similar to: Welcome to the "R-help" mailing list

Displaying 20 results from an estimated 600 matches similar to: "Welcome to the "R-help" mailing list"

2010 Dec 01
0
thank you so much
Hi thereI appreciate for your reply.I am running into another problem now, the following is my date (example)2000-1-4 -0.0383447182000-1-5 0.0019222252000-1-6 0.0009557022000-1-7 0.0270903842000-1-10 0.0111899662000-1-11 -0.0130625692000-1-12 -0.0043863312000-1-13 0.0121696632000-1-14 0.0106713212000-1-18 -0.0068320652000-1-19 0.0005222872000-1-20
2005 Dec 16
10
Associative arrays
I just started playing with rails this week and am working on porting our existing website to rails in our navigation we have a list that has the days of the week that link to the articles for those days. this seems to be working when I had it in the template it would give me the array I was looking for so I decided to move it to the helper so that I could use it on all my templates.
2007 Mar 07
2
No years() function?
Hi, I'm trying to aggregate date values using the aggregate function. For example: aggregate(data,by=list(weekdays(LM),months(LM)),FUN=length) I would also like to aggregate by year but there seems to be no years() function. Should there be one? Is there any alternative choice? Also, a hours() function would be great. Any tip on this? Thanks in advance! S?rgio Nunes
2010 Mar 12
6
Randomly sampling subsets of dataframe variable
Fellow R users, I am stumped on what would seem to be something fairly simple. I have a dataframe that has a variable named 'WEEK' that takes the numbers 1:26 (26 week time-period) with each number repeated five times consecutively (once for each weekday, Monday through Friday). Ex. 111112222233333.....2626262626. I would like to randomly extract two weekdays per five day week for
2008 Sep 11
5
How to obtain a sequence of dates consisting of only weekdays
Dear R-users, How do I obtain a sequence of dates consisting of only weekdays without the weekends in R? In S, I can do the following: timeSeq(from="12/17/2007", to="8/25/2008", by="weekdays") I tried using looking at timeSequence (fSeries package) and seq.Date (base package) but I do not know if I can specify "weekdays" rather than "day".
2010 Oct 04
2
Generating weekdays only
Dear all, can anyone please tell me how to generate a sequence of days continuously, however without considering weekends i.e. Saturday and Sunday? I am aware of following code: > seq(as.Date("2010-01-01"), as.Date("2010-02-01"), by="1 day")  [1] "2010-01-01" "2010-01-02" "2010-01-03" "2010-01-04" "2010-01-05"
2008 Dec 12
3
loop with dates
Hello, I am trying to do a loop with dates, but when I try to use the index is not a date. Fcorte <- as.Date('2008/11/30',format = "%Y/%m/%d") fini <- Fcorte + 1 ffin <- seq(fini,by='months',length=2)[2] - 1 for (i in seq(fini,to = ffin, by='days')) print (weekdays(i)) # i doesn't a date How can I do a loop with dates and get the
2010 May 17
6
Change order of columns in table?
I'm an R noob and have a (maybe) stupid question... I have a table where I have the weekdays and a number for each weekday of entries: Thats what the table looks like... Now I want to have an pie3D plot of this, but obviously the order of the weekdays are not as one would expect... Friday Monday Saturday Sunday Thursday Tuesday Wednesday 119 173 80
2006 Jun 23
3
Problems with weekday extraction from zoo objects
Hi Folks! I'm struggling with dates - but enough about my personal life..... I have two daily time series files. In one (x) the date format is Y/m/d and the other (y) is d/m/y. I used read.zoo on both and they read into R with no problem. Then I use: weekdays(as.Date(x$DATE)) and get what I expect - all the days of the week in my data set. When I use:
2002 Feb 22
1
Weekdays
Hello, I'm trying to write a function that returns the number of weekdays between a vector of start dates and a vector of end dates. Subtracting the 2 times the number of whole weeks is the easy part and works if the number of days is a multiple of 7. However, the number of weekend days in the tail is a little harder. It depends on both the start date of the tail and the number of days in
2017 Jun 05
2
months not working with local language (weekdays does)
Hi, I want to reporte some strange behaviour with the "months" function, from base R. When using "months" to extract months from a date column, I'm getting the months in english, when I was expecting months in spanish. When using "weekdays" to extract days of week from a date column, I'm getting the the days in spanish (as expected). My understanding is
2012 May 11
1
summary for weekdays()
Hi all, probably really simple: I seem to be lacking some understanding for the character class: I have a bunch of dates in a dataframe and I want to add a string variable with the weekday for each date. If I use something like mydata$day <- weekdays (mydata$date), I can create subsets for each weekday (eg mydata=="Monday"), but summary (mydata$day) doesn't count the instances for
2007 Dec 13
1
counting weekday in a month in R
Hi, I am trying to count weekday of the month using R. For example, 1/4/2001 is the 4th weekday of Jan, and 1/5/2001 is the 5th weekday of the month, and 1/8/2001 is the 6th weekday of the month, etc. I get as far as extracting the weekdays from a sequence of dates (see below). But I have not yet figured out a fast way of counting without using a For Loop. Does anyone know how to do such counting
2017 Jun 05
2
months not working with local language (weekdays does)
For what it's worth, I tried setting my Region | Formats setting to Spanish (Peru) in Windows 10 Control Panel, and got Spanish weekday and month results. I believe on Windows we use the Microsoft C strftime function to produce these strings, with the %A (for weekday) or %B (for month) formats. So this question probably needs to be addressed to Microsoft. Duncan Murdoch On 05/06/2017
2007 Jun 19
2
names over names
Hello, I wonder if it's possible to put names above column names. Do you know if it's possible? thanks. ___________________________________________________________________________ [[alternative HTML version deleted]]
2011 Aug 30
3
having trouble extracting week from chron object
Running R 2.13.1 on Windows XP. I would like to get week of the year (1-52) for each date. library(chron) dts <- dates(c("02/27/92", "02/27/92", "01/14/92","02/28/92", "02/01/92")) dts dts.chron <- as.chron(dts) dts.chron class(dts.chron) # all of these component extractions work: months(dts.chron) weekdays(dts.chron) years(dts.chron)
2017 Jun 05
0
months not working with local language (weekdays does)
Hello, This doesn't answer the question, but in portuguese it works as expected. > x <- as.Date("2017-06-05") > months(x) [1] "junho" > weekdays(x) [1] "segunda-feira" > sessionInfo() R version 3.4.0 (2017-04-21) Platform: x86_64-w64-mingw32/x64 (64-bit) Running under: Windows 7 x64 (build 7601) Service Pack 1 Matrix products: default
2011 Mar 09
2
Complex sampling?
R users, I am trying to generate a randomized weekday survey schedule that ensures even coverage of weekdays in the sample, where the distribution of variable DOW is random with respect to WEEK. To accomplish this I need to randomly sample without replacement two weekdays per week for each of 27 weeks (only 5 are shown). However, I need to sample from a sequence (3:7) that needs to be
2011 May 28
1
How to do operations on zoo/xts objects with Monthly and Daily periodicities
Is there an elegant way to do operations (+/-/*/ / ) on zoo/xts objects when one serie is monthly (end of month) and the other daily (weekdays only) - typically a monthly economic indicator and a stock index price? Thanks, TDB -- View this message in context: http://r.789695.n4.nabble.com/How-to-do-operations-on-zoo-xts-objects-with-Monthly-and-Daily-periodicities-tp3558081p3558081.html
2017 Jun 05
0
months not working with local language (weekdays does)
Thank you Duncan and Rui for your time and interest in this issue. Maybe it is a problem with Windows 7 and Spanish, and not Windows 10. Let's wait for someone with the same enviroment, before assuming it's a problem with my PC/configuration. 2017-06-05 14:37 GMT-05:00 Duncan Murdoch <murdoch.duncan at gmail.com>: > For what it's worth, I tried setting my Region