similar to: R string help

I'm new to R and very excited about its possibilities. But I'm struggling with some very simple things, probably because I haven't found the correct documentation. Here's a simple example which illustrates several of my problems. Suppose I want to have a regexp match against a string, and return all the matching substrings in a vector of strings. regexp <-

Hi, I am working with a dataset for sometime and I need some help in parsing some data. There is a column called "Duration" which has data like following: 2 minutes => 120 2 min => 120 10 seconds =>10 2 hrs =>7200 2-3 minutes => 150 or 120 5 minutes (when i arrived => 300 Flyby approx 20 sec. => 20 felt like 10 mins but tim => 600 I need to convert them to

> grep("f[0-9]+=", "f1=5,f22=3,", value = T) [1] "f1=5,f22=3," How do I make the line output c("f1", "f22") instead? (Actually, c(1,22) would be even better). Thank you. -- View this message in context: http://r.789695.n4.nabble.com/Quick-GREP-challenge-tp2339486p2339486.html Sent from the R help mailing list archive at Nabble.com.

Please consider following string: MyString <- "ABCFR34564IJVEOJC3434" Here you see that, there are 4 groups in above string. 1st and 3rd groups are for english letters and 2nd and 4th for numeric. Given a string, how can I separate out those 4 groups? Thanks for your time [[alternative HTML version deleted]]

Hi, I'm not being able to capture a position of a 'string' in a character string. In this example: 'There are 20 species in this grid' I would like to capture the string (number) after 'are' and before 'species'. Consider they do not change. I wouldn't like to use substr because stop position may change. Thanks Paulo

Hello, Newbie question: how do you capture groups in a regexp in R? Let's say I have txt="blah blah start=20080101 end=20090224". I'd like to get the two dates start and end. In Perl, one would say: my ($start,$end) = ($txt =~ /start=(\d{8}).*end=(\d{8})/); I've tried: txt <- "blah blah start=20080101 end=20090224" m <-

I have a string such as fileName<-"Agg.20.20.20-all-01". All I want to do is pull the "20.20.20" and the "all" as strings. Obviously, they aren't always those values. The "20.20.20" can be "30.30.30" but it's always after the . which is next to the second g in Agg and it's always the same length. The all might not always be

Greetings, I have a vector of values that are a word followed by a number, e.g., x = c("Apple12","HP42","Dell91"). The goal is to split this vector into two vectors such that the first vector contains just the words and the second contains just the numbers. I cannot use strsplit (or at least I do not know how) as there is no obvious separator. I can use sub to

Dear R user How to make the program stop at the spot where the error occurs? I mean inside the iterations,. Many thanks yan ********************************************************************** This email and any files transmitted with it are confide...{{dropped:10}}

Hello, I have a dataframe (tab separated file) which looks like the example below - two values separated by a comma, and tab separation between each of these. [,1] [,2] [,3] [ ,4] [1,] 0,1 1,3 40,10 0,0 [2,] 20,5 4,2 10,40 10,0 [3,] 0,11 1,2 120,10 0,0 I would like to calculate the percentage of the smallest number separated by the comma by: 1) summing the values e.g. for

Dear all, I would like to ask you if R has a library that can work with different GPS formats For example  I have a string of this format N50° 47.513 E006° 03.985 and I would like to convert to GPS decimal format. that means for example converting the part N50° 47.513 to 50 + 47/60 + 513/3600. Is it possible to do that with R? What is the name of such a library? I would like to thank you in

Hi All, I have a character vector with naems of cities in the us. I need to extract the number that appear after the word "New York", for example, x<-c("P Los Angeles44AZ", "P New York722AZ", "K New York20") I want the results to be 722, 20 cab I use the grep function, if so how? I appreciate your help, thanks, -- View this message in context:

hi, is there an easy way to extract numbers from a string? for example I have; "this Item costs 3.32 Dollars" is there an easy way to extract the 3.32 as a number? thanks!

Dear R People: Here is a toy example: > x <- c("2E","5W","12H") > substr(x,2,2) [1] "E" "W" "2" > Sometimes x has 3 elements, sometimes 2. I want to extract the last element, and then extract the other 1 or 2 elements. How can I do this, please? TIA, Sincerely, Erin -- Erin Hodgess Associate Professor Department of

Hi, this should be an easy one, but I can't figure it out. I have a vector of tests, with their units between brackets (if they have units). eg tests <- c("pH", "Assay (%)", "Impurity A(%)", "content (mg/ml)") Now I would like to hava a function where I use a test as input, and which returns the units like: f <- function (x) sub("\\)",

Hi there I have a string like this i want to extract 9831019 from this string i used a regular expresion \d+ by which i can only make it to see 7 and returns. This type of number(9831019) appears in any part of the string and is definitely more than 5 digits all the time and i want to give that as a condition UV7C11-F9-E1 MCS#9831019 MCS Lot #9512516" how do i go abt it Ramya -- View

I'm having a Thursday morning mental block, any suggestions on the following would be most appreciated... I have (as an example) surgery = c("d48", "d67", "dnc37", "a75", "d10", "a78", "d31", "d55", "d1") before each number part the possibilities are c("a", "d",

Given a text like I want to be able to extract a matched regular expression from a piece of text. this apparently works, but is pretty ugly # some html test<-"</tr><tr><th>88958</th><th>Abcdsef</th><th>67.8S</th><th>68.9\nW</th><th>26m</th>" # a pattern to extract 5 digits > pattern<-"[0-9]{5}" #

Dear R Users, if I have a string as follows x<-"jsda23tth" How can I extract out 23 as a numeral? I found substr(x,5,6) but, this doesnt work if the number of alphabets differ. This is another example where the numbers need to be extracted. x<-c("jsda23tth","fgd54fgd","j3ngh","gfdjh564") any ideas? This didnt work.

Hi, I am trying to do some calculations turning DMS data to decimal degrees using the formula (D+(M/60)+(S/3600)), some of the D's involve -ve numbers, the easiest way to do the calculation is to use absolute numbers then use the 'sign' function in R to change the answer back to the correct -ve or +ve, for example, if; D<--69 M<-8 S<-10 then decimal<-D+(M/60)+(S/3600)