similar to: Matrix manipulation

Dear list, I'm trying to create a matrix by combining the sites that species occur in a new matrix with species as rows and sites as columns. The main matrix is "mat": mat <- as.data.frame(cbind(sp1=c(rep(0, 5), rep(1, 5)),sp2=sample(c(rep(0, 6),rep(1, 4))), fac=c(rep("a", 3), rep("b", 3),rep("c", 4)))) The first two columns are species and the

Hi all! I am currently writing a C-module for a for loop in which I permute columns in a matrix (bootstrapping) and I send a couple of variables into C initially. All of it is working, except the initial values I send to R are rounded/truncated (I believe rounded). I am using a 32 bit machine to compile, I am using (I believe) 32 bit R.... While debugging I print the values I am sending to C,

Hi, I have matrix of 104 columns and 30000 rows (Each Row has rowname). I have 13 different  list of selected rownames (character) say 1000 each. Now I want to extract the all the columns according to the rownames in each the list. How can I do that in R ? 1 ) For a single list 2) For all the 13 list at a time  Regards, Pankaj Barah Department of Biology,  Norwegian University of

Hi, I've a matrix that contains 4 replicates of each rowname. (4 a's, 4 b's, 4 c's in no particular order) Like this: # c 32 a 1 b 4 c 87 c 34 b 54 a 23 a 12 b 9 a 3 b 87 c 43 There are a couple of more columns but I'm using the above as an example I need to sort it so that the same rownames appear together in alpahbetical order. Like this: # a 1 a 23 a 12 a 3 b 4

Hi everybody. I have list like this: l<-list(data.frame(q1=c(1,2,"check"),q2=c(3,"check",5)), data.frame(q1=c("check",1),q2=c(4,5))) names(l)<-c("A","B") rownames(l[[1]])<-c("aa","bb","cc") rownames(l[[2]])<-c("aa","bb") Every object has the same number of columns but different number

Hello again, Let say I have 1 matrix: Mat <- matrix(1:12, 4, 3) rownames(Mat) <- letters[1:4] Now I want to subscript of Mat in following way: Subscript_Vec <- c("a", "e", "b", "c") However when I want to use this vector, I am geting following error: Mat[Subscript_Vec, ] Error: subscript out of bounds Basically I want to get my final matrix

Dear expeRts, What's the easiest way to convert an ftable object to a matrix such that the row names of the ftable object are shown in the first couple of columns of the matrix? This is (typically) required, for example, when the final goal is to print the matrix via xtable. Below is a rather complicated example of how to do it... Cheers, Marius ## Goal: convert an ftable() to a

Hi List, Here is some example data. myDat <- read.table(textConnection("group id 1 101 1 201 1 301 2 401 2 501 2 601 3 701 3 801 3 901"),header=TRUE) closeAllConnections() corr_mat <-read.table(textConnection("1 1 .5 0 0 0 0 0 0 0 2 .5 1 0 0 0 0 0 0 0 3 0 0 1.0 0 0 0 0 0 0 4 0 0 0 1 .5 .5 0 0 0 5 0 0 0 .5 1

Dear R Users, close to the end of this I used wireframe to create a 3D plot from a matrix. The x and y axis tick labels (1-6) for each were created from the matrix being a 6X6 matrix. I need the axis tick labels to be the row and column headings which you can see in the output (mat.x). I have tried several work arounds, but they have not been successful. Thanks in advance. keith rm(list=ls())

Hola! I have data in the form of a symmetric distance matrix, in the file I have recorded only the upper triangular part, with diagonal. The matrix is 21x21, and the file have row and col names, and some other information. I am trying to read with the following code (I tried many variations on it, but all give the same error). The items in the data file is delimited by white space. (Part

Does anyone know if there is an R function that will take a matrix like this jim 1 0 0 0 0 0 jim 0 1 0 0 0 0 jim 0 0 1 0 0 0 bob 1 0 0 0 0 0 bob 0 0 1 0 0 0 harry 0 0 1 0 0 0 harry 0 0 0 1 0 0 harry 0 0 0 0 1 0 harry 0 0 0 0 0 1 and make it like this? (that is, add together rows that have the same name?) jim 1 1 1 0 0 0 bob

Hola tengo una tabla de tipo data.frame "datos" con la siguiente estructura, simplificada en número de niveles por variable, para crear un ejemplo más sencillo: id anio t_8a t_10a t_12a rankf8 rankf10 rankf12 1 1 100 220 220 NA NA NA 2 1 140 350 350 NA NA NA 3 2 55 165 165 NA NA NA 4 2 60 200 200 NA NA NA 5 2 100 NA NA NA NA NA 6 3 NA 350 350 NA NA NA También tengo una matriz,

Hi, I am facing a problem with the legend, I don?t know how to use the fill option in the legend in order to achieve the same standard gray levels that are plotted. Sorry for this easy one, but I really did not find anything so far. It works fine with color: ###### C O L O R mat <- matrix(2,3,rep(2,6)) rownames(mat)<-c("A","B","C") par(xpd=T,

Dear list, I was curious how to subtract a vector from matrix? Say, I have mat <- matrix(1:40, nrow=20, ncol=2) x <-c(1,2) I want, x-mat[1,] and x-mat[2,], and so on... Basically, subtract column elements of x against column elements in mat. But x-mat won't do it. Thanks, Mike [[alternative HTML version deleted]]

Hi list, I've thus far not found a solution to my problem and hope someone can help. I have a data matrix and wish to plot a stacked bar plot using barplot(). This is simple enough, but I have a problem with the legend labels being in the reverse order from what I want. The default appears to have labels ascending bottom-to-top reflecting bottom-to-top sub-bars, but I would like the

Hi, I am trying to add duplicates of matrix "mat" by row. Commands subset(mat,duplicated(rownames(mat))) or mat[which(duplicated(rownames(mat))),] return only half of the required indices. How can I find the remaining ones, ie the matches, so that I can add them up? Thanks, Serguei ___________________________________________________________________ Austrian Institute of Economic

hello, i have been trying to convert my data frames to matrices in the hopes of speeding up some of my more complicated scripts. to assist with this, i am trying to create a "matrix column operator" like $: "%$%" = function(data,field) { as.numeric(data[,grep(field,unlist(dimnames(data)[2]))]) } the idea here is that you can use a matrix like a dataframe:

Greetings, My goal is to create a Markov transition matrix (probability of moving from one state to another) with the 'highest traffic' portion of the matrix occupying the top-left section. Consider the following sample: inputData <- c( c(5, 3, 1, 6, 7), c(9, 7, 3, 10, 11), c(1, 2, 3, 4, 5), c(2, 4, 6, 8, 10), c(9, 5, 2, 1, 1) ) MAT <- matrix(inputData,

There was a BioConductor thread today where the poster wanted to find pairwise difference between columns of a matrix. I suggested the slow solution below, hoping that someone might suggest a faster and/or more elegant solution, but no other response. I tried unsuccessfully with the apply() family. Searching the mailing list was not very fruitful either. The closest I got to was a cryptic chunk

Dear WizaRds, although this might be a trivial question to the community, I was unable to find anything solving my problem in the help files on CRAN. Please help. Suppose I have 4 variables and want to use all possible combinations: 1,2 1,3 1,4 2,3 2,4 3,4 for a further kmeans partitioning. I tried permutations() of package e1071, but this is not what I need. Thank you for your help and