similar to: Problem with long number (from character to numeric class)

Hello, I convinced our new Ph student to work with R and I managed to convince the guy in charge of the computer networks to install R 2.12.0 (we haven't the admin rights). I wanted to install on his computer the same packages I use (but I have R 2.11) and especially RMySQL. Problem : there is no more RMySQL package in the list pf the packages. I've tried to install my version but it is

Hello, I discovered R two years ago and thanks to the R-community I managed to write some scripts to analyze my data stored in mysql databases. The only problem is that I am the only one using R in the lab. Colleagues mainly use Matlab (but not with mysql, only with text files) but regularly come to me to get data treated with R-scripts !!!. To allow the use of my scripts by other people, my

I'm plotting a lattice bwplot from a data.frame and would like to add some horizontal lines indicating some reference values (preferably with text annotation) as well as a grid of regular log tics. The following illustrates the plot: data(ToothGrowth) require("lattice") p = bwplot(exp(len) ~ supp, ToothGrowth, panel = function(..., box.ratio) { panel.grid(h=-1,

Hello, I would like to replace a for loop with lapply in order to speed up the treatment of my data (I've read lapply can help to do it). At the end of the message, you will find a simple example (function is more complex and data frames is more than 1 million of rows) of what I would like to do, that is applying the same calculation to all the rows of the data frame (knowing that I cannot

Hello, I've two data.frames (data1 and data4), dec="." and sep=";". http://r.789695.n4.nabble.com/file/n4199964/data1.txt data1.txt http://r.789695.n4.nabble.com/file/n4199964/data4.txt data4.txt When I do plot(data1$nx,data1$ny, col="red") points(data4$nx,data4$ny, col="blue") , results seem very similar (at least to me) but the R-squared of

Hello, I'm trying to fit experimental data with a model and nls. For some experiments, I have data with x from 0 to 1.2 and the fit is quite good. But it can happen that I have data only the [0,0.8] range (see the example below) and, then, the fit is not correct. I would like to add a constraint, for example : the second derivative must be positive. But I don't know how to add this to

Hello, I'm still trying to make the life of my colleagues easier. Nice, isn't it ? At the moment, I'm looking for a way to generate multiple "single report". In fact I have a .rnw file which send a query to a MySQL database (rs<-dbSendQuery(con, statement="select * from treatdata where name='Device1'") But of course my colleagues have many devices and

Hello, In one of my functions, I need to extract the hour from a date. For example: as.POSIXlt("2010-03-27 02:00:00")$hour gives 2 as expected. It works for all the dates I've tested except the following one which is in my list of dates: as.POSIXlt("2010-03-28 02:00:00")$hour which gives 0. I don't understand why it doesn't work with this particular date. Any

Hi, I have a data frame of 2 columns with the following types : data$day char data$value num And I plot my data with : plot(strptime(donnees$day,format="%Y-%m-%d %H:%M:%S"),donnees$value, type="l") And I'd just like to get the numerical value of the integration of this graph. I looked at ?integrate but, as far as I understood (that is, not very much, due to my poor

Hello, I would like to know if it exists a package including something equivalent to this page: http://www.developpez.net/forums/d740403/autres-langages/algorithmes/contribuez/image-geometrie-projective-homography/ http://www.developpez.net/forums/d740403/autres-langages/algorithmes/contribuez/image-geometrie-projective-homography/ I've searched with these keywords: R-project homography

Hello, I'm just looking for an easy way to find the positions of a complete sequence in a bigger vector. For example : c("a","z","e") in c("a","z","e","r","t","a","z","a","z","e","c") and the result should be 1 8 that is the positions of the beginning of

Thanks to your help, I managed to link R and a Mysql Database, send queries, plot the results and put everything in a pdf document (with Sweave). My co-workers find the job not bad but they would like to have a friendly interface to send queries and see the graphs (the pdf document is not necessary). Something like this coul be a good starting point : --------------------------------------- |

Hi, I have a vector called nfichiers of 138 names of file whose extension is .P0 or P1 ... to P8. The script is not the same when the extension is P0 or P(1 to 8). Examples of file names : [128] "Output0.P0" [129] "Output0.P1" [130] "Output0.P2" [131] "Output01102007.P0" [132] "Output01102007.P1" [133]

Hello, When I plot y=f(x) from the file xy.txt ( http://www.nabble.com/file/p18773387/xy.txt xy.txt ), I can clearly see a trend. Is there a function or a package able to take the median value of y for an interval of x (x +/- a defined value) to plot nice graph (at least a better one) ? Thanks in advance, Have a nice week-end, Ptit Bleu. -- View this message in context:

Hello, I'm looking for a R-package to solve such an equation : http://n4.nabble.com/file/n1590462/iv.png which is one current-voltage equation of a solar cell. Thanks in advance, Ptit Bleu. -- View this message in context: http://n4.nabble.com/looking-for-a-package-to-solve-current-voltage-equation-I-f-I-tp1590462p1590462.html Sent from the R help mailing list archive at Nabble.com.

Hello, I would like to plot the following xyplot : for each date of fff (1 date per panel), bbb=f(aaa) for the two groups (ddd=1 and ddd=2) superimposed. I can do it by group (see below) but not together. I looked at http://lmdvr.r-forge.r-project.org/figures/figures.html but I haven't found what I was looking for (to be honest, I haven't understood all the examples). Any help will be

Hi, I read the posts for 2 hours and ?list and tried many comninations but I haven't found the answer to this basic question. So I decided to post my question even if it is a silly one ... What is the instruction to retrieve, for example, the "D" of the first list ? Thanks in advance, Ptit Bleu. > x<-list(LETTERS[1:5], LETTERS[10:20]) > x [[1]] [1] "A"

Hello, I'm trying to fit some points with a 8-degrees polynom (result of lm is stored in pfit). In most of the case, it is ok but for some others, some coefficients are "NA". I don't really understand the meaning of these "NA". And the problem is that I can't perform a derivation (pderiv<-as.function((deriv(polynomial(pfit$coefficients))))) on pfit due to the

Hello, I would like to fit data with the following formula : y=V*(1+alpha*(x-25)) where y and x are my data, V is a constant and alpha is the slope I'm looking for. How to translate this into R-language ? At the moment, I only know : lm(y ~ x) Sorry for such a basic question. I thought I could find the solution in a post but I have to confess that, up to know, I'm not able to understand

Hello, I have 3 columns : a, b and a*b I would like to find the pair (a,b) so that a*b is the minimum but not from the points I measured but from the fit of the curve (I have more points that the ones given below but I fit only on this part because I know that the minimum a*b is in this interval). I thought doing it this way : - to fit a*b=f(a) abfit<-lm(ab ~ poly(a,8,raw=T)) - to use the