Displaying 20 results from an estimated 2000 matches similar to: "help needed with histogram plotting"
2010 Nov 14
2
replace a row in a matrix
Dear all,
I created a n*2 matrix and I want to replace the ith row with a vector. Can
anyone suggest me what is the simple way to do it? Sorry for bothering you
with such simple question. I appreciate any hints or advice.
Thanks in advance.
Cassie
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2010 Nov 09
2
simulation from pareto distn
Dear all,
I am trying to simulate from truncated Pareto distribution. I know there is
a package called PtProcess for Pareto distribution...but it is not for
truncated one. Can anyone please help me with this?
Thanks in advance.
Cassie
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2011 Apr 08
4
Simulation from discrete uniform
Dear all,
I am trying to simulate from discrete uniform distribution. But I could not
find any in-built code in R. Could anyone help me please?
Thanks in advance for the time and help.
Cassie
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2012 Apr 10
1
how to convert seconds to 12 hour time format
Hello everyone,
I am wondering if there is any routine in R which can convert time given in
'seconds' unit to the 12 hour time format. For example, suppose the data
set looks like
x=c(36885,84000,20) #x in seconds
I want to get the output as
[1] " 11:14:45 AM"
[2] " 11:20:00 PM"
[3] "12:20:00 AM"
Does anyone have any idea? Thanks in advance.
Cassie
2010 Sep 29
1
executing loop
Dear All,
I am trying to define a loop for a m*n matrix, where i=1:n and j=1:m. Unlike
the usual for loop, i should go in the following way:
For j=1,
i=1,2,3,....n
For j=2,
i=n,n-1,n-2,......,1
For j=3,
i=1,2,3,.....n etc.
which means i should go in either increasing or decreasing order
alternatively.
Can anyone please help me in doing this?
Thanks,
Cassie
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2011 Feb 14
2
how to overlay a map of US on image plot
Dear all,
I have a data set which has latitude, longitude (not in increasing order)
and observed precipitation corresponding to those locations. I am using
image.plot command for that. But I want to overlay a map of US on that plot.
I know we can use map('usa') to draw it, but I dont know how can I overlay
it on the plot of the precipitation data. Can anyone please help me with it?
2011 Mar 08
1
defining an array with one of the elements being a vector
Dear all,
I am trying to define an array as follows:
a=array(NA,c(m,2,N,G)),
Even though the numbers N and G are fixed, m is a vector. So, I can't define
'a' as above.
For eg,
N=3
G=6,
but m=c(2,7,5) and length(m)=N.
Can anyone suggest me how can I define 'a' when m is a vector?
Thanks in advance for your help.
Cassie
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2010 Jul 29
2
Fry Plots
Does anyone know how to do a fry plot in R? I have 600-800 points per image, and I really don't want to attempt that manually.
Thank you!
Cassie
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2011 Jul 27
2
for loop help
I am having a hard time putting the below into a loop, where it pulls out ppt from all he stations I have versus having to go through and hard code the data to the specific stations. I tried
stnID <- stnid[which(duplicated(stnid)==FALSE)]
for(i in 1:length(stnID))
{
ppt[i] <- ppt[which(stnid==[i])]
}
but it doesn't like to use the which function inside a for loop? Any idea's here is
2011 May 16
1
simulation from truncated poisson
Dear all,
I need to simulate values from a Poisson distribution which is truncated at
certain value 'a'. Can anyone tell me if there is in-built package in R
which can simulate from a truncated Poisson? If not, what should be the
steps to write a function which would do that?
Thanks in advance.
Cassie
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2011 Jul 21
1
replacing duplicate rows
Hi all,
I have a matrix which looks like the following,
x=matrix(c(1,2,3,4,3,5,4,6,4,9),5,2,byrow=T)
Now, I want to replace the 2nd columns of those 4 rows which have duplicate
entries in the 1st column. For example, x[2,1]=x[3,1]=3 and I want to
replace x[3,2] by x[2,2]. Similarly, I want to replace x[5,2] with x[4,2],
which means that for duplicate entries in the 1st column, I want to replace
2012 Apr 26
2
problem with break command
Hello R-users,
I am having a problem with the 'break' command in R. I am wondering if
anyone can help me out with this. My program is similar to the following.
a=rep(NA,5)
a[1]=0
for(i in 2:5)
{
a[i]=a[i-1]+runif(1,0,3)
if(a[i]>5)
{
i=2
break
}
}
What exactly I am trying to do is find the sequence 'a' where the
individual values of 'a'
2013 Apr 10
1
problem with the image command
Hello R-users,
I am trying to do an image plot where I have been given latitudes,
longitudes and the values at the corresponding locations. A sample of the
data is given as follows:
values=c(0,1,0,0,0,0,2,2,0,0)
lat=c(29.6660,29.6756,29.3492,29.2654,29.2827,29.4070,35.3510,35.6590,35.7587,38.2794)
2011 Jun 17
1
issue with strptime
Hi everyone,
I have bunch of date and time observations in the format %Y-%m-%d %I %M %S
%p. I used strptime() to read this format. But the problem is some of the
times are in the format of %I %M %p, so for those times, strptime is giving
me NA values.
For example,
strptime(paste("2009-04-08","1:49:47 PM"),format="%Y-%m-%d %I:%M:%S %p")
[1] "2009-04-08
2012 Jan 31
1
about colnames
Hi,
when I run the below code,there is an error occured. could you please tell
me how to treat it?
> pdf('covariate.pdf')
> par(mfrow=c(1,1))
> pairs(data2[,c("ID","TYPE","AGE","GNDR","HT")],
+ panel=function(x,y) { points(x,y); lines(lowess(x,y))})
Error in `[.data.frame`(data2, , c("ID", "TYPE",
2010 Sep 09
1
executing loop in circular way
Dear all,
I am writing a program using for loop. The loop contains i which runs from
1:n. There is a feature I need to include here. That is, when i=n, i+1 would
be 1, not n+1. Basically the loop should run in a circular fashion. That
also means, if i=1, i-1=n.
Can anyone help me with this? How can I define it?
Thanks.
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2012 Jun 21
1
install package mixdist
Hi all,
I'm trying to install the mixdist package with:
install.packages("mixdist")
But I'm getting the following errors:
* installing *source* package ‘mixdist’ ...
** R
** data
** preparing package for lazy loading
** help
*** installing help indices
** building package indices ...
Warning in utils::data(list = f, package = package, lib.loc = lib.loc,
envir = dataEnv) :
2002 Sep 06
3
Histogram Ranking
Hello,
This is not exactly an R question, but I suspect that there is an R
procedure that does what I am calling (for lack of a better name)
"histogram ranking".
I'm trying to evaluate a set of regression features by segregating by
target class and comparing the feature histograms. My idea is that if the
histograms are the same for two different classes then there is no
2013 Jan 26
1
Attempting to confirm a program i wrote in C (normalize 2 datasets, transform into histogram, transform into CDF, perform KS test)
I have written a program in C that two xy datasets, aligns these 2 datasets
based on shared features, transforms them into equal sized histograms,
transforms the histograms into cumulative distribution functions (via GSL)
and finally performs a KS_test.
I am wanting to validate my program's results and figure'd i would use R but
i am kinda stuck at ithe histograms (I have 2 histogram
2003 Mar 08
1
How to store histogram plots
Hello all,
Is there any way to save histogram results to a file and then read it
back later? I am dealing with several sets of data that are too large to
be loaded in the same R process, but I want to plot their histogram side
by side for comparison. I am also considering how to use the ''wireframe''
function to plot these histograms in the same figure. Any suggestions
will be