similar to: Quadratic regression: estimating the maximizing value

Good morning to you all, Sorry for taking your time from your research and teaching schedules.   If you have a non-stationary univariate time Series data that has the transformation: Say; l.dat<-log (series) d.ldat<-diff (l.dat, differences=1) and you fit say arima model. predit.arima<-predict (fit.series, n.ahead=10, xregnew= (n+1) :( n+10)) How could I re-transform

Dear Uwe, (When replying to your message, I sent the reply to r-devel and not r-package-devel, as Martin Meachler suggested that this thread would be a better fit for r-devel.) Thanks. In the example below I used rm() explicitly, but in general users wouldn't do that. One of the reasons for the large number of file handles is that sometimes unnamed temporary objects are created. For

Fellow R users, I'm using the BCE {BCE} function to run a Bayesian sediment mixing model. The aim is to find the optimum % contribution from each of the 4 source areas that can yield the target geochemistry. I have geochemistry for 4 source areas called Rat: Rat<-read.table(text="CaO MgO Na2O Al2O3 Topsoils 2.511250 0.7445500 0.7085500 14.10375 ChannelBanks

Hello All, I have a couple of stacked histograms which I need to compare/evaluate for similarity or difference. http://r.789695.n4.nabble.com/file/n4635668/Selection_011.png I believe rather than evaluating histograms is will be east to work with dataset used to plot these stacked histograms, which is in format: RED PURPLE BLUE GREY

Dear R users, Based on a set of binomial sample data, how would you utilize the "nlm" function in R to estimate the true proportion of the population? Thanks. Debbie _________________________________________________________________ [[elided Hotmail spam]] [[alternative HTML version deleted]]

Hello dovecot, First poster here. What I want : give a.chaouche at algerian-radio.dz list and read permissions on a.chaouche at backup.algerian-radio.dz. Let's just discuss sharing the inbox then I can do the same for subfolders, in any. a.chaouche at algerian-radio.dz and a.chaouche at backup.algerian-radio.dz are two different users. Details about the domains aren't relevant here I

Hi Martin, When I attended the LinuxWorld Expo in NYC back in January, I chatted with some folks at the AMD booth, as well as guys from Penguin Computing (where we bought our Opteron box). I was told that the Operton has this somewhat strange setup that the memory is controlled by one CPU. The net effect of this being that when both CPUs are running, one might only be running at around 90%

Dear All,I encountered a problem when I use RWeka for prediction. Specifically, I use the following: res=J48(X1~.,data=mydata); predict(res), #it worked fine but when I tried to use a different data set, i.e. predict(res,newdata=mynewdata); all the predictions I get is 0, which apparently is problematic. What is weird is, if I use the old data, but use the newdata option, i.e.

Hi everyone, Some of you probably received the following thread from the Rcpp-devel mailing list: http://lists.r-forge.r-project.org/pipermail/rcpp-devel/2018-August/010072.html Summing up, the issue described is the following: pkg1 provides type1 in pkg1.so building on some headers. pkg2 links to pkg1 (BTW, LinkingTo is actually misleading, because it doesn't really link to it), i.e.,

Dear R-list, i have a problem, in the framework of simulations, i want to vectorize for earning time: a variable, say X, has values on intervals and an other variable, say Y, has values on other intervals. For example Inf Sup X 0 2 1 2 4 2 4 6 3 and Inf Sup Y 1 3 1 3 5 2 5 7 3 i want to create a matrix like this Inf Sup

Hi all, My problem is as follows: I want to run a loop which calculates two values and stores them in vectors r and rv, respectively. They're calculated from some vector x with length a multiple of 7. x <- c(1:2058) I need to difference the values but it would be incorrect to difference it all in x, it has to be broken up first. I've tried the following: r <- c(1:294)*0 rv

Decodes mouse event packet dz value and passes it as a wheel event into the input stream. Please apply to linux-2.6.18-xen Signed- off- by: Pat Campbell <plc@novell.com> _______________________________________________ Xen-devel mailing list Xen-devel@lists.xensource.com http://lists.xensource.com/xen-devel

Suppose I have a 4-D array X with dimensions (dx, dy, dz, dp). I want to collapse the first 3 dimensions of X to make a 2-D array Y with dimensions (dx*dy*dz, dp). Instead of awkward looping, what is a good way to do this? Is there a similar function like reshape in Matlab? Thanks, Gang

:-) On 3/17/19 10:22 AM, Yassine Chaouche via dovecot wrote: > > On 3/16/19 3:49 PM, Marek Kozlowski via dovecot wrote: >> Can I test local mail delivery by dovecot LMTP manually? I mean: to >> simulate "I'm the Postfix" and produce for some testing e-mail the >> same effect as postfix granting it via `local_transport' to dovecot? >> > You can

Dear Luke, Thanks. See below On 07-08-18 17:07, luke-tierney at uiowa.edu wrote: > In R 3.5 and later you should not need to gc() -- that should happen > automatically within the connections code. Could you elaborate on what has changed in R 3.5? As far as I can tell my problem also occurs in R 3.5 (my computer is still on 3.4.4; but I assume the solaris CRAN machine isn't). And

I'm trying to read a binary file created by a fortran code using readBin and readChar. Everything reads fine (integers and strings) except for double precision numbers, they are read as huge or very small number (1E-250,...). I tried various endianness, swap, But nothing has worked so far. I also tried on R 64 bit for linux and windows (R 2.14) and R 2.11 on windows XP 32 bit. Any help would

Hi, I have 2 questions on list object:   1. Suppose I have a matrix like: dat <- matrix(1:9,3)   Now I want to replicate this entire matrix 3 times and put entire result in a list object. Means, if "res" is the resulting list then I should have:   res[[1]]=dat, res[[2]]=dat, res[[3]]=dat   How can I do that in the easilest manner?   2. Suppose I have 2 list objects: list1 <- list2

I cannot figure out how, using R, I can paste indexes or characters to the variable names which are used within loops. I will explain this with a simple example: Immagine I have a huge series of variables, each one taken two times, say x1 x2 y1 y2 z1 z2..... Now, immagine that I want to compute a variable from the difference of each couple, say dx=x1-x2, dy=y1-y2, dz=z1-z2... In Stata, for

>>>>> Joshua Ulrich <josh.m.ulrich at gmail.com> >>>>> on Tue, 6 Dec 2016 09:51:16 -0600 writes: > On Tue, Dec 6, 2016 at 6:37 AM, <frederik at ofb.net> wrote: >> Hi all, >> >> I ran into a segfault while playing with dates. >> >> $ R --no-init-file >> ... >> >

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