similar to: sum the values in a vector as a complete number

Hi Suppose we have an object with strings: A<-c("a","b","c","d") Now I do: B<-matrix(A,4,4, byrow=F) and I get a a a a b b b b c c c c d d d d But what I really want is: a b c d b c d a c d a b d a b c How can I do this? thank you A. Dias -- View this message in context:

Hi, as an example I have made this script to give the user the answer if a number is odd or even: { cat("Please, enter a number (Zero ends)") n<-scan(n=1) if(n==0)break i<-("The number is odd") p<-("The number is even") if (n%%2==0) p else i } If you run this script it will only work once, I mean, after it gives you the answer is won't ask for

Hi, I am having a problem in doing something similar to this example: Suppose I have this vector a, and from it I wish to create 5 other vector each one with less one value than what object a has So I have "a" a<-c(1,2,3,4,5) and I want a1 that shoud have (2,3,4,5) a2 that should have (1,3,4,5) a3 that should have (1,2,4,5) a4 that should have (1,2,3,5) a5 that should have

Hi, I have this character vector: A<-c("Tell me how many different letter this vector has?") Is there a way with R that it can let me know how many different letters I have on this vector? If I use nchar(A) que gives me the number 50. With this function he is counting all the letters present and also spaces between the words. Can we also not count the spaces between words? Then

Hi, I am with a problem on how to do a comparison of values. My script is as follows: repeat{ cat("How many teams to use? (to end write 0) ") nro<-scan(n=1) if(nro==0)break cat("write the", nro, "teams names \n") teams<-readLines(n=nro) if (teams[1]==teams[2)next else print(teams) } On this example I only compare teams 1 name with teams 2 name, and if they

Hi I have this function and this matrix: function(x,y) x+y/x m<-matrix(c(1,2,4,2,10,8),3,2) > m [,1] [,2] [1,] 1 2 [2,] 2 10 [3,] 4 8 each row represent a point (x,y) in a chart and I want via my fucntion to calculate the image in order to get this results: for point (1,2) I would get 1+2/1 = 3 for point (2,10) I would get 2+10/2 = 7 for point (4,8) I would get

Hi, here im unable to run a string handle function called unpaste(). for eg:- a<- "12345_mydata" Actually my requirement what is i need to get , only 12345. Means that , i need the all letter as a word which is before of first " _ " - symbol of "a". i tried to do with unpaste, it says function not found. After that i tried with "strsplit() ". it

The problem ----------- I want to copy a file from machine A (master) to machine B (backup) but I would like to stop root user on machine B to easily look at the file contents. So I encrypt the file to send at machine A and send just the encrypted version to machine B (which has no means to decrypt the file). Then I make a small change in the file in the machine A and want to send the new

Dear R users, I have a dataframe with one character field, and I would like to create two new fields (columns) in my dataset, by spliting the existing character field into two using an existing substring. ... something that in SAS I could solve e.g. combining substr(which I am aware exist in R) and "index" for determining the position of the pattern within the string. e.g. if my

I need to split a given matrix in a sequential order. Let my matrix is : > dat <- cbind(sample(c(100,200), 10, T), sample(c(50,100, 150, 180), 10, > T), sample(seq(20, 200, by=20), 10, T)); dat [,1] [,2] [,3] [1,] 200 100 80 [2,] 100 180 80 [3,] 200 150 180 [4,] 200 50 140 [5,] 100 150 60 [6,] 100 50 60 [7,] 100 100 100 [8,] 200 150 100 [9,]

Dear Mao Jianfeng, "r-help-owner" is not the place for help, but: r-help at r-project.org (CC-ed here) In any case, strsplit() does the job, i.e.: > unlist(strsplit("BCPy01-01", "-")) [1] "BCPy01" "01" You can work with the whole variable, like: splitpop <- strsplit(df1$popcode, "-") then access the first part with >

I'm just wondering if there is an easy way to do this... My pxelinux.cfg/default is getting very long... and I'd like to make it shorter by spliting it up into sections which would load other config files. So basically I want to do something like the grub: "configfile (nd)/other.lst" Is there an easy way? -- Cheers Paul

Hello All, Sorry if this has be discussed already, I have a syslinux config which is rather big [7000+ char] and I see that the menu system "menu.c32" shows only part of the menu configured. Also the last entry in the menu contains only half of the configuration. Is there a limit to the size of config file for the menu ? I tried to work around the problem by spliting the config file

Hi there, From the vector X of integers, X = c(11999, 122000, 81997) I would like to make these two vectors: Z= c(1999, 2000, 1997) Y =c(1 , 12 , 8) That is, each entry of vector Z receives the four last digits of each entry of X, and Y receives "the rest". Any suggestions? Thanks in advance, Dimitri [[alternative HTML version deleted]]

Hi Steven, Thank you for the help. I get an error though when i do this : >lit<-read.csv("litologija.csv", sep=";", dec=".") >sent <-data.frame(sentence=lit$Opis,stringsAsFactors=FALSE) >str(sent) >sentV<-rep(sent,10) >str(sentV) >first=second=third=fourth=fifth=sixth=seventh=eighth=ninth=tenth<-vector(length=10) >DF

Dear R users, Suppose I have a data set with inconsistent names for a field. I desire to make these to consistent names. i.e "University of New Jersey", "New Jersey Uni", "New Jersey University" (3 different inconsistent names) to "The University of New Jersey" (consistent name) Below are arbitrary data set produced from "state.name" (built

Hello list, hope some one could help me find the answer. Asterisk 1.4.16.2 installd as no-root user The main issue is that every now and then, cd * box seems to loose the user's registrations, there is nothing in the console, absolutely no messages, only when another friend trys to dial an extension I can see this on messages logs [Jan 26 10:35:46] WARNING[23015] app_dial.c: Unable to

Hi everyone, I have a vector of strings, each string made up by different number of words. I want to get a new vector which has only the first word of each string in the first vector. I came up with this: str <- c('aaa bbb', 'cc', 'd eee aa', 'mmm o n') str1 <- rep(1, length(str)) for (i in 1:length(str)) { str1[i] <- strsplit(str, "

Is it possible to call rsync and tell it to use a filter file if it exists, but otherwise continue without errors? If I pass "--filter=. .rsync-filter", it will fail if .rsync-filter doesn't exist. I know you can pass "--filter=: /.rsync-filter" to search for filter files in each directory. That won't fail if there aren't any such files. But I'm only

Hi i have the data in the following format: rent,100,1,common,674 pipe,200,0,usual,864 car,300,1,uncommon,392:jump,700,0,common,664 car,200,1,uncommon,864:snap,900,1,usual,746 stint,600,1,uncommon,257 pull,800,0,usual,594 where as i want the above 6 lines data into 8 lines as below (Spliting row 3 & 4 at : and sending to a new row): rent,100,1,common,674 pipe,200,0,usual,864