similar to: extracting random effects from model formula

Displaying 20 results from an estimated 1000 matches similar to: "extracting random effects from model formula"

2008 Feb 15
2
help on using try() to catch an error
Dear R Users, I have the following glm, which I am running several times in a loop (I am not including the full code): reduced_model <- NULL; full_model <- NULL; reduced_model <- try(glm.fit(X4,n,family=poisson(link="log"))) full_model <- try(glm.fit(X5,n,family=poisson(link="log"))); On some occasions, an error is produced, which is why I have attempted to work
2012 Aug 04
3
Questionnaire Analysis virtually without continuous Variables
Hello! I am doing an analysis on a questionnaire of hunters taken in 4 different districts of some mysterious foreign country. The aim of the study was to gather info on the factors that determine the hunting success of a peculiarly beautiful bird in that area. All variables are factors, i.e. they are variables such as "Use of Guns - yes / no", "Use of Dogs - yes / no" and
2011 Mar 07
4
png inside loop
hello list! I'm sorry, I just stumbled over this strange behaviour (at least I am not able to explain the behaviour, therefore I assume it to be a strange behaviour): attach(water) # I know, this is not recommended names(water[3:10]) [1] "temp" "pH" "DO" "BOD" "COD" "no3" "no2" "po4" for (i in
2008 Feb 20
1
debugging a try() statement
Dear R Users, I implemented a try() statement that looks like: <- function(index) { reduced_model <- try(glm.fit(X4,n,family=poisson(link="log"))) full_model <- try(glm.fit(X5,n,family=poisson(link="log"))) if (inherits(reduced_model,"try-error") || inherits(full_model,"try-error")) return(NA) else { p <-
2010 May 17
3
applying quantile to a list using values of another object as probs
Hi r-users, I have a matrix B and a list of 3x3 matrices (mylist). I want to calculate the quantiles in the list using each of the value of B as probabilities. The codes I wrote are: B <- matrix (runif(12, 0, 1), 3, 4) mylist <- lapply(mylist, function(x) {matrix (rnorm(9), 3, 3)}) for (i in 1:length(B)) { quant <- lapply (mylist, quantile, probs=B[i]) } But quant
2010 Nov 26
2
get list index
Hi R-users, I have a list mylist <- list(c(0.79, 0.92, 0.91, 0.86, 0.96, 0.96, 0.95, 0.94, 0.99), c(0.28, 0.45, 0.59, 0.69, 0.80, 0.87, 0.95, 0.94, 0.98), c(0.29, 0.39, 0.59, 0.69, 0.68, 0.80, 0.93, 0.95, 0.98)) Is there a way to find the index of the list element that contains the lowest value among all the other elements? As the lowest value in each element is the first, the
2011 May 08
1
Hosmer-Lemeshow 'goodness of fit'
I'm trying to do a Hosmer-Lemeshow 'goodness of fit' test on my logistic regression model. I found some code here: http://sas-and-r.blogspot.com/2010/09/example-87-hosmer-and-lemeshow-goodness.html The R code is above is a little complicated for me but I'm having trouble with my answer: Hosmer-Lemeshow: p=0.6163585 le Cessie and Houwelingen test (Design library): p=0.2843620
2010 Jul 13
2
modifying vector elements
Hello R-users, I have a very large vector (a) containing elements consisting of numbers and letters, this is the i.e. a [1] "1.11.2a" "1.11.2d" "1.11.2e" "1.11.2f" "1.11.2x1" "1.11.2x1b" [7] "1.11.2x2" "1.11.2x2a" "1.11.2x2b" "1.11.2x3" "1.11.2x4"
2008 Jan 25
1
increasing speed for permutations of glm
Dear R Programmers, I am trying to run a Poisson regression on all pairs of variables in a data set and obtain the permutation distribution. The number of pairs is around 100000. It seems my code will take weeks to run, unless I try something else. Could you give me any suggestions on how to improve the speed of the code below, or any general suggestions on how I may accomplish this task. Thanks
2010 Sep 27
3
name ONLY one column
Hi R-users I can not change the name of one column only of my matrix. my_matrix <- matrix (1:12,ncol=3) colnames(my_matrix)[1] <- 'myname' Error in dimnames(x) <- dn : length of 'dimnames' [2] not equal to array extent thank you for your help Lorenzo [[alternative HTML version deleted]]
2011 Aug 25
2
string manipulation
I R-users, I am trying to find the way to manipulate a character string to select a 4 digit number after some specific word/s. Example: mytext <- "I do not want the first number 1234, but the second number 5678" Is there any function that allows you to select a certain number of digits (in this case 5678) after a particular word/s (e.g., second number) Thank you for your help
2010 Aug 11
2
storing the results of an apply call
Hi R-users, I have a function (myfun) that I want to apply to the rows of a matrix. Basically, "myfun" takes the values from the matrix ("exp.des"), which represent the different combinations of my experimental design, and pass them as arguments to some other functions (fun1 and fun2). As I want to replicate the results of fun1 and fun2 a certain number of time (e.g. 5), I
2011 Feb 27
3
accessing variables inside a function, inside a loop
dear list! I KNOW this has been answered a million times before. But, as some might remember from their "freelance" times as a statistic consultant, sometimes you're blinded by the facts. I KNOW I have seen this problem solved, but due to the mental blockade i have been suffering from the last 3 hours, I can neither find the answer on the mailing list nor on google. I wrote a
2012 Aug 10
2
creating a contingency table from a data.frame automatically (NOT BY HAND)
Hello there! I am still struggling with a binomial response over all categorical variables (some of them with 3 levels, most with 2 levels). After initial struggles with glm's (struggle coming from the data, not the actual analysis) I have decided to prefer contingency tables. I have my data such as: response:
2010 Nov 03
2
memory allocation problem
Hi R users I am trying to run a non linear parameter optimization using the function optim() and I have problems regarding memory allocation. My data are in a dataframe with 9 columns. There are 656100 rows. >head(org_results) comb.id p H1 H2 Range Rep no.steps dist aver.hab.amount 1 1 0.1 0 0 1 100 0 0.2528321
2011 Feb 02
2
automatic coercion to character
Hi R users I am wondering how I can avoid automatic coercion of my numeric vector elements to character init <- c(age='N', R=as.numeric(0.5), S=as.numeric(0.8)) I have used as.numeric() but it does not seem to work Thank you Lorenzo [[alternative HTML version deleted]]
2010 Oct 05
2
accessing elements located after $ symbol
Hi R-users I am having troubles accessing elements after the $ symbol. Reproducible example: >test <- data.frame (first=1:10, second=11:20, third=21:30) >test$first #this works fine but when I try >interest <- "first" >test$interest # does not seem to work Could you tell me why that happens and show how to do instead? Thanks so much Lorenzo
2011 Feb 02
2
slightly off topic...
i'm sorry to bother but... sometimes theres an attachment in the posts on the list, a single file called: Teil 1.2 whys that? i dont want to open it to find out, as i have used computers before ;) therefore i suspect it to be either some security problem OR to be the alternative HTML version that is claimed to have been deleted. any light-shedding would be appreciated!
2011 Apr 05
1
do not execute newline command
Hi R-users, To automate the creation of scripts, I converted the code (example below) into a character string and wrote the object to a file: Repeat <- " myvec <- c(1:12) cat('vector= ', myvec, '\n') " write (Repeat, 'yourpath/test.R') the problem is that one line of the code is a "cat" command. In the output file (i.e. test.R), the newline
2011 May 05
1
lapply, if statement and concatenating to a list
Hi R users I was wondering on how to use lapply & co when the applied function has a conditional statement and the output is a 'growing' object. See example below: list1 <- list('A','B','C') list2 <- c() myfun <- function(x,list2) { one_elem <- x cat('one_elem= ', one_elem, '\n') random <- sample(1:2,1) show(random)