similar to: '=' vs '<-'

Hello group, I Just joined the group and this is the first message to this group. I am facing a problem while configuring mysql backend to samba. I am using samba 2.2.7, mysql 5.0, pam-mysql-0.5 and RH9. Is it possible to set mysql backend for samba2.2.7? Pls explain the way to configure mysql to samba as backend. Regards Krishnam. __________________________________________________ Do You

Hi, I've the following kind of data Time Country Values 2010Q1 India 5 2010Q2 India 7 2010Q3 India 5 2010Q4 India 9 2010Q1 China 10 2010Q2

Dear R users: I want to convert some character vectors into numeric vectors. > head(price) [1] "15450 EUR" "7900 EUR" "13800 EUR" "3990 EUR" "4500 EUR" [6] "4250 EUR" >head(mileage) [1] "21000?km" "119000?km" "36600?km" "92000?km" "140200?km" [6] "90000?km" in

Dear R users: I encountered difficulties in michaelis-menten equation. I found that when I use right model definiens, I got wrong Km vlaue, and I got right Km value when i use wrong model definiens. The value of Vd and Vmax are correct in these two models. #-----right model definiens-------- PKindex<-data.frame(time=c(0,1,2,4,6,8,10,12,16,20,24),

I'm testing R version 2.7.0 on windows and there seems to be a compatibility issue with objects that were created by "approxfun" in older versions. As long as the objects were created in version 2.7.0 things work ok, but calling the interpolated functions from R version 2.0.1 causes this error: Error in .C("R_approx", as.double(x), as.double(y), as.integer(n), xout =

I am new to the world of R/programming so this may be a really easy question. I thank you for your patience and help in advance I would like the characters km^2 to be displayed on the plot subtitle as km squared - two as a superscript. I would also like to have the numbers from the data set for longitude and latitude to be rounded to four decimal places. Thank you. plot (

Dear R-help list, I have a problem with the tick marks of a Kaplan-Meier survival plot. Here is a sample: follow.up<-c(10,20,30,40,50,60,70,80,90,100) #months dead<-c(1,1,1,0,1,1,0,0,0,0) KM <-survfit(Surv(follow.up, dead)) plot(KM) The result is a nice plot. However, our research group thinks it may be a better idea to place the ticks to the years on the time scale, i.e. 0, 12, 24, 36

DeaR comRades: I have a 2D spatial binomial process as shown in the data and code below. I am plotting the number of trials and the number of successes in the spatial binomial experiments and would like to draw the spatial cells were the trials and successes were counted, i.e. a partial grid in the plot only for those cells where there is a number. The cells are 2x2 km cells. The count of Trials

Buenas, Como pudeo calcular el tiempo de vida? Os cuento, tengo una serie de cuchillas y quiero ver el consumo de las mismas y he pensado en hacer un estudio por tiempo de vida. No se como hacerlo con R Gracias Jesús [[alternative HTML version deleted]]

Hi, I am wondering if anyone can explain to me if cumulative incidence (CI) is just "1 minus kaplan-Meier survival"? Under what circumstance, you should use cumulative incidence vs KM survival? If the relationship is just CI = 1-survival, then what difference it makes to use one vs. the other? And in R how I can draw a cumulative incidence plot. I know I can make a Kaplan-Meier

Los datos no son de desgaste de cuchilla, sino de consumo de las mismas. Por ello tengo los datos de la siguiente forma: Unidades cambiadas Fecha En unidades cambiadas, suele ser una y en fecha el dia que se hizo el cmabio. Con eso no se muy bien como estructurar los datos para hacer el análisis. Gracias Jesús > Date: Mon, 7 Dec 2015 16:27:18 +0100 > From: griera en yandex.com

I am trying to get the following line in a plot margin using mtext: 100% Area = 120.000 km^2 Where I intend that "100% Area =" is text, 120.000 is a number that varies according to different data, and km^2 should be a neat km-with-superscript-2. The expression function fails me, since it apparently cannot coerce an expression when a variable is involved. In the R help file there is

Hello again, I'm able to run KoolMoves 6.0 (KM) under Wine but it's missing some functionality. KM is a Flash authoring tool and the missing functionality is mostly the ability to use the internal preview functions. Internal preview requires a browser and a flash plug-in, both of which I have. I also tried KM under CrossOver Office and it works 100%, so I'm hoping I can tweak

Hey, I am just starting to learn R now and I typed in this simple survival program: library(survival) t <- c(10,13,18,19,23,30,36,38,54,56,59,75,93,97,104,107,107,107) c <- c(1,0,0,1,0,1,1,0,0,0,1,1,1,1,0,1,0,0) data <- Surv(t,c) km <- survfit(data) summary(km) Call: survfit(formula = data) but everytime I run it I get this error: Error in

Dear All, I am trying to put 10^-8 st km^-2day^-1 on x-axis of my plot. I tried using : ylab = expression(paste("st / ", plain(km)^2, " / day")) to see if I can at least get the unit before thinking about the power of 10 (10^-8). However, ylab = expression(paste("st / ", plain(km)^2, " / day")) didn't give the result I expected. The power 2 in km was

To enhance my understanding, and that of my students, I have a question about cox.zph in the survival package. If I have correctly gleaned the high-level point from the 1994 Biometrika paper of Grambsch and Therneau, it looks to me like cox.zph provides a mechanism to test for a simple trend in plots of a function of time, g(t) versus the scaled schoenfeld residuals and it also provides some

Hello, I am doing a simple linear regression analysis that includes few variables. I am using a bootstrap analysis to obtain the variation of my variables to replacement. I am trying to obtain the coefficients 95% confidence interval from the bootstrap procedure. Here is my script for the bootstrap: N = length (data_Pb[,1]) B = 10000 stor.r2 = rep(0,B) stor.r2 = rep(0,B) stor.inter =

Hi all, I'm plotting to get the intersection value of three curves. Defining the x-axis as dsm, the following code works; dsm = c(800,600,NA,525,NA,450,400,NA,NA,NA,0) s3 = seq(0.05,1.05,0.1) plot(dsm,s3,col="blue",las=1,ylab="fraction",xlab="distance (km)") fc <- function(x,a,b){a*exp(-b*x)} fm <- nls(s3~fc(dsm,a,b),start=c(a=1,b=0)) co <- coef(fm)

I will get back to the mailing list.?? But to answer your questions, yes the IP addresses and interface names are as expected (as before) with the new MAC/HW addresses.? I have someone else looking into it because when we plugged in the cable the light on the card did not light up.?? when we connect the pair server to another separate server it did.? Once the server is back up I will try these

Dear All, I have a data, suppose it is an N*M matrix data. All I want is to classify it into, let see, 3 classes. Which method(s) do you think is(are) appropriate for this purpose? Any reference will be welcome! Thanks! Best, Baoqiang Cao