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I have the attached class that I''m writing. The problem that I''m running into is that I can not access the options from the createArray function which get called after the ajax request gets done. I want to move the values of the xml file to an array and story it in the options variable. Can someone explain what I''m doing wrong? var LeaderInfo = Class.create();

Here's the select.frame() function I babbled about before. Suggestions about coding style, etc., are welcome, I feel a bit green at this. select.frame<- function (dfr, ...) { subst.exp <- function(e) { for (i in 2:length(e)) { ei <- e[[i]] if (is.call(ei)) e[[i]] <-

Thanks. Will try it. Have not tried it but I think the following may work: out$results<-NULL out$results$ei<-ap out$results$vi<-vap All I need is printing by returning out (unless I turn it off). And, retrieve ap and vap as needed as shown above. Guess I need to read more about invisible. On 8/11/2024 10:09 PM, Rui Barradas wrote: > ?s 09:51 de 11/08/2024, Steven Yen escreveu:

?s 09:51 de 11/08/2024, Steven Yen escreveu: > Hi > > In the following codes, I had to choose between printing (= TRUE) or > deliver something for grab (ei, vi). Is there a way to get both--that > is, to print and also have ei and vi for grab? Thanks. > > Steven > > ... > > out<-round(as.data.frame(cbind(ap,se,t,p)),digits) > out<-cbind(out,sig) >

Hi Dear All, This is a function which contains Covariance Ratio and Likelihood Distance values (CVRi, LDi). i want to compute the all row's values, that is run this function for nrow(X) times. The X and Y matrices are;

Hi In the following codes, I had to choose between printing (= TRUE) or deliver something for grab (ei, vi). Is there a way to get both--that is, to print and also have ei and vi for grab? Thanks. Steven ... out<-round(as.data.frame(cbind(ap,se,t,p)),digits) out<-cbind(out,sig) out<-out[!grepl(colnames(zx)[1],rownames(out)),] if(printing){ cat("\nAPPs of bivariate ordered

Hi, I' am interested in differences between sample's result when samples consist of full elements and consist of only distinct elements. When sample consist of full elements it take about 120 sec., but when consist of only distinct elements it take about 4.5 or 5 times more sec. I expected that opposite of this result, because unique(sample) has less elements than full sample. Code as

Christian, the question for you is towards the end... On 09/10/2015 15:39, Denis V. Lunev wrote: > diff --git a/arch/x86/kvm/hyperv.c b/arch/x86/kvm/hyperv.c > index 62cf8c9..15c3c02 100644 > --- a/arch/x86/kvm/hyperv.c > +++ b/arch/x86/kvm/hyperv.c > @@ -23,13 +23,265 @@ > > #include "x86.h" > #include "lapic.h" > +#include "ioapic.h"

Christian, the question for you is towards the end... On 09/10/2015 15:39, Denis V. Lunev wrote: > diff --git a/arch/x86/kvm/hyperv.c b/arch/x86/kvm/hyperv.c > index 62cf8c9..15c3c02 100644 > --- a/arch/x86/kvm/hyperv.c > +++ b/arch/x86/kvm/hyperv.c > @@ -23,13 +23,265 @@ > > #include "x86.h" > #include "lapic.h" > +#include "ioapic.h"

Hi I work with cmsaf package and have a script for prepare data in R. I run this script and have some error like this:Error in if (startdate < dates[1]) (dums <- 1) : missing value where TRUE/FALSE needed In addition: Warning messages: 1: running command 'tar.exe -tf "D:/CM SAF/ORD24552.tar"' had status 2 2: In eval(ei, envir) : NAs introduced by coercion 3: In eval(ei,

Hi everyone ! I am very new to LLVM and intent to use it in a research project. I have a problem with the interpreter: I have a simple compiler that generates LLVM bitcode, JIT it and execute it, and it works very well. Now I would like to execute it using the interpreter. And I get a segfault. Here is the code : // This code JIT the function and executes it llvm::InitializeNativeTarget();

Hi, Calling gdistance::shortestPath gives me the error Error in asMethod(object) : not a symmetric matrix; consider forceSymmetric() or symmpart() The output of dput(.traceback()) is pairlist("stop(\"not a symmetric matrix; consider forceSymmetric() or symmpart()\")", "asMethod(object)", "as(Laplacian,\"symmetricMatrix\")",

Hello All, I need a script to perform different actions depending on the file from which it was source()'d. Thus, my script needs a way to figure out from whence it was sourced. There seems to be some relevant information in sys.calls() (see below). However, I need to get at the name of the file that directly source the file in question. That is, just one level above. For example, in the

Helps to send to list: On Tue, Nov 2, 2010 at 1:00 PM, OvermindDL1 <overminddl1 at gmail.com> wrote: > On Tue, Nov 2, 2010 at 12:51 PM, Salomon Brys <salomon.brys at gmail.com> wrote: >> Hi everyone ! >> I am very new to LLVM and intent to use it in a research project. >> I have a problem with the interpreter: I have a simple compiler that >> generates LLVM

Hi R-users, I have a data frame like this: photographer category picture points Hannu kalat limamikko 1 Teemu kalat verkkovaja 3 Hate kalat munat puoliks padassa 6 Hannu kalat isokala 8 Teemu kasvit, sienet ja muut eliöt harppi 2 Hate kasvit, sienet ja muut eliöt pyynikki 2 Petteri kasvit, sienet ja muut eliöt harmaaleppä 5 Lauri kasvit, sienet ja muut eliöt lumipuu 9 Teemu linnut kainostelua 1

Hi everyones, my function like; e <- rnorm(n=50, mean=0, sd=sqrt(0.5625)) x0 <- c(rep(1,50)) x1 <- rnorm(n=50,mean=2,sd=1) x2 <- rnorm(n=50,mean=2,sd=1) x3 <- rnorm(n=50,mean=2,sd=1) x4 <- rnorm(n=50,mean=2,sd=1) y <- 1+ 2*x1+4*x2+3*x3+2*x4+e x2[1] = 10 #influential observarion y[1] = 10 #influential observarion data.x <- matrix(c(x0,x1,x2,x3,x4),ncol=5) data.y

Hello. In order to practice compiler writing, I am implementing a simple compiler for the Tiger language. I am using llvm IR for the intermediate representation. Regarding llvm, I have started by reading the OCaml version of the LLVM Tutorial, where a compiler for the kaleidoscope language is built. The language I am implementing has a form of expression called "sequence expression".

Hi, R-users, I met a problem: Items:[Anna 'moi =) akku loppu joskus 4ltä. Kestää kauan nää..'\tAmer, Tuusula (0:20)\t20\t12\t16\t00\t00\t11]/Anne 'Ei jakoa,uus päivä muistio et 4n niin peruin. Hups'\t (0:16)\t0\t12\t18\t00\t00\t11/Elina 'Konsertissa. En tod. vastaa teille'\tEtu-Töölö, Helsinki (2:40)\t24\t12\t18\t00\t00\t11 I want to parsing the above data into the

Is there a way to set up a regression in R that forces two coefficients to be equal but opposite in sign? I'm trying to setup a model where a subject appears in a pair of environments where a measurement X is made. There are a total of 5 environments, one of which is a baseline. But each observation is for a subject in only two of them, and not all subjects will appear in each

While working on the printing code, my colleague Zbyn?k ?lajchrt noticed that complex matrixes are sometimes misaligned: > { matrix(1i,2,13) } [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13] [1,] 0+1i 0+1i 0+1i 0+1i 0+1i 0+1i 0+1i 0+1i 0+1i 0+1i 0+1i 0+1i 0+1i [2,] 0+1i 0+1i 0+1i 0+1i 0+1i 0+1i 0+1i 0+1i 0+1i 0+1i 0+1i 0+1i 0+1i (the values in the last four columns