similar to: Unexp. behavior from boot with multiple statistics

Hi List, need your help, property the here following. OS / Samba = samba-3.0.10-1.4E (RHEL4) Error message in Samba logfile = Invalid key XXX given to dptr_close This message comes then if by NT server with BrighStore a Backup is started. The Backup is made by a Share. all the same with or without kernel oplocks = no level2 oplocks = no oplocks = no without success Info: Error Log from

Fabian, Fast explains. On the NT server work BrightStore with version r9, more highly does not go because of NT. On the REHL4 side works (worked) BrightStore Linux Client r11.5. Smaller version does not work goes because of RHEL4. BrightStore servers r9 and Linux Client r11.5 are not compatible unfortunately. I must now decide everything with the version Share to work to get. Or the operating

Dear members, Please tell me what's wrong. After setig firewalld, I got fail on cloud-init with reboot. The server is rebooted, but I cannot access from internet. Before reboot I can access form internet. And before setig firewalld, there's no problem on reboot. /var/log/cloud-init.log shows following Jul 17 14:18:46 biz105 cloud-init: ci-info: !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!Route info

Hello, I have an input file: http://r.789695.n4.nabble.com/file/n3700031/testOut.txt testOut.txt where col 1 is chromosome, column2 is start of region, column 3 is end of region, column 4 and 5 is base position, column 6 is total reads, column 7 is methylation data, and column 8 is the strand. I would like a summary output file such as:

Hi, I have a dichotomous variable (Q1) whose answers are Yes or No. Also I have 2 categorical explanatory variables (V1 and V2) with two levels each. I used logistic regression to determine whether there is an effect of V1, V2 or an interaction between them. I used the R and SAS, just for the conference. It happens that there is disagreement about the effect of the explanatory variables

Hello, My name is Rodrigo, I am using R program and I have a trouble. I am trying to do a dendrogram with genetics information. Let me explain... The Similarity Matrix was already did, and with this matrix I want to construct a dendrogram. So, the distance is done. I need to transform this matrix (that I have) in a dendrogram, I woud be very grateful if someone could help me. PS: I am sending

Hello, I hope you can help me! I`m trying to tune svm parameters: cost and gamma for a landsat image classification, but I get an error and I can't understand it. I write this: > tune(svm, Class~., data = mdt01bis, ranges = list(gamma = 2^(-15:3), cost > = 2^(-5:15))) and R gives: Error en predict.svm(model, if (!is.null(validation.x)) validation.x else if (useFormula)

Dear R-helpers, Happy New Year to all the helpful members of the list. Here is the behavior I'm looking for: > v1 <- c("a","b","c") > n1 <- c(0, 1, 2) > v2 <- c("c", "a", "b") > n2 <- c(0, 1 , 2) > (f1 <- data.frame(v1, n1)) v1 n1 1 a 0 2 b 1 3 c 2 > (f2 <- data.frame(v2, n2))

Hi all, I have investigated the compile-time overhead of "Polly Scop Detection" pass based on LNT testing results. This mail is to share some results I have found. (1) Analysis of "SCOP Detection Pass" for PolyBench (Attached file PolyBench_SCoPs.log) Experimental results show that the "SCOP Detection pass" does not lead to significant extra compile-time

Hi, I am using Rattle 2.6.4 with R 2.12.2 on win64, is this a bug ? Following is the content after execute the associate analysis process: Summary of the Apriori Association Rules: Number of Rules: 23351 Summary of the Measures of Interestingness: support confidence lift Min. :0.1250 Min. :1 Min. :2.667 1st Qu.:0.1250 1st Qu.:1 1st Qu.:2.667 Median :0.1250

On 06/29/2013 05:04 PM, Star Tan wrote: > Hi all, > > > > I have investigated the compile-time overhead of "Polly Scop Detection" pass based on LNT testing results. > This mail is to share some results I have found. > > > (1) Analysis of "SCOP Detection Pass" for PolyBench (Attached file PolyBench_SCoPs.log) > Experimental results show that the

Hello, I probably have a syntax error in trying to generate an expected survival curve from a weighted cox model, but I can't see it. I used the help sample code to generate a weighted model, with the addition of a "weights=albumin" argument (I only chose albumin because it had no missing values, not because of any real relevance). Below are my code with the resulting error

At 2013-06-30 08:34:34,"Tobias Grosser" <tobias at grosser.es> wrote: >On 06/29/2013 05:04 PM, Star Tan wrote: >> Hi all, >> >> >> >> I have investigated the compile-time overhead of "Polly Scop Detection" pass based on LNT testing results. >> This mail is to share some results I have found. >> >> >> (1) Analysis

On 23.11.2012, at 15:12, john skaller <skaller at users.sourceforge.net> wrote: > > On 23/11/2012, at 5:46 PM, Sean Silva wrote: > >> Adding LLVMdev, since this is intimately related to the optimization passes. >> >>> I think this is roughly because some function level optimisations are >>> worse than O(N) in the number of instructions. >>

Hello all R-users _question 1_ I need to make a statistical model and respective ANOVA table but I get distinct results for the T-test (in summary(lm.object) function) and the F-test (in anova(lm.object) ) shouldn't this two approach give me the same result, i.e to indicate the same significants terms in both tests??????? obs. The system has two restrictions: 1) sum( x_i ) = 1 2) sum(

Dear R-tisans, I am trying to calculate the 12th root of a transition (square) matrix, but can't seem to obtain an accurate result. I realize that this post is laced with intimations of quantitative finance, but the question is both R-related and broadly mathematical. That said, I'm happy to post this to R-SIG-Finance if I've erred in posting this to the general list. I've

Hi List, I have to compare a relationship between y and x for two locations. I found logistic regression fits both datasets well, but I am not sure how to test if relationships for both sites are significantly different. I searched the r site, however no answers exactly match the question. I used Tukey's HSD to compare two means, but the relationship in my study was not simply linear. So I

Have you seen how these sub-one-cent companies take off on Good News? For the past two months, every one we have brought you has shown Amazing Appreciation. At such a low price even the smallest Gain means a Significant Percentage Return. We called (P)(P)(T)(L) as one to watch on Friday because of a Highly Anticipated Report from the Field. It moved up 13% on Friday and the news

Hi, I am new to model selection by coefficient shrinkage method such as lasso. And I became particularly interested in variable selection in Cox regression by lasso. I became aware of the coxpath() in R package glmpath does lasso on Cox model. I have tried the sample script on the help page of coxpath(), but I have difficult time understanding the output. Therefore, I would greatly appreciate if

Have you seen how these sub-one-cent companies take off on Good News? For the past two months, every one we have brought you has shown Amazing Appreciation. At such a low price even the smallest Gain means a Significant Percentage Return. We called (P)(P)(T)(L) as one to watch on Friday because of a Highly Anticipated Report from the Field. It moved up 13% on Friday and the news