Displaying 20 results from an estimated 500 matches similar to: "multi-level cox ph with time-dependent covariates"
2013 May 07
4
how to calculate the mean in a period of time?
Hi,
Your question is still not clear.
May be this helps:
dat2<- read.table(text="
patient_id????? t???????? scores
1????????????????????? 0??????????????? 1.6
1????????????????????? 1??????????????? 2.6
1????????????????????? 2???????????????? 2.2
1????????????????????? 3???????????????? 1.8
2????????????????????? 0????????????????? 2.3
2?????????????????????? 2???????????????? 2.5
2010 Sep 07
2
Plotting longitudinal data
Hello,
Hope that someone could help me plotting longitudinal data below:
7213 3333330001 0.8300 13.05.09 1
1 3333330001 0.8700 09.02.05 NULL
4797 3333330001 0.7700 21.03.07 NULL
2399 3333330001 0.7800 12.04.06 NULL
2400 3333330002 NULL 27.03.06 NULL
7230 3333330002 0.8200 14.05.09 0
2 3333330002 0.8400 09.02.05 NULL
4798 3333330002 0.8700 20.03.07 0
4799 3333330003 0.9000 20.03.07 13
2401
2010 Jun 29
3
merging/intersecting 2 data frames
Dear R People:
I have two data frames, a.df and b.df as seen here:
> a.df[1:10,]
DATE GENDER PATIENT_ID AGE SYNDROME
1 4/16/2009 F 23686 45 RASH ON BODY
2 4/16/2009 F 13840 35 CANT URINATE
3 4/16/2009 M 12895 30 BLURRED VISION
4 4/16/2009 M 18375 33 UNABLE TO VOID
5 4/16/2009 M 2237 44
2007 Feb 20
1
Reshape (pivot) question
Hi R-users,
I have a data set like this (first ten rows):
id patient_id date code class eala ID1564262 1562 6.4.2006 12:00 5555 1
NA ID1564262 1562 6.4.2006 12:00 5555 1 NA ID1564264 1365 14.2.2006 14:35
5555 1 50 ID1564265 1342 7.4.2006 14:30 2222 2 50 ID1564266 1648 7.4.200614:30
2222 2 50 ID1564267 1263 10.2.2006 15:45 2222 2 10 ID1564267 1263
10.2.200615:45
3333 3 10 ID1564269 5646
2007 Jun 26
1
A really simple data manipulation example
In response to those who asked for a better explanation of what the
Vilno software does, here's a simple example that gives some idea of
what it does.
LABRESULTS is a dataset with multiple rows per patient , with lab
sodium measurements. It has columns: PATIENT_ID, VISIT_NUM, and
SODIUM.
DEMO is a dataset with one row per patient, with demographic data.
It has columns: PATIENT_ID, GENDER.
2006 Aug 17
1
How to sort child table on fields in the associated parent
For an Xray file system patients have folders and folders have studies.
That is:
patients folders studies
id id id
name patient_id folder_id
... label type
... ...
The list of studies with their associated folder and patient might look
like this:
name folder_label study_type
2010 Jan 21
2
will_paginate ?
Does anyone have experience with will_paginate?
I''m trying to use it with acts_as_ferret.
routes.rb
...
map.search ''/search'', :controller => ''notes'', :action => ''search''
notes.rb
...
acts_as_ferret :fields => [ ''body'' ]
notes_controller.rb
...
def search
if params[ :query ]
@query = params[
2008 Jul 09
1
Need basic PPPoE startup help
I need basic PPPoE startup help.
adsl-start DID bring up my PPPoE link (ppp0) to my ISP over eth0 via the
DSL modem/bridge. My IPv4 CIDR block is routing and Shorewall is doing
the firewalling.
But shorewall has to be started after ppp0 is up and working. For now
this means running shorewall restart (or start?). Shorewall 4.2 will
have a way to restart shorewall without recompiling, I
2007 Sep 13
2
beginner's questions ... sorry
I have 316 files. Each file represents a patient's breathing track
(respiratory signal recorded for a variable number of cycles). All files
have the same are made up of a header followed by a variable number of
records.
Each record contains 7 comma separated fields.
The patient ID is recorder in the header which is stripped off when reading
the file into a R data.frame.
Since I need to keep
2013 Apr 12
5
how to change the date into an interval of date?
Hi,
I am not sure I understand your question correctly.
dat1<- read.table(text="
id??????????? responsed_at???????????????? number_of_connection????????????????? scores
1????????????????? 12-01-2010?????????????????????????????????? 1????????????????????????????????????????????? 2
1????????????????? 15-02-2010??????????????????????????????????
2013 May 22
0
calcul of the mean in a period of time
Hi,
I guess you meant this:
dat2<- read.table(text="
patient_id????? t???????? scores
1????????????????????? 0??????????????? 1.6
1????????????????????? 1??????????????? 2.6
1????????????????????? 2???????????????? 2.2
1????????????????????? 3???????????????? 1.8
2????????????????????? 0????????????????? 2.3
2?????????????????????? 2???????????????? 2.5
2?????????????????????
2006 Jul 17
1
Getting rid of for loops
Hello R-users!
I have a style question. I know that for loops are somewhat frowned upon in
R, and I was trying to figure out a nice way to do something without using
loops, but figured that i could get it done quickly using them. I am now
looking to see what kind of tricks I can use to make this code a bit more
aesthetically appealing to other R users (and learn something about R along
the
2013 Jun 04
0
choose the lines2
HI,
You can do this:
dat1<- read.csv("dat7.csv",header=TRUE,stringsAsFactors=FALSE,sep="\t")
dat.bru<- dat1[!is.na(dat1$evnmt_brutal),]
fun2<- function(dat){?
????? lst1<- split(dat,dat$patient_id)
??? lst2<- lapply(lst1,function(x) x[cumsum(x$evnmt_brutal==0)>0,])
??? lst3<- lapply(lst2,function(x) x[!(all(x$evnmt_brutal==1)|all(x$evnmt_brutal==0)),])
2013 Jun 04
0
choose the lines2
Hi,
May be this helps:
dat1<- read.csv("dat7.csv",header=TRUE,stringsAsFactors=FALSE,sep="\t")
dat.bru<- dat1[!is.na(dat1$evnmt_brutal),]
fun2<- function(dat){??
????? lst1<- split(dat,dat$patient_id)
??? lst2<- lapply(lst1,function(x) x[cumsum(x$evnmt_brutal==0)>0,])
??? lst3<- lapply(lst2,function(x) x[!(all(x$evnmt_brutal==1)|all(x$evnmt_brutal==0)),])
2005 Feb 10
5
sample
I am trying to sample a subset from a matrix using sample.
The size of the matrix is 20X 1532. It works fine with this,
but when I transpose the matrix and try to sample it, it returns
null.
pick.set<-sample(tissue.exp.t,5,replace=FALSE,prob=NULL)
Is there something that I am missing here ?
Thanks ../Murli
2008 Sep 14
2
Help please! How to code a mixed-model with 2 within-subject factors using lme or lmer?
Hello,
I'm using aov() to analyse changes in brain volume between males and
females. For every subject (there are 331 in total) I have 8 volume
measurements (4 different brain lobes and 2 different tissues
(grey/white matter)). The data looks like this:
Subject Sex Lobe Tissue Volume
subect1 1 F g 262374
subect1 1 F w 173758
subect1 1 O g 67155
subect1 1 O w 30067
subect1 1 P g 117981
2007 Feb 14
1
nested model: lme, aov and LSMeans
I'm working with a nested model (mixed).
I have four factors: Patients, Tissue, sex, and tissue_stage.
Totally I have 10 patients, for each patient, there are 2 tissues
(Cancer vs. Normal).
I think Tissue and sex are fixed. Patient is nested in sex,Tissue is
nested in patient, and tissue_stage is nested in Tissue.
I tried aov and lme as the following,
> aov(gene ~ tissue + gender +
2011 Sep 20
1
A question regarding random effects in 'aov' function
Hi,
I am doing an analysis to see if these is tissue specific effects on the
gene expression data .
Our data were collected from 6 different labs (batch effects). lab 1 has
tissue type 1 and tissue type 2, lab 2 has tissue 3, 4,5,6. The other labs
has one tissue type each. The 'sample' data is as below:
2008 Sep 13
2
moving from aov() to lmer()
Hello,
I've used this command to analyse changes in brain volume:
mod1<-aov(Volume~Sex*Lobe*Tissue+Error(Subject/(Lobe*Tissue)),data.vslt)
I'm comparing males/females. For every subject I have 8 volume measurements
(4 different brain lobes and 2 different tissues (grey/white matter)).
As aov() provides only type I anovas, I would like to use lmer() with type
II, however, I have
2010 Apr 23
2
Problem with parsing a dataset - help earnestly sought
Dear fellow R-help members,
I hope to seek your advice on how to parse/manage a dataset with hundreds of
columns. Two examples of these columns, 'cancer.problems', and
'neuro.problems' are depicted below. Essentially, I need to parse this into
a useful dataset, and unfortunately, I am not familiar with perl or any such
language.
data <- data.frame(id=c(1:10))