similar to: How to Plot Two Curves Into One Page

Hello all, I upgraded my R workstation, and to my dismay, only one core appears to be used during intensive computation of a bioconductor function. What I have now is two dual-core Xeon 5160 CPUs and 10 GB RAM. When I fully load it, top reports about 25% user, 75% idle and 0.98 short-term load. The archives gave nothing helpful besides mention of snow. I thought of posting to HPC, but this system

Dear All I want to store matrix in an array Suppose s<-array(0,4) for(i in 1:4) s[i] <- read_matrix(a,2,2) But the error - number of items to replace is not a multiple of replacement length. Can you suggest me any alternative method for storing a matrix in an array. Thanks In advance. Kind Regards Wesley C Mathew [[alternative HTML version deleted]]

Hi, I want 12 ticks at axis 1 and want to write Jan-Dec on each. something like: axis(1, at=1:12, labels=c('J','F','M','A','M','J','J','A','S','O','N','D')) I could omit default ticks but now how to control ticks. plot(file$time, file$ch4*1000, ylim=c(1500,1700), xaxt='n', xlab= NA,

Hi, I have been working with Program R for my stats class and I keep coming upon the same error, I have read so many sites about inputting data from a text file into R and I'm using the data to do a correspondence analysis. I feel like I have read everything and it is still not explaining why the error message keeps coming up, I have used the exact examples I have seen in articles and the

Hi all, Suppose I have 2 matrices A and B. And I want to measure how good each of this matrix is. So I intend to compare A and B with another "gold standard" matrix X. Meaning the more similar a matrix to X the better it is. What is the common way in R to measure matrix similarity (ie. A vs X, and B vs X) ? - Gundala Viswanath Jakarta - Indonesia

Dear all, I tried to find index in repo given a query with this: > repo <- c("AAA", "AAT", "AAC", "AAG", "ATA", "ATT") > qr <- c("AAC", "ATT", "ATT") > which(repo%in%qr) [1] 3 6 Note that the query contain repeating elements, yet the output of which only returns unique. How can I make it

Hi, I have the following vector which is created from 3 distinct distribution (three components) of gamma: x=c(rgamma(30,shape=.2,scale=14),rgamma(30,shape=12,scale=10),rgamma(30,shape=5,scale=6)) I want to plot the density curve of X, in a way that it shows a distinct 3 curves that represent each component. How can I do that? I tried this but doesn't work: lines(density(x)) Please

Dear all, I have the following matrix. > dat A A A A A A A A A A [1,] 0 0 0 0 0 0 0 0 0 0 [2,] 0 0 0 0 0 0 0 0 0 1 [3,] 0 0 0 0 0 0 0 0 0 2 How can I change it into: [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [1,] 0 0 0 0 0 0 0 0 0 0 [2,] 0 0 0 0 0 0 0 0 0 1

Hi, I have the following (M x N) matrix, where M = 10 and N =2 What I intend to do is to group index of (M) based on this condition of "x_mn" , namely For each M, If x_m1 > x_m2, assign index of M to Group1 otherwise assign index of M into Group 2 > x [,1] [,2] [1,] 4.482909e-01 0.55170907 [2,] 9.479594e-01 0.05204063 [3,] 8.923553e-01 0.10764474

Dear all, Suppose I have this data frame: > data_main V1 V2 foo 13.1 bar 12.0 qux 10.4 cho 20.33 pox 8.21 And I want to split the data into two parts first part are the one contain in the source array: > src [1] "bar" "pox" and the other one the complement. In the end we hope to get this two dataframes: > data_child1 V1 V2 bar 13.1 pox

Hi, How can I extract the label only from a given data frame. Fore example from this data frame. > print(dataf) V1 V2 V3 V4 V5 V6 V7 V8 V9 11145 14.3 17.1 31.2 41.7 45.8 49.8 68.6 70.6 72.9 3545 10.2 15.6 20.9 23.2 31.4 31.7 36.2 48.4 51.9 8951 15.2 17.5 20.0 21.4 32.4

Hi, I have the following data that looks like this: > names(dat) [1] "(-2329,-2319]" "(-1399,-1389]" "(-669.4,-659.4]" How can I modify those names into just this? [1] -2329 -1399 -669.4 - Gundala Viswanath Jakarta - Indonesia

Hi Dieter, Sorry my mistake. I wanted to convert them into Decimal (not Hexadecimal). Given this string, the desired answer follows: > ascii_str <- "ORQ>IK" 79 82 81 62 73 75 > ascii_str2 <- "FDC" 70 68 67 - Gundala Viswanath Jakarta - Indonesia On Mon, Dec 22, 2008 at 5:49 PM, Dieter Menne <dieter.menne at menne-biomed.de> wrote: > Gundala

Hi all, Given a matrix: > mat [,1] [,2] [,3] [1,] 0 0 0 [2,] 3 3 3 [3,] 1 1 1 [4,] 2 1 1 How can I convert it to a list of strings: > desired_output [1] "aaa" "ttt" "ccc" "gcc" In principle: 1. Number of Column in matrix = length of string (= 3) 2. Number of Row in matrix = length of vector ( = 4). 3.

Hi, Suppose I have these two matrices (could be more). What I need to do is to store these matrices into a hash. So that I can call back any of the matrix back later. Is there a way to do it? > mat_1 [,1] [,2] [1,] 9.327924e-01 0.067207616 [2,] 9.869321e-01 0.013067929 [3,] 9.892814e-01 0.010718579 [4,] 9.931603e-01 0.006839735 [5,] 9.149056e-01 0.085094444

On 2017-11-16 17:53, Thomas Gleixner wrote: > On Thu, 16 Nov 2017, Quan Xu wrote: >> On 2017-11-16 06:03, Thomas Gleixner wrote: >> --- a/drivers/cpuidle/cpuidle.c >> +++ b/drivers/cpuidle/cpuidle.c >> @@ -210,6 +210,13 @@ int cpuidle_enter_state(struct cpuidle_device *dev, >> struct cpuidle_driver *drv, >> ??????????????? target_state =

On 2017-11-16 17:53, Thomas Gleixner wrote: > On Thu, 16 Nov 2017, Quan Xu wrote: >> On 2017-11-16 06:03, Thomas Gleixner wrote: >> --- a/drivers/cpuidle/cpuidle.c >> +++ b/drivers/cpuidle/cpuidle.c >> @@ -210,6 +210,13 @@ int cpuidle_enter_state(struct cpuidle_device *dev, >> struct cpuidle_driver *drv, >> ??????????????? target_state =

Dear all, The basename() function returns the extension also: > myfile <- "path1/path2/myoutput.txt" > basename(myfile) [1] "myoutput.txt" Is there any other function where it just returns plain base: "myoutput" i.e. without 'txt' - Gundala Viswanath Jakarta - Indonesia

Dear all, Does R has any function/package that can pack and unpack string into bit size? The reason I want to do this in R is that R has much more native statistical function than Perl. Yet the data I need to process is so large that it required me to compress it into smaller unit -> process it -> finally recover them back again into string with new information. In Perl the

Hi, How can I partitioned an example vector like this > print(myvector) [1] 30.9 60.1 70.0 73.0 75.0 83.9 93.1 97.6 98.8 113.9 into the following pairwise partition: PAIR1 part1 = 30.9 part2 = 60.1 70.0 73.0 75.0 83.9 93.1 97.6 98.8 113.9 PAIR2 part1 = 30.9 60.1 part2 = 70.0 73.0 75.0 83.9 93.1 97.6 98.8 113.9 .... PAIR9 part1 = 30.9