similar to: How to build a matrix of number of appearance?

I want to write a function that get 2 strings y and z and does the following R command. temp<-qq1[qq1$z==y,] for example if it get y="AMI" and z="PrimaryConditionGroup" It should do the following temp<-qq1[qq1$PrimaryConditionGroup=="AMI",] I could do it by the following function that is ugly and I wonder if there is an easier way to do it espacielly when temp

Hi, This is only a small portion of the Data i am working on I want to make a subset of this data set( Data Set=Claims) MemberID ProviderID Vendor PCP Year Specialty 1 42286978 8013252 172193 37796 Y1 Surgery 2 97903248 3316066 726296 5300 Y3 Internal 3 2759427 2997752 140343 91972 Y1 Internal 4 73570559

Hello, I''m new to facebooker and ruby, so not sure if the issue I am having is due to my misunderstanding or a bug in facebooker plugin. Here is what I have: def show @current_user ||= facebook_session.user @member ||= params[:id].to_s==@current_user.id.to_s ? @current_user : Facebooker::User.new(params[:id]) #for each of current_user''s friends, check if they are

Dear R help, I tried to plot two qq plots in the same window using the code below.? Somehow it is plotting only one at a time.?? I borrowed the print function from xyplot. ? pdf("QQplotCorrUncorr.pdf") qq1<-qqPlot(residuals(fm), main="QQ plot for Correlated Model") qq2 <-qqPlot(residuals(fma), main="QQ plot for Uncorrelated Model") print(qq1, pos = c(0.0,

Hi... Here''s a working Perl script that I want to be able to do in Ruby: use WWW::Mechanize; my $url = "http://host/tt?name=chris"; my $mech = WWW::Mechanize->new(); $mech->add_header( Referer => "http://chrismcmahonsblog.blogspot.com" ); $mech->add_header( Cookie => "messageid=170118; memberid=1007"); $mech->get($url) so the header

I need to insert/update multiple MySQL columns in a single row with the func_odbc function at the SAME TIME. Someone showed me how to use ARRAY to retrieve multiple values at the same time, but I need to SET multiple values. Can this be done? If not, I will just stick with MySQL, but that's a pain in the ass because the asterisk-addons package has no default rpm spec file for building an

Dear R users, Would need some help. I will compare some results in a dotplot. The picture is very dark(grey) in the background, could I get it ligther? R-code dotplot(LINES~VAL, groups=QQ,key=simpleKey(levels(QQ1),space="top"),xlab="Values",main="Tail-Measure" ) (where LINES,VAL, QQ is vectors)

Hello, I am trying to see whether there has been a significant difference in whether people experienced damages from wildlife in two different years. I therefore have two columns: year 1: yes no no no yes yes no year 2: no yes no yes I wanted to do a chisq.test, but if I enter it this way: chisq.test(year1, year2) I get the error saying the columns are two different lengths. So then I tried

Hi, I have two datasets stored in tab-separated format in the following way file1: country year1 year2 Germany var1 var1 Hungary var1 var1 file2: country year1 year2 Germany var2 var2 Hungary var2 var2 I can easily read in these files, but how can I merge them as a panel dataset? Thanks, Viktor

I would like to know how I can assign a name to a name. I have a dataset that has different years in it. I am writing scripts using R and I would like to give a month a generic name and then use the generic name to do different analysis. The reason for the generic name would be so that I only have to change one thing if I wanted to change the year. For example. Year1 = 1999 datayear <-

Hi all! I am fitting a Poisson model, using the following command: > fit2<-glm(canc~id1+year1+time+lnpa,family=poisson) where 'id1', 'year1' and 'time' are factors. I defined them with: > id1<-C(factor(id1), treatment) and 'lnpa' is a continuous variable. The 'summary' function gives me all the effects estimates, that is, for id1, I

Hi I have monthly data and the dates are in MM/YY Format I need to convert them into DD/MM/YY format by pasting 01 in place of DD to all the observations in my Year Column ex: Year Stock Prices 01/2000 1 02/2000 2 03/2000 3 I need to convert them to Year Stock Prices 01/01/2000 1 01/02/2000 2 01/03/2000

I need to apply a yearly inflation factor to some wages and supply some simple sums by work category. I have gone at it with a brute force "for" loop approach which seems okay as it is a small dataset. It looks a bit inelegant and given all the warnings in the Intro to R, etc, about using loops I wondered if anyone could suggest something a bit simpler or more efficent? Example:

Dear R Experts, I am trying to produce a legend for a series of plots which are generated in a loop. The legend is supposed to look like this: 2000: gamma=1.8 where gamma is replaced by the greek letter and both the year and the value of gamma are stored in variables. Everything works fine as long as I have only one data series: year = 2001 g = 1.9 plot(1) legend('top',

Hello! I have measurements (length and volume) of fish collected in two years. I want to know if the the relationship between length and volume is the same for both years. The number of fish measured is different for each year. I don't know whether lm or aov is more appropriate to use. Here are the two output options: Call: lm(formula = Volume ~ Length * Year) Residuals: Min 1Q

Hi All, con <- member <- class <- list() for(i in 1:5) { con[[i]] <- odbcConnectAccess(paste("C:/Desktop/Data/source",i,".mdb",sep = '')) #read data from Access files member[[i]] <- sqlFetch(con[[i]],'member') #get table data from *.mdb files observe[[i]] <- sqlFetch(con[[i]],'observe') #get table data from *.mdb

I am graphing longitudinal data from three time points. I'd like to draw a solid line from point 1 to point 2, and then a dashed line from point 2 to point 3. It works if I do it in two steps: > first.vector <- c(mean(year1$variable1), mean(year2$variable1)) > second.vector <- c(NA, mean(year2$variable1), mean(year3$variable1)) > plot(first.vector, type="b",

Dear R Helpers I have following data - cash_flow = c(7, 7, 107)  # 107 = Principle 100 + interest of 7% t = c(1,2,3) and zero rate table as rating         year1           year2           year3 AAA            3.60            4.17              4.73 AA              3.65            4.22              4.78 A                 3.72           4.32              4.93 BBB            4.10           

Hi R-helpers, My real data is a panel (unbalanced and with gaps in years) of thousands of firms, by year and industry, and with financial information (variables X, Y, Z, for example), the number of firms by year and industry is not always equal, the number of years by industry is not always equal. #reproducible example firm1<-sort(rep(1:10,5),decreasing=F) year1<-rep(2000:2004,10)

Hi all, I am trying to display collective data from 3 MySQL tables: The query I have, so far, is SELECT c . * , COUNT( m.id ) AS `members` FROM `jos_mls_teams` AS `c` LEFT JOIN `jos_mls_teams_members` AS `m` ON m.teamid = c.id RIGHT JOIN ( SELECT u.name, u.lastvisitDate FROM `jos_users` AS `u` ) ON u.id = m.userid GROUP BY c.id LIMIT 0 , 30 But get the following error: #1248 - Every derived