similar to: Time out for a R Function

I'm attempting to create an array of treatment comparisons for modelling data generation. This involves comparison of one treatment (c2) with another (c3), relative to a common comparator (c1). Attached code gives me the correct array but need to remove duplicates. Duplicates relate only to c2 and c3 such that I need to remove r3 because c2 and c3 are same as r1 with c2 and c3 swapped r5

Dear All, I am trying to create a empty structure that I want to fill gradually through the code. I want to use something like rbind to create the basic structure first. I am looking for a possibility to do an rbind where the columns names dont match fully (but the missing columns can be defaulted to either zero or n/a) (my actual data has a lot of columns). Please see the data frames below I

Hello, I have a data frame as below ... in cases where I have N.A. I want to use an average of the past date and next date .. any help? 13/10/2010 A 23 13/10/2010 B 12 13/10/2010 C 124 14/10/2010 A 43 14/10/2010 B 54 14/10/2010 C 65 15/10/2010 A 43 15/10/2010 B N.A. 15/10/2010 C 65 ---------------------------------------------------------------------------- -------------------------- Thanks

Dear Group, I have the following data matrix which is a timeseries. > dput(tData) structure(list(A = c(0.2, 0.13, 0.05, 0.1, 0.02, 0.18, 0.09, 0.06, 0.13), B = c(0.15, 0.06, 0.09, 0.02, 0.03, 0.12, 0.01, 0.15, 0.06), C = c(-0.1, 0, -0.07, -0.06, -0.05, -0.05, -0.06, -0.08, -0.07), D = c(-0.15, -0.05, -0.1, -0.03, -0.13, -0.04, -0.1, -0.04, -0.15), E = c(-0.17, -0.16, -0.08, -0.07, -0.09,

Dear Group, I have a following dataset: > a A B C D 1 22 3 31 40 2 26 31 36 32 3 3 7 49 16 4 24 40 27 26 5 20 45 47 0 6 34 43 11 18 7 48 48 24 2 8 3 16 39 48 9 20 49 7 21 10 17 36 47 10 > dput(a) structure(list(A = c(22L, 26L, 3L, 24L, 20L, 34L, 48L, 3L, 20L, 17L), B = c(3L, 31L, 7L, 40L, 45L, 43L, 48L, 16L, 49L, 36L), C = c(31L, 36L, 49L, 27L, 47L, 11L, 24L,

Hi Group, Is there something like a delay function based on System time or equivalent? I basically am generating a few graphs and I would like to see each graph for say 2mins before moving on to the next one? I can always have an empty for-loop I guess but is there a better way? Thanks, S

Hi Group, I often need to print out data frames with results of analysis into a neat little image to copy and paste into documents. I need apply formatting like bold, currency signs, number formats, header shading etc. I currently output the data into csv and format using good old excel. Any suggestions if there are packages to help with such activities (to some level of basic functionality). I

I'm unable to find the OR operator like other language .. any suggestions? I want to do If (condition1 OR condition 2){ do something } Thanks for answering this elementary question. [[alternative HTML version deleted]]

Dear R-Group, I am looking for suggestions for the "best" IDE for R. Best is obviously subjective but I need just the basic features that should function well (and I looked through the threads already). - Proper integration with R 2.11.1 - Good key shortcuts ... similar to the R Gui - Manageability of Projects, etc. - Neat formatting features I tried Revolution R but it seems huge in

Hello Group, I need a modification in the data.table example to get my intended result shown below ... is there a more simple way! dt <- data.table(A = rep(1:3, each=4), B = rep(1:4, each=3), C = rep(1:2, 6)) dt[, transform(.SD,D=mean(A)), by="B"] The result I want is below ... which is probably long winded! data.table(unique(as.data.frame(dt[, transform(.SD,D=mean(A)),

Hello,   I tried to use a variable to refer colname, but I got error, could anyone give me advice?   >df=data.frame(cbind(AB=1:3,AC=3:5)) > df$AC [1] 3 4 5 > df$paste("A","C",sep="") Error: attempt to apply non-function thanks Jian   [[alternative HTML version deleted]]

I am trying to find the function where I can search for a pattern in a text string (I thought I could use grep for this but no :(). > x [1] "abcdefghijkl" I want to find the positions (i.e. equivalent of nchar) for "cd" and in case there are multiple hits .. then the results as a array Thank you.

I need to transpose the following input dataset into an output dataset like below Input Date TICKER Price 11/10/2010 A 0.991642 11/10/2010 B 0.475023 11/10/2010 C 0.218642 11/10/2010 D 0.365135 12/10/2010 A 0.687873 12/10/2010 B 0.47006 12/10/2010 C 0.533542 12/10/2010 D 0.812439 13/10/2010 A 0.210848 13/10/2010 B 0.699799 13/10/2010 C

Dear Group, I am having a function that I am running in a loop that generated two results for each loop The result1 is a zoo object The result2 is a data frame Now I want to put both of them in a list or some structure ... that I can access or output to a file after the loop is done. For e.g. for (i in 1:20){ niceFunction(x[i],i) } niceFunction (x,i) { result1 = someOperations() #zoo

Dear Group, Is there some way for me to package a few lines of R-code as exe and have it running in the background? (unable to find info in the archives) Even better if I can package it as an installation and send to my team who do not have any background in programming / R? If they can install and run the exe ... it would suffice. Thanks, S

Dear R-group, I have some noise in my text file (coding issues!) ... I imported a 200 MB text file using readlines Used grep to find the lines with the error? What is the easiest way to drop those lines? I plan to write back the "cleaned" data set to my base file. Thanks.

Dear Group, Why does write.csv modify the date format when it write to a file. I have the following variable Param_Dat: dput(Param_Dat) structure(list(Last_Successful_Run = structure(1L, .Label = "30/10/2010", class = "factor")), .Names = "Last_Successful_Run", class = "data.frame", row.names = c(NA, -1L)) When I do:

Hi Group, I am having a strange problem for this simple task. I am using read.table to read a plan 3 column CSV file . the file is getting read . But the first column has datetime in the csv file in the following format: 20110221.114041 But this is being read as 20110221 only . the time portion (decimal is missing) in the data frame Any idea why? Thanks, Santosh

Hello Group, This is an open-ended question. Quite fascinated by the things I can do and the control I have on my activities since I started using R. I basically have been using this for analytical related work off my desktop. My experience has been quite good and most issues where I need to investigate and solve are typical items more related to data errors, format corruption, etc... not

My parallel code is running slower than my non-parallel code! Can someone pls advise what am I doing wrong here? t and tTA are simple matrices of equal dimensions. #NON PARALLEL CODE nCols=ncol(t) nRows=nrow(t) tTA = matrix(nrow=nRows,ncol=nCols) require(TTR) system.time( for (i in 1:nCols) { x = t[,i] xROC = ROC(x) tTA[,i]=xROC } ) user system elapsed 123.24 0.07 123.47 #