similar to: Matrix 3d plot

Displaying 20 results from an estimated 50000 matches similar to: "Matrix 3d plot"

2012 Jul 30
2
distance matrix and hclustering
Dear R Users,i am very new to R. I want your help on an issue regarding distance matrix and cluster analysis i had discharge data of 4 rivers(a,b,c,d) in 4 vectors each having 364 values > dput(qmu)structure(list(a = c(0.26, 0.25, 0.25, 0.25, 0.24, 0.23, 0.22, 0.21, 0.21, 0.21, 0.2, 0.19, 0.19, 0.19, 0.19, 0.18, 0.18, 0.18, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17,
2005 Jun 17
4
3D Scatter Plot
Hello: I would like to be able to do a 3D scatter plot from 3 variables, 2 independent and 1 dependent. The closest R function I could find for this is "cloud". However cloud uses, as input, a matrix where the value of each matrix element is the dependent variable value at that matrix coordinate. My problem is that the independent variable values are floating point and can be of
2006 Jun 25
1
Puzzled with contour()
Folks, The contour() function wants x and y to be in increasing order. I have a situation where I have a grid in x and y, and associated z values, which looks like this: x y z [1,] 0.00 20 1.000 [2,] 0.00 30 1.000 [3,] 0.00 40 1.000 [4,] 0.00 50 1.000 [5,] 0.00 60 1.000 [6,] 0.00 70 1.000 [7,] 0.00 80 0.000 [8,] 0.00 90
2012 Sep 28
2
Converting array to matrix
Hi, I have a 3d array as below, I want to make this array to a matrix of p=50(rows) and n=20(columns) with the coverage values . The code before the array is: library(binom) Loading required package: lattice pi.seq<-seq(from = 0.01, to = 0.5, by = 0.01) no.seq<-seq(from = 5, to = 100, by = 5) cp.all = binom.coverage( p = pi.seq, n = no.seq , conf.level = 0.95, method = "exact")
2012 Jul 06
3
estimating NA values against selected slots
Dear R Users, Could you please help me on the following issue? I have a real large yearly data set. For each year I have 365 flow values. Some of the flow values are not known and that’s why you will see NA written in those slots. I wanted to know, is there a way that I can estimate those values? I tried approx command but it seems least helpful for the kind of issue I am up against.
2006 May 08
1
persp or wireframe 3D plot: how can I independently adjust linewidth of the 'surface' and framebox?
It is a trivial matter to adjust the linewidth of the axes and plot line in a 2D plot: x <- 1:10; y <- 1:10; par(lwd=2); # axis (and others) linewidth plot(x,y,"l",lwd=6); # plot linewidth Is there anything comparable to this for persp or wireframe? I've tried a number of ways, and the framebox/axes seem to be linked to the linewidth used in generating the
2006 May 26
2
Is there a way to draw 3d plot?
Hi all, I have a 2D matrix, which has 100 rows, and 100 columns, I have a 2D matrix, with 100 rows and 100 columns, I want to display it using 3D plot, much like plot3d and mesh/surf functions in matlab. Specifically, in matlab, I just need to do the following: -------- [X, Y]=meshgrid([0:0.01:0.99, 0:0.01:0.99]); % Z is my 2D matrix, surf(X, Y, Z); -------- Note that X and Y are created so
2012 Jul 10
2
estimation of NA by predict command
Dear arun and all R users, I will first of all try to simply define my issue.. I have data in the following format Year Discharge dd/mm/yyyy x .. … … … There are some NA values in the discharge which I would like to predict by using “predict command”. I cant figure out the way to write the coding for that. Could you please help me on that??? I have also ,written
2011 Dec 29
2
3d plotting alternatives. I like persp, but regret the lack of plotmath.
I have been making simple functions to display regressions in a new package called "rockchalk". For 3d illustrations, my functions use persp, and I've grown to like working with it. As an example of the kind of things I like to do, you might consult my lecture on multicollinearity, which is by far the most detailed illustration I've prepared.
2012 Nov 28
1
Plot 3d density
I want to create a 3d plot with densities. I use the function density to first create a 2d dimensional plot for specific x values, the function then creates the density and puts them into a y variable. Now I have a second set of x values and put it again into the density function and I get a second set of y variables and so on.... I want to put those sets into a 3d plot, I hope you know what I
2015 Nov 11
3
Selección de elementos de dos listas
Hola La duda que tengo es la siguiente Quiero coger elementos de unas listas de valores y que haga un bucle con unas condiciones: que no sean iguales k y z y que si ha hecho la simulación para, por ejemplo 0.1 y 0.15, no lo haga para 0.15 y 0.1 (es decir tener combinaciones de esas litas) La primera condición es fácil, pero con la segunda lo conseguido creando una lista en txt y que la lea
2011 Oct 24
4
Lm function: Error in model.frame.default
Hello, I am trying to get a linear model of y ~ log(x). *> lm (y~log(x))* However, I always get an error report: /Error in model.frame.default(formula = y ~ log(x), drop.unused.levels = TRUE) : variable lengths differ (found for 'log(x)')/ *Here was my y:* > y [1] 0.4500000 0.0500000 0.5000000 0.4000000 0.0000000 0.5000000 0.4000000 [8] 0.0500000
2008 Sep 05
3
how to draw the legend about color from 3d picture
I have drawed a picture with persp, it's 3d map with different color, indicate different altitude. In gnuplot, the corresponding command 'splot' will generate a picture beside to indicate the relationship between color and altitude. But in R, how to draw it? I have read the manual of legend, but they are all about how to draw a legend with colored text, not a continuous varing color
2007 Apr 25
1
help
Hi all, I have 2 questions: 1)How do I calculate the mean on an imported txt file? I've imported the file below and that's what it looks like imported. How do I then calcuate the mean, median, or mode on the column LeafArea using the desktop R package? Any help would be greatly appreciated!! Thanks, Nat LeafType Leaflets LeafArea ShapeRatio LeafWeight LeafThickness 1 1
2001 Feb 22
1
Graphical parameters in perspective plot
Hello, I've a problem for setting graphical parameters in perspective plot (function persp). I wonder if it's possible to add some text (function text) on an existing persp plot USING the axis coordinates. In fact I want to add some text on a persp plot according to x coordinates. I've tried to use text(xcoord,ycoord, label="toto") but the toto text doesn't appear at
2005 Mar 03
3
3d plot of regression squared error
Hi. I'm trying to create a 3d plot for a teaching example of finding a least-squares estimate of the parameters to fit a line to some data. I was hoping to get a nice plot with a clear, single minima where the derivative of the surface is zero. No matter how much I tinker, I can't seem to get a simple straightforward plot. Am I doing something wrong? Thanks in anticipation, Ross-c x
2005 Mar 16
1
Help in persp (VERY URGENT ASSISTANCE)
Dear All, I am very new to R projects.May be i am wrong in some steps.I have given the code which i tried for drawing 3d surface using persp.I need to label the axes with scales z <- array(topnew2$V2, dim=c(600,2)) x <- 10 * (1:nrow(z)) y <- (1:ncol(z)) persp(x, y, z, theta = 30, phi = 30, expand = 0.5, col = "lightblue", xlab ="fluidlevel", ylab
2010 Apr 30
3
3D Surface plot
Dear All, I want to create a surface plot from the data. My data set is consists of x, y and z data. I plotted in very easy way by Excel worksheet as shown in the attached picture. I did some steps in R, but I cannot have the same plot as in Excel worksheet's figure. the R code is x <- c(-1,-0.75,-0.5,-0.25,0,0.25,0.5,0.75,1) y<- c(-1,-0.75,-0.5,-0.25,0,0.25,0.5,0.75,1) z<-
2008 Dec 06
1
Morlet wavelet not supportd by wavCWTPeaks
aa <- (structure(list(X.0.85 = c(-1.02, -1.17, -1.29, -1.39, -1.46, -1.5, -1.52, -1.5, -1.46, -1.39, -1.3, -1.19, -1.07, -0.93, -0.79, -0.65, -0.5, -0.36, -0.22, -0.08, 0.05, 0.18, 0.3, 0.41, 0.52, 0.62, 0.72, 0.81, 0.89, 0.98, 1.05, 1.13, 1.19, 1.25, 1.29, 1.31, 1.31, 1.29, 1.24, 1.16, 1.06, 0.93, 0.77, 0.58, 0.38, 0.16, -0.07, -0.31, -0.89, -1.05, -1.19, -1.31, -1.41, -1.47, -1.51, -1.51,
2017 Aug 09
2
Package nleqslv ERROR
Dear all, I am relatively new to R and have had some difficulty in understanding an error i get when running a code to solve a system of non-linear equations, with four equations and two variables. This is my code: ALPHA <- c(-0.0985168033402, 0.1, 0.15, 0.2, 0.25, 0.3, 0.35, 0.4) BETA <- c(-0.0985168033402, 0.1, 0.15, 0.2, 0.25, 0.3, 0.35, 0.4) GAMMA <- c(0.3940672148378, 0.1, 0.15,