Displaying 20 results from an estimated 2000 matches similar to: "modifynig some elements of a vector"
2010 Apr 29
1
randomness in stepclass (klaR) or lda (MASS) ?
Hi,
a colleague ran a stepwise discriminant analysis
twice in a row and got different results, suggesting
some "sochasticity" in the algorithms involved.
I looked at her data and found that there was a lot
of collinearity, so that I reckoned that maybe "stepclass"
(klaR) cannot find a clear winner when trying to include a
new variable and makes a random choice. Is that true?
2013 Dec 12
1
censored counts and glmer/glmmADMB
dear R-users,
I have to model counts where all counts above some threshold
have been censored. In the same dataset I have too many zeroes for
a Poisson or even a negative binomial distribution to make
sense, so I would need a zero-inflated-censored negative binomial
family for use in glmer (or glmmADMB?). That seems not to exist.
my question is :
how could I add a custom-built family of
2006 Sep 11
3
"unvector" ?
Hi ev'rybody,
is there a way to pass a vector to a function
expecting separate arguments?
more specifically, I have a character vector, say u
and I want a single string, but
>paste(u)
doesn't work, so I would like something like
>paste(unvector(u)).
I am interested in a solution to the general problem too,
as the only one I found is maintaining two versions of the
functions I
2007 Mar 28
2
what is the difference between survival analysis and (...)
Hi everybody,
recently I had to teach a course on Cox model, of which I am
not a specialist, to an audience of medical epidemiologists.
Not a good idea you might say.. anyway, someone in the
audience was very hostile. At some point, he sayed that
Cox model was useless, since all you have to do is count
who dies and who survives, divide by the sample sizes
and compute a relative risk, and if there
2012 Mar 18
1
call to system returns warning : status 2 (Ubuntu)
Hi everybody,
I have to run under Ubuntu a programs repeatedly
with different arguments and I am using R just to
generate the data files and call the external program.
basically, in my script I have inside a loop these two lines:
command <- paste(<some constant or variable strings>,sep="")
system(command,intern=T,wait=T)
when I run this script, I get a number of warnings,
2011 Jul 20
2
bar chart issue
Hi everyone,
I determined the presence of three types parasites in a passerine bird
over two years. I would like to create a bar chart that shows the
proportion infected on the y and year/parasite on the x such that each
type of parasite is grouped together (single label) and a bar for each
year . This would show if there have been changes in the prevalence of
a the parasite over two years.
2016 Dec 02
2
pdftools on Ubuntu
Hi,
I am trying to install pdftools package on R 3.3.1 (Ubuntu 16.04), but the
following issue occurs:
------------------------- ANTICONF ERROR ---------------------------
Configuration failed because poppler-cpp was not found. Try installing:
* deb: libpoppler-cpp-dev (Debian, Ubuntu, etc)
* rpm: poppler-cpp-devel (Fedora, CentOS, RHEL)
* csw: poppler_dev (Solaris)
* brew: poppler (Mac OSX)
2016 Dec 02
1
pdftools on Ubuntu
Hi Francois,
Thanks for your quick response.
Actually, I had already done that...
sudo apt-get install libpoppler-cpp-dev
Reading package lists... Done
Building dependency tree
Reading state information... Done
libpoppler-cpp-dev is already the newest version (0.41.0-0ubuntu1.1).
0 upgraded, 0 newly installed, 0 to remove and 107 not upgraded.
Therefore, I assume I have this installed.
Best
2009 Apr 27
2
refit with binomial model (lme4)
Dear R users,
I'm trying to use function 'refit' from lme4
and I get this error that I can't understand:
> refit(dolo4.model4,cbind(uu,50-uu))
Error in function (classes, fdef, mtable) :
unable to find an inherited method for function "refit", for signature
"mer", "matrix"
if I try:
> refit(dolo4.model4,uu)
Error in asMethod(object) :
2007 Dec 19
1
FW: cgh package
Hi,
I would like some extra information on the 'cgh' package in R. I noticed
that there isn't much activity regarding this package on the R and BioC
mailing list (I googled it).
I started using this package and I have few questions:
1/ As I have a custom tiling like array @8um features resolution (affy),
I have a lot of probes to work with. I'm assuming it is correct to
2020 Sep 25
6
Question regarding cent OS 7.8.2003 compatibility with large SAS disks
Hello,
I have a blade server with SAS HDD's of 12TB in total.
3 HDD's of 4TB each.
Is it possible to install Cent OS 7.8.2003 on 12TB disk space?
I will be installing Cent OS on the bare metal HW.
I referred = https://wiki.centos.org/About/Product
But slightly confused with the 'maximum file size' row for ext4 FS.
Thanks & Regards,
Amey.
2013 Jan 26
2
different legends in lattice panels
Hi listers,
I want to make lattice plots xyplots with the indication of legends
inside each panel with only the points and the lines actually ploted
inside each given panel according to the group(ing) factor.
The code below shows what I have achieved so far and I hope will make
clear what I want to have.
It seems to me that my solution is a very "dirty hack" and there
certainly is
2005 Jul 27
1
how to get actual value from predict in nnet?
Dear All,
After followed the help of nnet, I could get the networks trained and, excitedly, get the prediction for other samples. It is a two classes data set, I used "N" and "P" to label the two. My question is, how do I get the predicted numerical value for each sample? Not just give me the label(either "N" or "P")? Thanks!
FYI: The nnet example I
2006 Oct 23
2
character manipulation
Dear R'helpers,
I am reading lines in a .txt file
Each line is stocked into a n elements object, as this:
[958] " 422 287 339 31 203 602 547 1026 500 366 346 227"
[959] " 410 67 11 220 110 451 562 598 732 163 163 220"
[960] " 179 513 95 186 102 595 333 1289 804 210 294 459"
[961] " 276 153 307 138 126 233 623 739 521 421 209 75"
[962] " 64
2003 Feb 13
3
search contrasts tutorial
I'm looking for a tutorial or notes on the use of contrasts factor in
linear model in R,
I've found some mails and infos about in various documents about R,
but I've probably missed
a good review on this subject.
--
Robert Espesser
Laboratoire Parole et Langage UMR 6057, CNRS
29 Av. Robert Schuman 13621 AIX (FRANCE)
Tel: +33 (0)4 42 95 36 26 Fax: +33 (0)4 42 59 50
2011 Jun 16
1
problem with missing package
Hi everybody,
I just tried to run R on one of my projects
but it did not want to run:
R version 2.12.1 (2010-12-16)
Copyright (C) 2010 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
Platform: x86_64-pc-linux-gnu (64-bit)
<some lines deleted>
Loading required package: utils
Error in loadNamespace(i[[1L]], c(lib.loc, .libPaths())) :
there is no package called
2010 Mar 10
1
Extract values of a two-factor table and duplicate them into a three-factor table
Dear all,
I would like to solve a trivial problem (I guess it is) but can't find the right way. Maybe someone can help me ?
I've got a table with two factors (station = station ID, buffer = buffer size in meters) and a value for each unique combination of those two factors (S = number of habitats within each buffer around each station) like this:
TABLE 1
station buffer S
Abaia01 200 2
2010 Oct 18
1
Error: subscript out of bounds
Dear All
I have problem with this:
> IWJR.temp <-IWJR.missing[sample(1:length(IWJR.missing),1),]
Error: subscript out of bounds
How I can solved this.
Thanks
IRD
2020 Jul 23
5
Off Topic bash question
I have a simple script:
#!/bin/bash
#
index=0
total=0
names=()
ip=()
while read -r LINE
do
NODENAME=` echo $LINE | cut -f 1 -d ','`
IP=` echo $LINE | cut -f 2 -d ','`
names[index]="$NODENAME"
ip[index]="$IP"
index=`expr index+1`
total=`expr total+1`
done <<< $(cat list.txt)
simple file:
more list.txt
name1,ip1
name2,ip2
name3,ip3
output when
2007 Feb 16
2
if() for() { }
Dear R'helpers,
I guess the solution is trivial but despite some hours of testing and
looking at the doc, I was unable to fix the following problem.
I want to do either:
for (i in 1:lat) a[i,which(a[i,]==0] <- NA
or:
for (i in 1:lat) a[i,which(a[i,]==-9999|a[i,]==9999|a[i,]==9998|a[i,]
==-9998)] <- NA
if the word "Time" is or is not present in variable