similar to: Create Matrix with Float32 values

Hi all, Suppose we have the following matrix m <- matrix(c(1,2,3,2,1,3,3,1,2), ncol = 3, byrow=T) where in each row each number occurs only once. I'd like to define a permutation, e.g. 1 -> 2, 2 -> 1, 3 -> 3 and apply it to the matrix. Thus, the following matrix should result: m.perm <- matrix(c(2,1,3,1,2,3,3,2,1), ncol = 3, byrow=T) i.e. each 1 should map to 2 and vice

Dear R users, I am a new R user and something stops me when I try to write a academic article. I want to make a nomogram to predict the risk of prostate cancer (PCa) using several factors which have been selected from the Logistic regression run under the SPSS. Always, a calibration plot is needed to validate the prediction accuracy of the nomogram. However, I tried many times and read a lot of

Hi, I got this error every time when I put upper and lower bound on my parameters in nls. I'm not quite sure what this error is about. I also wanted to find the content of nls_port_fit. But typing this directly into R doesn't seem to give any result out. I also tried to see the content of If anybody could shed some light I'd greatly appreciate. Thank you. rc

----- Original Message ----- From: Villmow, Micah To: LLVM Developers Mailing List Sent: Friday, February 06, 2009 5:47 AM Subject: [LLVMdev] 16 bit floats I need to support 16 bit floats for some operations, outside of datatypes.td and the constants class, is there anything else I will need to modify to add f16 support? probably also code generation (can't give specifics, no

On Feb 5, 2009, at 12:51 PM, BGB wrote: > > ----- Original Message ----- > From: Villmow, Micah > To: LLVM Developers Mailing List > Sent: Friday, February 06, 2009 5:47 AM > Subject: [LLVMdev] 16 bit floats > > I need to support 16 bit floats for some operations, outside of > datatypes.td and the constants class, is there anything else I will > need to modify to

Hello, I'm having trouble performing a certain function within R and I was hoping someone might be able to help. I have a matrix (1000x21) that contains whole-number values ranging from 1-7 and I want to replace all entries within this matrix that have a value of 1 with a random number contained within a different dataframe that has 21 rows,1000 columns. I've tried using the if/else

Hello, I am working with a sparse matrix that is approx. 13,900 by 14,100. My goal is to select a row out of the matrix and create a new matrix with that row repeated 13,900 times without having to do any looping. Example: Starting Matrix: exampleMatrix 3 x 4 sparse Matrix of class "dgCMatrix" [1,] 1 . . . [2,] . 1 . 0.5 [3,] . . 1 .. New Matrix:.. newExampleMatrix 3 x 4 sparse

Hi Group, Consider a data frame like this: mylabel1 <- rep(c("A","B","C"),each=3) mylabel2 <- rep(c("A","B","C"),3) corrs <- c(1,.8,.7,.8,1,.7,.7,.7,1) myData <- data.frame(mylabel1,mylabel2,corrs) myData mylabel1 mylabel2 corrs 1 A A 1.0 2 A B 0.8 3 A C 0.7 4 B

Hi, I am having troubles in building xen unstable. make[3]: Entering directory `/data/xen/build/xen-unstable.hg-3.0-20060725.5/tools'' [ -f ioemu/config-host.h ] || \ (cd ioemu && sh configure --prefix=/usr) Install prefix /usr BIOS directory /usr/share/xen/qemu binary directory /usr/lib/xen/bin Manual directory /usr/share/man ELF interp prefix Source path

I have a very large dataframe and wish to extract a subset of rows. I have a two column matrix listing the starting and ending indices of one subset on each row. My idea is to create a vector of indices that could be applied to the dataframe and I have a solution using a for loop (below). But surely there is some more elegant way to do this! I looked thorough the archives without

*I've been trying for several weeks to install R-2.2.1 on a PC with an AMD Athlon 64 2800*+* processor running Mandriva 2006_64. After unpacking R-2.2.1.tar.gz I ran ./configure. However, configure stopped prematurely with the message *"configure:27295: WARNING: gfortran and gcc disagree on int and double configure:27297: error: Maybe change CFLAGS or FFLAGS?"* Altough

Hi,R_Help! I have done something like this: >x<-seq(412,612,1) >plot(x,dpois(x,512),col="blue",type="l") >plot(x,dnorm(x,512,sd=sqrt(512)),col="red",type="l") And now,I want to plot the two lines in the same picture or with the same "plot" action? What should I do? And any advises? Thank you in advance! 仭仭仭仭仭仭仭仭仭仭仭仭仭仭仭仭伖併佇伹

useR's, Consider: y <- c(20, 25, 30) > m <- matrix(c(0.0,1,NA,0.5,1.25,0.75, 0.5, NA, > NA),byrow=TRUE,nrow=3,ncol=3) > m [,1] [,2] [,3] [1,] 0.0 1.00 NA [2,] 0.5 1.25 0.75 [3,] 0.5 NA NA For each numeric value, I want to replace them with their corresponding y-value. The result should look like (here, each row represents a variable rather than the columns):

Hi, I am working on DSP module of Ne10. I see there are fixed-point and floating-point FFT inside Opus. Is fixed-point FFT only a fall back for CPU without VFP? On ARMv7-A and ARMv8-A, benchmark result shows that fixed-point (int32) and floating-point (float32) FFT have similar performance. I guess fixed-point version is not often used on these platforms. Is it worth the effort to NEON-optimize

Does anyone know how -log(x) can equal 743 but -log(x+0)=Inf? That's what the following stream of calculations suggest: Browse[2]> -log ( 1e-323+yMat2 - yMat1 * logitShape(matrix(parsList$Xs, nrow = numXs, ncol=numOfCurves), matrix(means, nrow = numXs, ncol=numOfCurves, byrow=TRUE), matrix(sigmas, nrow = numXs, ncol=numOfCurves, byrow=TRUE)) )[5,9] [1] Inf Yet: Browse[2]>

It's exactly what I was looking for, thanks. I'm replying to the whole list so others can skip this question, to not waste time on it. Bonne fin de journ?e de Montr?al (nous sommes le matin ici) On Fri, May 3, 2024 at 10:30?AM Marc Girondot <marc_grt at yahoo.fr> wrote: > Is it what you want ? > mat_letters <- matrix(data=c('A', 'B', 'C',

Hi, I have two (large) matrices A and B of dimensions (m,n) and (p,n) respectively. I'd like to see if the is a fast way to compute a new matrix C with dimension (m*p,n) in which each row in C is found by applying some function f to each pair of rows (x,y) where x is a row in A and y is a row in B. For example, if A <- matrix(c(1, 2, 3, 4, 5, 6), byrow=TRUE, ncol=3) B <- matrix(c(7,

Dear all, I am trying to create a 6-plot layout - 3 rows and 2 columns - so that only the top two plots have variable widths, all else with their default setting. Using "layout(matrix(c(1,2,3,4,5,6),3,2,byrow=T),widths=c(5,2))" rescales column #2 of all three rows, whereas I would like to rescale that of only row #1. Is there a simple way of doing this? Thanks, Manojit

Is there a way to get a copy of a matrix only for TRUE entries of a matching size boolean matrix? For *example*: > mat_letters <- matrix(data=c('A', 'B', 'C', 'D'), ncol=2, byrow=TRUE) > mat_letters [,1] [,2] [1,] "A" "B" [2,] "C" "D" > mat_bools <- matrix(data=c(FALSE, TRUE, TRUE, FALSE), ncol=2,

All, I have: x <- matrix(c(22,3,6,69,9,4,7,81,23,4,22,50),nrow=3,byrow=TRUE) rownames(x) <- c("Cold or flu","Headache","Backache"); colnames(x) <- c("Went to doctor","No response","Did nothing","Self-medicated") x <- t(x) print(x) barplot(x,beside=TRUE, ylim=c(0,90), xlab="Ailment",