similar to: fast subsetting of lists in lists

Dear all, I have searched the forums for an answer - and there is plenty of questions along the same line - but none of the paproaches shown worked to my problem: I have a data frame that I get from a csv: summarystats<-as.data.frame(read.csv(file=f_summary)); where I have the columns Dataset, Class, Type, Category,.. Problem1: I want to find a subset of this frame, based on values in

Dear all This may be obvious, but I cannot get it working. I'm trying to subset & sort a data frame in one go. x <- iris x$Species1 <- as.character(x$Species) ##subsetting alone works fine with(x, x[Sepal.Length==6.7,]) ##sorting alone works fine with(x, x[order(Sepal.Length, rev(sort(Species1))),]) ##gets subsetted, but not sorted as expected with(x, x[(Sepal.Length==6.7) &

Hi, I have a data-frame, r (column names below), that needs subsetting: date, time, strain, gene, deltact When I try to subset r by applying selection criteria on two columns I get an empty data frame. For example I would like to extract all rows that have time == 0h and strain == ROC. So, t <- subset(r, (r$time == "0h" && r$strain == "ROC"), select= c(time,

Hi, I'm wondering why indexing a data frame by row name doesn't work with [[. It works with [: > sw <- swiss[1:5,1:2] > sw["Moutier", "Agriculture"] [1] 36.5 but not with [[: > sw[["Moutier", "Agriculture"]] Error in .subset2(.subset2(x, ..2), ..1) : subscript out of bounds The problem is really with the row name (and not

To the R-Help list, I would like to have a clarification about an issue that I observe when subsetting a vector. This is R version 4.3.3 on Windows 10. -- Example with a vector: > a <- 1:5 > a [1] 1 2 3 4 5 So we have, with a negative index: > a[-3] [1] 1 2 4 5 But when the index is integer(0), we have this: > a[integer(0)] integer(0) > a[-integer(0)] integer(0) When

As with a lot of things in R, the behaviour is counterintuitive but (arguably) logical. The key (maybe) is that `a[-x]` does not mean "take all of the elements of a except those indicated by `x`, but rather, "negate x, then take all but the negative elements". In other words, -integer(0) is integer(0) (we multiply *each of the elements of integer(0)* by -1, but

Hello. I'm currently trying to wrap up data frames into OCaml via OCaml-R, and I'm having trouble with data frame subsetting: > # x#column 1;; > Erreur dans (function(x, i, exact) if (is.matrix(i)) as.matrix(x)[[i]] else .subset2(x, : > l'?l?ment 1 est vide ; > la partie de la liste d'arguments de 'is.matrix' en cours d'?valuation ?tait : > (i)

Hi, Hope you are well. I was wondering if there is a function at C level that is equivalent to mtcars$carb or .subset2(mtcars, "carb"). If I have the index of the column then the answer would be VECTOR_ELT(df, asInteger(idx)) but I was wondering if there is a way to do it directly from the name of the column without having to loop over columns names to find the index? Thank you Best

On Sun, Jun 23, 2019 at 03:34:08PM +0200, Stefan Froehlich via samba wrote: > No need to be sorry - most likely I'll the whole setup from scratch. Did so (I am following a script by now, so it does not take too long), but I feel more and more lost - there must be always something different I do wrong: Now I configured DNS the other way round, pointing every host to the DC and using

Consider in R-2.6.0 (also R-patched from yesterday): iris[1, c(TRUE, FALSE, FALSE, FALSE, FALSE)] ## Error in .subset2(xx, j) : recursive indexing failed at level 2 iris[1, c(FALSE, FALSE, FALSE, FALSE, TRUE)] ## Error in .subset2(xx, j) : attempt to select less than one element i.e. matrix-like indexing on data.frames, one logically-indexed dimension with only one value TRUE in it. It is

Hello, I'm fairly new to R. I'm a chemist, not a programmer so please bear with me. I have a large data.frame that I want to break down (subset) into smaller data.frames for analysis. I would like to give the data.frames descriptive names which I have stored in a character vector. My original thought was that I want the subsets to show up as individual objects, but haveing them stored

Hello, I am trying to graph a regression line using the followings: Age <- c(39, 47, 45, 47, 65, 46, 67, 42, 67, 56, 64, 56, 59, 34, 42, 48, 45, 17, 20, 19, 36, 50, 39, 21, 44, 53, 63, 29, 25, 69) BloodPressure <- c(144, 220, 138, 145, 162, 142, 170, 124, 158, 154, 162, 150, 140, 110, 128, 130, 135, 114, 116, 124, 136, 142, 120, 120, 160, 158, 144, 130, 125, 175) SimpleLinearReg1=lm(Age ~

Below is a version of [.data.frame that is faster for subscripting rows of large data frames; it avoids calling duplicated(rows) if there is no need to check for duplicate row names, when: i is logical attr(x, "dup.row.names") is not NULL (S+ compatibility) i is numeric and negative i is strictly increasing "[.data.frame" <- function (x, i, j,

Dear all, I would like to know how to subset a data.frame by rows. Example: Probesets 34884 34888 34892 1 100009676_at A A A 2 10001_at P P P 3 10002_at A A A 4 10003_at A A

Hi, Anne, assign Age and Bloodpressure in the correct order to the axes in your call to plot as in: plot(y = Age, x = BloodPressure) abline(SimpleLinearReg1) Hth -- Gerrit --------------------------------------------------------------------- Dr. Gerrit Eichner Mathematical Institute, Room 212 gerrit.eichner at math.uni-giessen.de Justus-Liebig-University Giessen Tel:

Hi folks, Pls help me to understand follow; An Introduction to R 2.4 Logical vectors http://cran.r-project.org/doc/manuals/R-intro.html#R-and-statistics 1) > x [1] 1 2 3 4 5 > temp <- x != 1 > temp [1] FALSE TRUE TRUE TRUE TRUE > 2) > x [1] 1 2 3 4 5 > temp <- x > 1 > temp [1] FALSE TRUE TRUE TRUE TRUE Why NOT > temp [1] TRUE FALSE FALSE FALSE

Hi folks, Pls help me to understand follow; An Introduction to R 2.4 Logical vectors http://cran.r-project.org/doc/manuals/R-intro.html#R-and-statistics 1) > x [1] 1 2 3 4 5 > temp <- x != 1 > temp [1] FALSE TRUE TRUE TRUE TRUE > 2) > x [1] 1 2 3 4 5 > temp <- x > 1 > temp [1] FALSE TRUE TRUE TRUE TRUE Why NOT > temp [1] TRUE FALSE FALSE FALSE

Is there a low-level function that returns the length of an object 'x' - the length that for instance .subset(x) and .subset2(x) see? An obvious candidate would be to use: .length <- function(x) length(unclass(x)) However, I'm concerned that calling unclass(x) may trigger an expensive copy internally in some cases. Is that concern unfounded? Thxs, Henrik

> On Oct 25, 2017, at 6:57 AM, BooBoo <booboo at gforcecable.com> wrote: > > On 10/25/2017 4:38 AM, Ista Zahn wrote: >> On Tue, Oct 24, 2017 at 3:05 PM, BooBoo <booboo at gforcecable.com> wrote: >>> This has every appearance of being a bug. If it is not a bug, can someone >>> tell me what I am asking for when I ask for "x[x[,2]==0,]". Thanks.

Hello, I have been banging my head against the wall trying to figure out this seemingly simple problem with no success. I'm hoping that one or some of you can help. Here is the code I am trying to use: #importing data data.file <-read.csv("/file/location", header=TRUE, sep = ",") #selecting a subset of data based on variable "Sample" data.subset1 <-