similar to: Aggragating subsets of data in larger vector with sapply

Hi, I cannot figure out how to change the index format when displaying POSIXct objects. Would like the xts index to display as %H:%M:%OS3 when doing viewing the xts object. Think I am missing the obvious. Cheers, Chris -- View this message in context: http://r.789695.n4.nabble.com/xts-POSIXct-index-format-tp3336136p3336136.html Sent from the R help mailing list archive at Nabble.com.

Hi, Have been having trouble trying to figure out the right regex parameters to remove the last "." in timestamp with the following format: Convert 09:30:00.377.853 to 09:30:00.377853 Thanks, Chris -- View this message in context: http://r.789695.n4.nabble.com/Regex-to-remove-last-character-tp3172466p3172466.html Sent from the R help mailing list archive at Nabble.com.

Hi, I am trying to find the best way to read 85 tick data files of format: > head(nbbo) 1 bid CON 09:30:00.722 09:30:00.722 32.71 98 2 ask CON 09:30:00.782 09:30:00.810 33.14 300 3 ask CON 09:30:00.809 09:30:00.810 33.14 414 4 bid CON 09:30:00.783 09:30:00.810 33.06 200 Each file has between 100,000 to 300,300 rows. Currently doing nbbo.list<-

Is there a easy way to create the time index for a zoo/xts object for every 100 milliseconds. eg. time Index would be: 10:00:00:100 10:00:00:200 10:00:00:300 10:00:00:400 I am looking to build an empty zoo/xts object with time index from 10am to 3pm, index jumps by 100ms each row. Thanks, Chris -- View this message in context:

Have timestamp in format HH:MM:SS.MMM.UUU and need to remove the last "." so it is in format HH:MM:SS.MMMUUU. What is the fastest way to do this, since it has to be repeated on millions of rows. Should I use regex ? Currently doing it with a string split, which is slow: >head(ts) [1] 09:30:00.000.245 09:30:00.000.256 09:30:00.000.633 09:30:00.001.309 09:30:00.003.635

Hi, Please can you tell me what I am doing wrong. When trying to merge two xts objects, one of which has multiple character vectors for columns...I am just getting NAs. > str(t) POSIXct[1:1], format: "2011-01-04 11:45:37" > y2 = xts(matrix(c(letters[1:10]),5), order.by=as.POSIXct(c(t + 1:5))) > names(y2) = c(1,2) > y2 1 2 2011-01-04 11:45:38

Hi Ralph, On 05.01.15 15:00, Ralph B?hme wrote: >> [Programs] >> path = /server/shares/programs >> valid users = some users >> read only = No >> force create mode = 0660 >> force directory mode = 0770 >> vfs objects = fruit # tried without fruit vfs, no change > > on first reading I thought this sound

The following patches shave some rough edges off the tools build system to allow cross compiling for at least arm32 and arm64 based on the Debian/Ubuntu multiarch infrastructure. They also add the necessary fixes to build for arm64 (which I have only tried cross, not native). I have posted some instructions on how to compile with these patches on the wiki:

Hi, I am trying to create Bid/Ask for each second from a high volume stock and the only way I have been able to solve this is using loops to create the target matrix from the source tick data matrix. Looping is too slow and not practical to use on multiple stocks. For example: Bids Matrix (a real one is 400,000++ length): Bid Time 10.03 11:05:03.124 10.04 11:05:03.348 10.05

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 I have a small planning problem... I built an environment for a customer about six (or so) months ago based on RH8 which authenticate and mount homes from an AD server... The Linux stuff was straigt forward - using LibNSS/LDAP and LibPAM/{LDAP,Krb5} for authentication and samba (2.x something) to mount the home directories. Unfortunatly, this

Hi, When I am editing a command using default R console in Linux, sometimes it is going into "vi mode"...not too sure how/why this happening. It then requires me to use vi commands to edit the line, which is very frustrating when I just want to use the delete key instead of "x" to delete a character. How do I turn this off ? Thanks, Chris -- View this message in context:

Losing time offset from GMT: > sTime = as.POSIXct(paste("2008-03-03","09:30:01"), origin="1970-01-01") > sTime [1] "2008-03-03 09:30:01 EST" <---- 9.31am EST > sTime [1] 1204554601 > t = as.numeric(sTime) > as.POSIXct(t, origin="1970-01-01") [1] "2008-03-03 14:30:01 EST" <----- no tz option and t is sTime + 5

Hi, I am processing tick data and my code has stopped working as I have increased the size of data being processed. Now I am receiving error for basic tasks in RConsole: > a = c(1:1000) Error: evaluation nested too deeply: infinite recursion / options(expressions=)? My R code worked fine with 50 stocks and 500,000 rows per stock, but when I increased this to 50 stocks and 5,000,000 rows per

Hello, I'm using the latest git 4.2.0 samba version (4.2.0rc4-GIT-93b73bf, to get latest vfs_fruit module). I noticed the following strange behavior with OSX clients (10.10.1, 10.10.2 beta): When they connect using either smb 3.0 or 2.1 (verified on the server with `smbstatus` and the `version` column `SMB3_00` or `SMB2_10` respectively), symbolic links pointing at non existent files are not

Dear developers, I found a small typo in the german translation for the aggregate() function: In the string "keine Zeile f?r die Aggragation" it should be spelled 'Aggregation' instead of 'Aggragation' (e instead a). After a quick look into the sources, I found two places for it: #grep -r -e "Aggragation" * src/library/stats/po/R-de.po:msgstr "keine

Hi R experts, I need know how calculate a weighted mean by group in a data frame. I have tried with aggragate() function: data.frame(x=c(15,12,3,10,10),g=c(1,1,1,2,2,3,3),w=c(2,3,1,5,5,2,5)) -> d aggregate(d$x,by=list(d$g),weighted.mean,w=d$w) Generating the following error: Error en FUN(X[[1L]], ...) : 'x' and 'w' must have the same length Thanks in advance [[alternative

Hi all, I've got the following problem. I have a vector containing file names. I want to read these files as csv and calculate the density-function for each file (has just one column with data). Then, I'd like to plot all density functions into one window. I did the following to calculate the density data: s <- sapply(filelist, function(x) { if(file.exists(x)) { file <-

I am puzzled by the scope rules that apply with sapply. If I want to modify a vector with sapply I tried... N <- 10 vec <- vector(mode="numeric", length=N) test <- function(i){ vec[i] <- i } sapply(1:N, test) vec but it not work. How can this be done? Worik [[alternative HTML version deleted]]

Hi, sapply((1:NCOL(hermes)),function(x) hist(hermes[,x],main=names(hermes)[x])) .......this works , but i would like use it with apply to generate many plots in one step! #################################################################### >>apply((1:ncol(hermes)),2,function(x) hist(hermes[,x],main=names(hermes)[x])) Error in apply(1:ncol(hermes), 2, function(x) hist(hermes[, x], main =

HI, You can also try this: d<-1:25 A<-sample(combn(20:30,2)) B<-sample(combn(20:30,2)) lapply(d,function(x) matrix(c(1,A[x],B[x],1),2,2)) [[1]] [,1] [,2] [1,] 1 23 [2,] 27 1 [[2]] [,1] [,2] [1,] 1 21 [2,] 21 1 [[3]] [,1] [,2] [1,] 1 29 [2,] 23 1 [[4]] [,1] [,2] [1,] 1 25 [2,] 20 1 [[5]] [,1] [,2] [1,] 1 23 [2,]