similar to: Displaying ylab in mfrow

Displaying 20 results from an estimated 400 matches similar to: "Displaying ylab in mfrow"

2009 Mar 06
1
Interpreting GLM coefficients
Hi all, I?m fitting GLM?s and I can?t interprete the coefficients when I run a model with interaction terms. When I run the simpliest model there is no problem: Model1<-glm (Fishes ~ Year + I(Year^2) + Kind.Geographic + Kind.Fishers + Zone.2 + Hours + Fishers + Month, family = poisson(log)) # Fishes, Year, Hours, and Fishers are numeric, Kind.Geographic, Kind.Fishers, Zone.2 and
2018 Feb 23
4
change location of temporary files
I would like to change where R stores the temporary files to my external hard drive in my iMac. This is important because the temporary files R creates are huge and I do not have enough available space in my internal HD. Again, this is for macOS. This change has to be temporary. Later I need to use the usual location for temp files in the internal HD. Thanks in advance, Kumar Mainali --
2009 Mar 29
1
Data decomposition
Hi R users, I have a time series variable that is only available at a monthly level for 1 years that I need to decompose to a weekly time series level - can anyone recommend a R function that I can use to decompose this series? eg. if month1 = 1200 I would to decompose so that the sum of the weeks for month1 equals 1200, etc.. Many thanks in advance for any help. -- View this message in
2018 Feb 23
0
change location of temporary files
Does setting the environment variable TMPDIR, before starting R, to a directory on a bigger file system help? On Linux I get % mkdir /tmp/RTMP-BILL % env TMPDIR=/tmp/RTMP-BILL R --quiet --vanilla > tempdir() [1] "/tmp/RTMP-BILL/Rtmppgowz4" > tempfile() [1] "/tmp/RTMP-BILL/Rtmppgowz4/file7ce36ec5cb1e" I don't know if there is an R-specific environment
2011 Dec 04
3
Group several variables and apply a function to the group
Dear R-experts, I am struggling with the following problem, and I am looking for advice from more experienced R-users: I have a data frame with 2 identifying variables (comn and mi), and an output variable (x). comn is a variable for a company and mi is a variable for a month. comn<-c("abc", "abc", "abc", "abc", "abc", "abc",
2013 Jan 30
2
Programmatically give file name to a matrix
I have a situation when I need to save matrix with file names that are programmatically created. for (i in levels(mergeTrn$Continent)) { matrix here.... # I want to save this matrix with a file name that carries "i" from for loop. The following does not work. paste("plotroc_GBM_Trn_", i, sep="") <- matrix } Thanks, Kumar -- Section of Integrative
2017 Dec 07
2
parallel computing with foreach()
I have used foreach() for parallel computing but in the current problem, it is not working. Given the volume and type of the data involved in the analysis, I will try to give below the complete code without reproducible example. In short, each R environment will draw a set of separate files, perform the analysis and dump in separate folders. splist <- c("juoc", "juos",
2011 Jul 25
2
Selecting unique values
Greetings I have a dataset with occurrence records of multiple species. I need to get rid of multiple listings of the same occurrence point for a species (as you see below in red and blue typeface). How do I create a dataset only with unique set of longitude and latitude for each species? Thanks in advance. Species_name Longitude Latitude Abies concolor -106.601 35.868 Abies concolor -106.493
2017 Dec 07
0
parallel computing with foreach()
Your code generates an error that has nothing to do with dopar. I have no idea what your function stack is supposed to do; you may be inadvertently calling utils::stack which would produce this kind of error: > stack(1:25, RAT = FALSE) Error in data.frame(values = unlist(unname(x)), ind, stringsAsFactors = FALSE) : arguments imply differing number of rows: 25, 0 HTH, Peter On Wed, Dec 6,
2012 Nov 24
3
Designating a new year (Sept-Aug) in R
If I have data (below) and need some help in figuring out how I can change the values of my date column, so that a year will be from September-August? So the year 1990 = September 89-August 90; 1991 = September 90-August 91, etc... I was trying to use the if() function, but am unable to figure it out. I basically need to change the years associated with September-December to the following
2013 Feb 15
1
file copy to password protected network drive
I am trying to copy files to a password protected drive which is "Ranch" at TACC from another network drive. I am logged in to the source drive and can run R there. The following code does not even find the destination folder. file.copy("sourcedrive/file.tar", " username@ranch.tacc.utexas.edu/uniqueID/destinationfolder/file.tar", overwrite = FALSE) Thanks in
2011 Jan 17
2
How to still processing despite bug errors?
Hi, everybody. I am working processing EEG data from 1000 pacients. I have a specific syntax to perform the Spectral Analysis and a loop to analyse all subjects. each subject data are in separate folders (P1, P2 P3...) My question is: in some cases, some errors can appear in one subject. I want to know if is possible to jump to the next subject and perform the same syntax , exibiting an error
2009 Mar 08
1
fill the space between to lines
hi, the code below produces me two curved lines. Now I want to fill the space between these curves with a color and I don't have any idea how to do that with R. I tried it with the polygon() function but it didn't worked out. Can someone her give me a hint on that? thanks! x1 <- c(0.0,0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9,1.0,1.1,1.2,1.3,1.4,
2004 Dec 10
1
Adding a polygon to a time series plot
Preamble: Sorry for being dense. Now that that's done, here are my questions. I want to put a polygon on a plot of a time series. I'm going to add lines from a smooth.spline interpolation and other annotation to it. But here's the general idea: # Start code n <- 121 dat <- rnorm(n) plot(dat, type="n") polygon(c(1:n,n:1), c(dat,c(rep(0,n))), col =
2008 Jul 23
6
Convert list of lists <--> data frame
For a function that takes an argument as a list of lists of parameters, I'd like to be able to convert that to a data.frame and vice versa, but can't quite figure out how. pats <- list(structure(list(shape = 0, shape.col = "black", shape.lty = 1, cell.fill = "white", back.fill = "white", label = 1, label.size = 1, ref.col = "gray80",
2000 Dec 22
0
par(lab= *) / axis(*) bug (PR#791)
As the subject says, here is example code (with comments) showing the problem: p1 <- function(lab = c(8,12,7)) { ## This `fails' (on a virgin device) clab <- paste(lab,collapse=",") plot(1,1, xlim = c(0,15), ylim = c(-.8,1), type ="n", axes = FALSE, main=paste("plot(*,axes=F); par(lab= c(",clab,")); axis(*) x
2012 Nov 24
0
Plot of 3d stock price density
Hi, I have thought a lot about my problem and also posted it on stackexchange, the post can be found here: http://stats.stackexchange.com/questions/44276/how-to-plot-3d-gbm but I have got no useful answer, that's why I trry the last possibility, which is to ask you professional guys. I want to recreate the following picture with my own code, the picture can be found in my other post:
2012 Oct 22
0
Lattice to ggplot2: Reference graphics across facets
Hi, I'm playing with moving some of my lattice graphics into ggplot2, and I'd like to ask how to achieve a couple of things, both of which are fully illustrated in self-contained code (and mostly minimal, although that left quite a bit) following this written description. 1. I quite often like to use a 'ghosted' reference across facets - for example, in my example program below,
2012 Nov 06
3
Survplot, Y-axis in percent
Hi I am a new fan of R after getting mad with the graphical functional in SPSS. I have been able to create a nice looking Kaplan Meyer graph using Survplot function. However I have difficulties in turning the y axis to percent instead of the default 0-1 scale. Further I have tried the function yaxt="n" without any results. Any help in this matter will be appreciated. The code is
2012 Nov 30
3
(no subject)
Hello R usuer, The code given below superimposes a pie diagram on another plot containing some points. However, I would like to center the pie diagram on the xy location on the plot, but not on the center. is there any way to re-center pic diagram. Any suggestion or better alternative are highly appreciated. Thank you in advance for your help. Regards, Bibke library(visualFields) library(car)