similar to: Outputting csv file from dataframe with columns in a particular order

Dear all, how can I perform a string operation like strsplit(x," ") on a column of a dataframe, and put the first or the second item of the split into a new dataframe column? (so that on each row it is consistent) Thanks Boris

I have a dataframe object having the following structure FinalOutput[1:3,] GasDays 2011-03-31 2010-09-30 2010-10-31 2010-11-30 2010-12-31 2011-01-31 2011-02-28 1 2006-10-01 217303553 221205033 222824639 217016511 216093460 216477468 216834021 2 2006-10-02 231158527 234565250 236004109 231467851 230100639 230079907 230734064 3 2006-10-03 282062314 285427832 286372163

Dear R-users, I'm writing a program that constructs a dataset. I wish to save the dataset to a file. Here's a very simple example of what I'm trying to do function(x=peter){ y <- x/2 write.csv(y, file = "...\x") } The problem is that I want to name the dataset as whatever the name of the input is. In this case peter. How do I do this? Thank you in advance. Kristian

Hi R-users I can not change the name of one column only of my matrix. my_matrix <- matrix (1:12,ncol=3) colnames(my_matrix)[1] <- 'myname' Error in dimnames(x) <- dn : length of 'dimnames' [2] not equal to array extent thank you for your help Lorenzo [[alternative HTML version deleted]]

Hi, I have a list which looks like this... > str(y) List of 10 $ : chr [1:4] "ABCD" "5" "0" "1" $ : chr [1:4] "DEF" "15" "1" "16" $ : chr [1:4] "AAA" "2" "17" "8" $ : chr [1:4] "SSS" "15" "25" "1" $ : chr [1:4] "III"

I often read SPSS system files (*.sav) into R using the 'read.spss' function from the 'foreign' library. To retain all the meta data, i.e. 'variable labels', I call the function like this: test.sav <- read.spss('http://www.cdc.gov/healthyYouth/shpps/2006/spss/envs2006.sav', to.data.frame=FALSE, use.value.labels=TRUE ) This returns a list, which is fine.

Dear All, I am experiencing some problems in resetting the values of some selected elements in a dataframe. Consider d<-seq(-1,1,length=16) dim(d)<-c(4,4) d<-as.data.frame(d) sel_pos<-which(d>0, arr.ind=TRUE) d[sel_pos]<- -9 which returns the error Error in `[<-.data.frame`(`*tmp*`, sel_pos, value = -9) : only logical matrix subscripts are allowed in replacement

First I have a matrix called stocks1: > class(stocks1) [1] "matrix" Here are the first 5 rows of the last 4 columns: > stocks1[1:5,2:5] [,1] [,2] [,3] [,4] [1,] 80.73 31.95 25.4 25.69 [2,] 83.66 31.95 27.12 25.2 [3,] 83.27 32.93 28.74 26.29 [4,] 83.9 34.07 29.77 26.6 [5,] 82.74 35.18 30.24 27.41 Now, why can't I convert this into a dataframe?

Hello everyone, I have a data set like this: > head( fish_transect) ID_TRANSECT ID_PROJECT DE_ZONE DE_LOCALITY DE_SECTOR MES 1 42 MB Tarragona Creixell Control I 9 2 42 MB Tarragona Creixell Control I 9 3 42 MB Tarragona Creixell Control I 9 4 42 MB Tarragona Creixell Control I 9 5 42

Dear users, My problem concerns save() within a for loop. Here is my code: for (i in 1:4) { temp <- data.frame(a=(i+1):(i+10), b=LETTERS[(i+1):(i+10)]) filename <- paste("file", i, sep="") assign(filename, temp) save(filename, file=paste(filename, ".rda", sep="")) } As you can see, save() doesn't work as I would like: (1) the object

Hi everybody! I would like to export the results of a test statistic in a *.csv file, but get an error. The code is below. The data are attached as .txt with tab as separator. I tried to get a sample dataset, but for some reason it didn't work, so please excuse the length of the file. I also attached a txt with the output (copy/paste) in case that helps. ---- > library(WRS) >

Hello everyone, I have versions 2.7.2 and 2.10.1 installed on a machine that has no access to internet. In 2.7.2 I can use ? to get help on functions, which in 2.10.1 that does not work, all I see is "starting httpd help server...done" and then nothing. Have I downloaded 2.10.1 incorrectly (=forgot to tick some box for local help file repository) or is the internet help now the

Hey all, I am writing a function in which I will have a matrix of 4 columns and a variable amount of rows. The first to columns will always contain be of the Character type, the third and fourth columns can be a variation of data types, usually characters and integers, but sometimes lists or matrices. At one point the code makes, for each row, a copy of that row, then it makes some adjustments

sorry I had a mistake sending my question without a subject. I do resend again. Please excuse me. > Hello > I have a data array with soil variables (caperf), in which the variable "clay" is factor (as I see entering str(caperf)) . I need to do a regression model, so I need to have arcilla (=clay) as a numeric variable. For that I have entered > >

Is there a way to use read.csv() on such a file without deleting one of the header rows? Thanks.

Dear users, I would like all the ticks on a boxplot (x and y) to be labeled I have checked all the par() arguments but couldn't find what I'm looking for Here is an example to show it: df <- structure(list(SPECSHOR = structure(c(1L, 1L, 1L, 3L, 3L, 3L, 3L, 3L, 4L, 4L), .Label = c("cotau", "dibic", "eqgre", "gicam"), class =

Hello guys, I want to rbind the columns of a data frame but I don't know how to do it, let's say: A B C 1 2 3 1 2 3 I want to get 1 1 2 2 3 3 It seems very simple but I still didnt get a find of how to do it...Please help! -- View this message in context: http://r.789695.n4.nabble.com/bind-a-data-frame-columns-tp2318526p2318526.html Sent from the R help mailing list archive

Hello, How can I read a xlsx file using xlsx package? Thanks Albert [[alternative HTML version deleted]]

Hi, I have tried looking at the archives but havent found any answer that works till now (Sorry if i have missed anything) I am a newbie to R and i am trying to carry out hierarchical clustering using hclust -> as.dendrogram and then plotting the results as a dendrogram using the plot function plot(object). My question is : In the function "plot", can one decrease the leaf label

Dear R-help list users, I have a huge vector of numbers, how I can invert orden? For example x <- 1:10000000 I would like to obtain x_r <- 10000000:1 Thanks, Sebastian.