- From: R-help [mailto:r-help-bounces at

Folks: I know this may be overreaching, but are we missing what's important? WHY do the zeros occur? Are they values less then a known or unknown LOD? -- and/or is there positive mass on zero? In either case, using logs to calculate a geometric mean may not make sense. Paraphrasing Greg Snow, what is the scientific question? What is the model? Cheers, Bert On Mon, Jan 17, 2011 at 9:13 AM,

Dear Christophe, Yes. It was helpful indeed. The four steps you outlined successfully helped me to install the newest version of R. I have been fiddling with this for days and I am quite grateful to all who contributed. I formally posted to r-help@r-project.org before somebody suggested posting to r-sig-debian@r-project.org. Best regards Ogbos 2011/5/31 Christophe Bonenfant

Dear Christophe, Yes. It was helpful indeed. The four steps you outlined successfully helped me to install the newest version of R. I have been fiddling with this for days and I am quite grateful to all who contributed. I formally posted to r-help@r-project.org before somebody suggested posting to r-sig-debian@r-project.org. Best regards Ogbos 2011/5/31 Christophe Bonenfant

Dear list, Thanks for your time. I was surprised. While I was still waiting for your response, I entered R and discovered that it has been updated!!!! I hurried logged out and went home since I had overstayed battling with it. I wonder how the update happened with the numerous errors that were reported. I wish I will be able to find out, otherwise, I am off with my analysis with the new version :)

Hi, A terrific resource for this type of issue (and pretty much anything related to R) is http://rseek.org/ I'm sure I use it at least daily. Check out ... http://rseek.org/?q=pointsToRaster The first hit is about pointsToRaster() - it has been replaced by raster::rasterize() Cheers, Ben > On Apr 30, 2016, at 4:28 AM, Ogbos Okike <giftedlife2014 at gmail.com> wrote: > >