similar to: group means of multi-way table?

Dear list colleagues, I'm trying to come up with a test question for undergraduates to illustrate comparison of means from a complex survey design. The data for the example looks roughly like this: mytest<-data.frame(harper=rnorm(500, mean=60, sd=1), party=sample(c("BQ", "NDP", "Conservative", "Liberal", "None", NA), size=500,

neptune# ps -M vmcore.1 -N kernel.debug -axl | grep inode | wc -l 961 and I have a vmcore to work on here !! :) (kgdb) proc 99643 (kgdb) bt #0 mi_switch () at machine/globals.h:119 #1 0x8014a1f9 in tsleep (ident=0x8a4ef600, priority=8, wmesg=0x80263d4a "inode", timo=0) at /usr/src/sys/kern/kern_synch.c:479 #2 0x80141507 in acquire (lkp=0x8a4ef600, extflags=16777280,

Dear colleagues, I'm working with the 2008 Canada Election Studies (http://www.queensu.ca/cora/_files/_CES/CES2008.sav.zip), trying to construct a weighted national sample using the survey package. Three weights are included in the national survey (a household weight, a provincial weight and a national weight which is a product of the first two). In the following code I removed variables with

A stupid question but does anyone know how to express the actual colours used by the main Canadian political parties? I want to do a couple of ggplot2 plots and have lines or rectangles that accurately reflect the party colours. I can probably play around with RColorBrewer or something to figure it out but if some some already has got them it would save me some time especially with the NDP

Dear R users. Recently I wanted to update my R distribution to the current one (R-2.7.1). I am running a Fedora core 8 distirbution. The installation went fine, but when I tried to add some additional packages the majority made an exit with an error. Only a few least demanding (e.g. RColorBrewer) managed to get through the installation process. What happened between the versions 2.6.x and 2.7.x

Dear all, I was wandering what could be wrong with my system (regularly updated Fedora core 8) so that installing packages does not succeed with almost every package. I follow the procedure specified in the help file R-admin section 6.3. This is not a feature new to the current version but happened (to me) in the previous version as well. Additionally R-help html pages try to follow wrong links

Hi, Sorry for the delay. On Tue, 11 Aug 2020 23:52:46 -0400 Laine Stump <laine@redhat.com> wrote: > On 8/10/20 11:23 PM, Ian Wienand wrote: > > Hello, > > > > Firstly THANK YOU for the IPv6 NAT support merged in 6.5. It has been > > almost impossible to get IPv6 into a VM on a laptop that switches > > between wifi and wired (dock) connections, because

Hello: Forgive me, this is surely a simple question but I can't figure it out, having consulted the help archives and "Data Manipulation With R" (Spector). I have a list of 11 data frames with one common variable in each (prov). I'd like to use lapply to go through and recode one particular level of that common variable. I can get the recode to work, but it only returns the

HI All, I have a long data file generated from a minimal pair test that I gave to learners of Arabic before and after a phonetic training regime. For each of thirty some subjects there are 800 rows of data, from each of 400 items at pre and posttest. For each item the subject got correct, there is a 'C' in the column 'Correct'. The line: tapply(ALLDATA$Correct,

Dear colleagues, Could I get some assistance using postForm() to scrape the business names and addresses at this website: http://www.brantford.ca/business/LocalBusinessCommunity/Pages/BusinessDirectorySearch.aspx I've read through (http://www.omegahat.org/RCurl/RCurlJSS.pdf) and scoured the web for tutorials, but I can't crack it. I'm aware that this is probably a pretty basic

Hello all, I changed the subject line of the e-mail, because the question I''m posing now is different than the first one. I hope that this is proper etiquette. However, the original chain is included below. I've incorporated bits of both Ethan and Brian's code into the script below, but there's one aspect I can't get my head around. I'm totally new to programming

Dear colleagues, this seems like an easy problem, and I found some suggestions which I've incorporated in the help list, but I can't quite get it right. I want to add a series of years to a second x-axis category label. I generate them with test and test_2 below, format them with some spacing (which is the suggestion I took from the R-list) and concatenate them and then write them with

Dear Colleagues, I have recently installed R Commander on my Mac OS 10.6.8. I'd like to use it for an undergraduate class this year. Everything appears to be working fine, except for one thing. I cannot use Command-tab to cycle from the X11 window in which RCommander is running to any other window open in my workspace. This is particularly important because I cannot cycle to the graphics

Hi there: I'm preparing a report in RStudio 0.96.330 on a Mac OS. I'm running R 2.15.0 I understand from Ross Ihaka's document (http://www.stat.auckland.ac.nz/~stat782/downloads/Sweave-customisation.pdf) that you can modify the line length of Sweave output by a call to options(wdith=x). This works great for me for numeric output, but not for character vectors that I have to print.

-----BEGIN PGP SIGNED MESSAGE----- ============================================================================= FreeBSD-SA-99:04 Security Advisory FreeBSD, Inc. Topic: Coredumps and symbolic links Category: core Module: kernel Announced: 1999-09-15 Affects:

Hello dear R users! I did not find a function which gives information about the number of digits of a value shown by R. Do you know one? I need it to solve the problem (see RFAQ 7.31)that 0.2==0.2+0.1-0.1 FALSE The solution suggested in RFAQ is to use isTRUE(all.equal(0.2,0.2+0.1-0.1)) But if I want to compare inequality: 0.2<=0.2 +0.1-0.1 TRUE but 0.2<=0.2 +0.1-0.1 FALSE bad! but in

. HI there, I'd like to show demonstrate how the chi-squared distribution works, so I've come up with a sample data frame of two categorical variables y<-data.frame(gender=sample(c('Male', 'Female'), size=100000, replace=TRUE, c(0.5, 0.5)), tea=sample(c('Yes', 'No'), size=100000, replace=TRUE, c(0.5, 0.5))) And I'd like to create a list of 100

Dear Colleagues, I have a data set that looks as below. I'd like to count the number of dates in a series of arbitrary ranges (breaks) i.e. not pre-defined breaks such as months, quarters or years. table(format()) produces ideally formatted output, but table() does not appear to accept arbitrary ranges. I also tried converting the dates to numeric and using histogram to try to get the data,

Hello, I'm trying to read in 50 text filess with dates as content to create a list of tables. a is the list of filenames that need to be read in. The following command returns the following error mylist<-lapply(a, read.table(header=TRUE, sep="\n")) Error in read.table(header = TRUE, sep = "\n") : element 1 is empty; the part of the args list of

Hi all: I struggle a lot scraping web data. I still haven't got a handle on the XML package. I'd like to get particular exchange rates from this table: https://raw.github.com/currencybot/open-exchange-rates/master/latest.json This is the code that I'm working with: library(RCurl) library(XML)