similar to: Selecting non-empty elements after strsplit of string

Hi there, I have a problem about lapply, strsplit, and accessing list elements, which I don't understand or cannot solve: I have e.g. a character vector with three elements: x = c("349/077,349/074,349/100,349/117", "340/384.2,340/513,367/139,455/128,D13/168", "600/437,128/903,128/904") The task I want to perform, is to generate a list,

Dear R-list I'm working with with geom_errorbar; specifically I'm trying to reproduce the example Hadley Wickham have on http://had.co.nz/ggplot2/geom_errorbar.html (all in the button of the page) where he makes an nice plot with errorbars and then draw lines between the points. What confuses me is the 'limits' he defines for the errorbars from the se variable. First he creates

Hello, I am wondering about the behaviour of strsplit. When the pattern matches the beginning of the search string, the mepty string is added to the result, but that's not the case when the pattern matches the end of the search string: strsplit(" hello dolly ") [1] "" "hello" "dolly" The man for strsplit explains the algorithm: " The algorithm

Dear R users, I am curious if someone could direct me towards websites/tutorials for uses of progress bars (especially) in R. I can't seem to figure them out. Thanks very much, Scott [[alternative HTML version deleted]]

Dear all, I want to use string split to parse column names, however, I am having some errors that I don't understand. I see a problem when I try to rbind the output from strsplit. please let me know if I'm missing something obvious, thanks, alison here are my commands: >strsplit<-strsplit(as.character(Rumino_Reps_agreeWalign$geneid),"\\.") >

strsplit() is a convenient way to get a list of items from a string when you have a regular expression for what is not an item. E.g., > strsplit("1.2, 34, 1.7e-2", split="[ ,] *") [[1]]: [1] "1.2" "34" "1.7e-2" However, sometimes is it more convenient to give a pattern for the items you do want. E.g., suppose you want to pull

Hi all, Came across an error in ?strsplit in the details section: Details: Arguments 'x' and 'split' will be coerced to character, so you will see uses with 'split = NULL' to mean 'split = character(0)', including in the examples below. I caught myself trying to use strsplit() on a factor and the coercion on 'x' is not done. According

Hi, As show in the code below, strsplit can be applied to a matrix but not a data.frame. I don't understand why R is designed in this way. Can somebody help me understand it? How to split all the strings in x$y? x=data.frame(x=1:10,y=rep("abc",10)) strsplit(x$y,'b') #Error in strsplit(x$y, "b") : non-character argument y=cbind(1:10,rep("abc",10))

\b is word boundary. But, unexpectedly, strsplit("dia ma", "\\b") splits character by character. > strsplit("dia ma", "\\b") [[1]] [1] "d" "i" "a" " " "m" "a" > strsplit("dia ma", "\\b", perl=TRUE) [[1]] [1] "d" "i" "a" " "

Hi, A pared down version of the dataset I'm working with: edm<-read.table(textConnection("WELLID X_GRID Y_GRID LAYER ROW COLUMN SPECIES CALCULATED OBSERVED w301_3 4428. 1389 2 6 18 1 3558 6490. w304_12 4836. 6627 2 27 20 1 3509 3228. 02_10_12080 3.6125E+04 13875 1 56 145 1

Hi, I tried to use strsplit for separating a string with || like strsplit(string,"\\||") but it returned each single character was separated. For example: strsplit("a||bc","\\||") [[1]] [1] "a" "" "" "b" "c" where I want the result to be "a" and "bc". Any ideas? Thanks! Best,

Dear R People: I am trying to split a character vector into a set of individual letters: Ideal: x3 <- c("dog") "d" "o" "g" I tried the following: > strsplit(x3) Error in strsplit(x3) : argument "split" is missing, with no default > strsplit(x3,1) [[1]] [1] "dog" I know that this is incredibly simple, but what am I doing

Hi All, is there a way of using strsplit with a forward slash '/' as the splitting point? For data such as: 1 T/T C/C 16/33 2 T/T C/C 33/36 3 T/T C/C 16/34 4 T/T C/C 16/31 5 C/C C/C 28/29 6 T/T C/C 16/34 strsplit(my.data[1,1], "/") # and any variation thereof Error in strsplit(apoe[1, 1], "/") : non-character

Hi all, > diff_operator <- "\\(" > strsplit(cond, diff_operator) [[1]] [1] "andsin" "log_angle_1_4)" > diff_operator <- "\\sin(" > strsplit(cond, diff_operator) Error in strsplit(cond, diff_operator) : invalid regular expression '\sin(', reason 'Missing ')'' When I am going to split with "("

I have a comma-separated data file in which trailing commas sometimes occur. I am using strsplit to extract the data from this file, and it seems great except in cases with trailing comma characters. The example below illustrates. What I'd like is to get a fourth element in the answer, being an empty string just like the second element. Is there a way I can express my patter (or perhaps

Full_Name: Charles Dupont Version: 2.2.0 OS: linux Submission from: (NULL) (160.129.129.136) when strsplit("", " ") returns character(0) where as strsplit("a", " ") returns "a". these return values are not constiant with each other. Charles Dupont

Dear Researchers, I have several files as this example: Myfile_MyArea1_sample1.txt i wish to split in "Myfile", "MyArea1", "sample1", and "txt", becasue i need to use "sample1" label. I try to use "strsplit" but I am able just to split as "Myfile_MyArea1_sample1" and "txt" OR "Myfile", "MyArea1",

Hello R Gurus: I would like to take a character string and split at the $ sign. I thought that strsplit would do it, but here are the results: > vv [1] "whine$ts1" > vv [1] "whine$ts1" > strsplit(vv,"$") [[1]] [1] "whine$ts1" Does anyone have any suggestions, please? Thanks, Edna Bell

Hi all, In the help of strsplit one can read split character vector (or object which can be coerced to such) containing regular expression<http://127.0.0.1:39783/help/library/base/help/regular%20expression>(s) (unless fixed = TRUE) to use for splitting. If empty matches occur, in particular if split has length 0, x is split into single characters. Ifsplit has length greater than 1, it is

Dear Guru's My first steps with R have ground to a halt! I have a vector of sample identifiers > sampleIDs [1] "D1_1" "D1_2" "D1_3" "D1_4" "D1_5" "D1_6" "D1_7" "D1_8" [9] "D1_9" "D1_10" "D1_11" "D1_12" "F1_13" "F1_14"