similar to: How to pass objects from local() to GlobalEnv

Hi I want to simplify my problem into a prototype, how to write a function to get all the object in your current environment, e.g. .GlobalEnv, and print their mode? For example, if I have object a,b,c... in my environment, a=1;b='test';c=matrix(0,3,3)..... I want to write a function myfun(), when I run myfun(), this retrieve all the objects in my environment automatically and print

Hi, I have a table of x rows and y columns. The table is huge and so i'd like to create a subset of the data containing rows where any of the y values are below a threshold, say 1e-4. Is there a simple way of doing this in R? thanks Rich

Dear All, to produce output of several columns of a data frame, I tried to use lapply and also l_ply. In both cases, I would like to print a header line containing also the name of the respective column in the data frame. For example, I would like the following lapply(data.frame(a=1:3, b=2:4), function(x) print(deparse(substitute(x)))) to produce: [1] "a" [1] "b" and

Hi All, I might misunderstood how cut works. But following behaviour surprises me. vv <- seq(150, 346, by= 4) cc <- cut(vv, 12) cc[vv == 330] Results [1] (330,346] I would have expected 330 to fall into (313,330] category. Can you please advice what do I do wrong? Many Thanks, Jussi Lehto -------------- next part -------------- Visit our website at http://www.ubs.com This message

Dear Sir/Madam, I got some problem about using R. I am a student, and need to use R a lot. But sometimes when I am working in computer lab, we can not install some particular pacakges by ourselves because of the previliges. Can the folder of Librabry of R, move to, for instance the personal folder, my documents... then we can install any specified package? Best regards,

Is there a way to combine two columns within a data frame? Example data: id snp AL1 AL2 1500 30 A B 1510 30 A A 1520 30 A B This is what I would like: indv snp AL1AL2 1500 30 AB 1510 30 AA 1520 30 AB Any help is greatly appreciated. Alysta

I noticed that when I fit a linear model using 'lm' there is an attribute called "factors" that is added to the "term". It doesn't seem to appear for 'model.matrix', just 'lm'. I have been unable to find where it gets constructed or what it means? It looks like a two dimensional array that I may be able to use so I would just like to get some

Hallo All, I would like to apply a function to all permutations of variables in a dataframe (except the first). What is the best way to achieve this? I produce the permutations using: nvar <- ncol(dat) - 1 perms <- as.matrix( expand.grid(rep( list(1:0) , nvar ))[ , nvar:1] ) Thanks in advance Serguei Test-dataframe, comma-delimited: code,wav,w,area,gdp,def,pop,coast,milspend,agr

Hi, all, Does R have a "const object" concept like which is in C++ language? I want to set some data frames as constant to avoid being modified unintentionally. Thanks! xiagao1982 2011-03-15 [[alternative HTML version deleted]]

Hi guys, I have a list of 250 numbers as a result of using the ?by function! List of 246  $ 0   : num [1:28] 22 11 31...  $ 1   : num [1:15] 12 14 9 ... .. .. ..  - attr(*, "dim")= int 250  - attr(*, "dimnames")=List of 1 The problem is that each list of 250 has different length! I would like to get the values of each list in a vector like vector_0 = (22,11,31,..), is this

Hi R, I am trying to download the data from R. I give the below command. > library(fImport) > yahooSeries("IBM") trying URL 'http://chart.yahoo.com/table.csv?s=IBM&a=7&b=08&c=2007&d=7&e=07&f=2008& g=d&x=.csv' Error in download.file(url = url, destfile = file, method = method) : cannot open URL

Hi all, Just thought I'd post this (maybe) helpful tool I wrote. For people like me who are bad at keeping a clean environment, it's a time-saver. #simple command to get only one type of object in current environment lstype<-function(type='closure'){ inlist<-ls(.GlobalEnv) if (type=='function') type <-'closure'

Hi, I have two dataframes one with 144 rows and 160 columns (SDF1) and one with 12 rows and 160 columns (SDF2). Now I'm trying to divide rows 1:12 with SDF2, rows 13:24 with SDF2, rows 25:36 with SDF 2, . In S-Plus the following code works fine: DFS = SDF1[1:144,1:60] / as.vector(SDF2[1:12,1:160]) but in R when I try to implement the formula I get the following error: "/

Hi, Is there are function similar to excel vlookup in R. Please let me know. Thanks, Sachin ____________________________________________________________________________________ [[alternative HTML version deleted]]

I am trying to generate artificial data for feature selection. Basically trying to generate a total of 1000 features with 100 that are informative and rest are uninformative. Informative.data.class1<-rnorm(100,0.25,1) Uninformative.data.class1<-rnorm(900,0,1) Informative.data.class2<-rnorm(100, -0.25,1) Uninformative.data.class2<-rnorm(900,0,1) The above will give me one set of data

Dear all, do you know if there is any particular version of R to implement with windows 64 bit, in such a way to increase the amount of memory it can use? How should I increase the memory, and more importantly to set a higher max vector size? It still stops me saying "Could not allocate vector of size 145" thanks to all alessia

Greetings, I would like to flexibly combine several data frames objects without specifying the exact names of the objects in memory. Should I use indexing to call those objects out of memory? I regularly use indexes to flexibly extract parts of data frames and lists and to read files from my hard drive, but I can't figure out how to do so with stored objects. In my case, all of the data

Dear all, could you please advice whether it is possible somehow to modify an external (from the point of some function view) variable by some function-internal operators. For example > var=1 > foo<-function(var){var=var+1} > foo(var) > var [1] 1 but the goal is to get the var equal to 2 in this specific case. Thanks! -- View this message in context:

Dear R forum I have just started my venture with R. While I am trying to learn R through the tutorials, I think the current problem I need to address to is beyond my knowledge about R. I have a dataframe as defined below - rat_dat = data.frame(name = c("A", "A", "A", "B", "B", "B", "C", "C", "C",

#copy and paste this into R f <- (structure(list(TKN = c(0.103011025, 0.018633208, 0.104235702, 0.074537363, 0.138286096), RM = c(215, 198, 148, 119, 61)), .Names = c("TKN", "RM"), class = "data.frame", row.names = 25:29)) plot(f$TKN~f$RM, type="b") I would like to reverse the X-Axis. How do I do this? -- Let's not spend our time and resources