similar to: Create Dot Chart

Hello, I have a cohort with approx 1,200 patients at the ages of 30-65 that had their first myocardial infarction during 1992: · They were in a follow up until 2005. · About 400 of them died during this period of time (right censored) · Each one of them had up to 4 mi recurrent events. I am using the semi-parametric model in order to assess the relationship of

Hi All, I have been trying to plot multiple line plots with different colors on one figure. in my example below I was able to plot cat vs num1 as a dot plot connected with lines but was not able to do that for cat vs num2 and I do not know how to add the third plot cat vs num3. below is my code df <- data.frame(cat=1:10, num1=rnorm(10), num2=rnorm(10), num3=rnorm(10)) plot(df$num1,

Hi I would like to normalize my data by one of the variables in long format. My data is like this: > t1<-data.frame(id=rep(1:3,rep(3,3)),dt=rep(1:3,rep(9,3)),var=c('num1','num2','norm'),value=rnorm(27)) > t1 id dt var value 1 1 1 num1 -1.83276256 2 1 1 num2 1.57034303 3 1 1 norm 0.60008563 4 2 1 num1 -0.96893477 5 2 1 num2 0.30423346 6

Hi, I have two accounts with broadvoice. Now, I want to be able to distinguish between them. I though that this would be simple by adding "/EXTEN" at the end of the register statement. For example: register => num1:pass@sip.broadvoice.com/1000 Unfortunately, this is not working. When I call into my box I hear busy tone. My config looks like this: [root@voip asterisk]# cat sip.conf

Hi, I am trying to simultaneously remove duplicate variables from two or more variables in a small R data.frame. I am trying to reproduce the SAS statements from a Proc Sort with Nodupkey for those familiar with SAS. Here's my example data : test <- read.csv("test.csv", sep=",", as.is=TRUE) > test date var1 var2 num1 num2 1 28/01/11 a 1 213 71 2

Hello, I have a list (mode and class are list) in R that is many elements long and of the form: >length(list) [1] 5778 >list[1:4] $ID1 [1] "num1" $ID2 [1] "num2" "num3" $ID3 [1] "num4" $ID4 [1] NA I'd like to convert the $ID2 value to be in one element rather than in two.?? It shows up as c(\"num2\", \"num3\") if I try to use

Dear Users, I have one problem here, I tried many time and even read a few notes on writing function but still..... Can anyone help me on how to simplify Part B (please refer the programming below), so that I don't have to repeat the calculation of "num" and "r" ? Thank you very much..every help is very much appreciated... ## Part A n=1400 m=matrix(c(0,0,0,0),4,1)

hi, running dovecot-0.99.10-rc2 on NetBSD, client is Entourage on MacOS 9.2. sylpheed on NetBSD does not show this behaviour. --snip-- Jun 23 16:28:15 host imap(user): file mail-index.c: line 619 (mail_index_lookup_uid_range): assertion failed: (first_uid > 0 && last_uid > 0) --snap-- any hints? thanks, TOM -------------- next part -------------- A non-text attachment was

Hello! I have asterisk updated from CVS on 31/8/2004 with sample configuration. I have just changed the sip.conf to register asterisk with sip proxy in out intranet. Then I can successfully make call to asterisk and go to demo IVR, but no response to dtmfs. I try to make call from several sip phones: Cisco7960, Ata186, Snom200. All of them send telephone-event in INVITE, but asterisk answers

Description: 'lapply' returns a list of the same length as 'X', each element of which is the result of applying 'FUN' to the corresponding element of 'X'. I expect that when I do > lapply(vec,f) f would be called _once_ for each component of vec. this is not what I see: parse.num <- function (s) { cat("parse.num1\n"); str(s) s

I believe this may be more related to analysis than it is to R, per se. Suppose I have the following function that I wish to integrate: ff <- function(x) pnorm((x - m)/sigma) * dnorm(x, observed, sigma) Then, given the parameters: mu <- 300 sigma <- 50 m <- 250 target <- 200 sigma_i <- 50 I can use the function integrate as: > integrate(ff, lower= -Inf, upper=target)

I have a program, when I write if(num!=NA) it yields an error message. However, if I write if(is.na(num)==FALSE) it works. Why doesn't the first statement work? Thanks, Miao [[alternative HTML version deleted]]

Hi all- I have a dataset (year, month, hour, co2(ppm), num1,num2) [49,] 2006 11 0 383.3709 28 28 [50,] 2006 11 1 383.3709 28 28 [51,] 2006 11 2 383.3709 28 28 [52,] 2006 11 3 383.3709 28 28 [53,] 2006 11 4 383.3709 28 28 [54,] 2006 11 5 383.3709 28 28 [55,] 2006 11 6 383.3709 28 28 [56,] 2006 11 7 383.3709 28 28 [57,] 2006

Hi all, I'm currently working on an R program where I have to access an FTP server to download some of the data I need. However, the people who post up the files I access are at times inconsistent with regards to time posted, if they post at all, etc.... Here's some of the code I use: library(RCurl) url1 = paste("ftp://user:password at a.great.website.com/",

Hola a todos, a ver si me pueden echar una mano que estoy atascado.tengo estas dos tablas: > head (intento1)      codigo     categoria         talla             num1       1                904                400               12       1                904                460               13       1                904                470               44       1                904  

I want to count attributes of IDs: --8<---------------cut here---------------start------------->8--- z <- data.frame(id=c(10,20,10,30,10,20), a1=c("a","b","a","c","b","b"), a2=c("x","y","x","z","z","y"),

Hi! I have data (also in attached file) in the following form: num1 num2 num3 int1 fac1 fac2 cha1 cha2 Date POSIXt 1 1 f q 1900-01-01 1900-01-01 01:01:01 2 1.0 1316666.5 2 a g r z 1900-01-01 01:01:01 3 1.5 1188830.5 3 b h s y 1900-01-01 1900-01-01 01:01:01 4 2.0 1271846.3 4 c i t x 1900-01-01 1900-01-01 01:01:01 5 2.5 829737.4 d j u w 1900-01-01 6 3.0

Hi! I have data (also in attached file) in the following form: num1 num2 num3 int1 fac1 fac2 cha1 cha2 Date POSIXt 1 1 f q 1900-01-01 1900-01-01 01:01:01 2 1.0 1316666.5 2 a g r z 1900-01-01 01:01:01 3 1.5 1188830.5 3 b h s y 1900-01-01 1900-01-01 01:01:01 4 2.0 1271846.3 4 c i t x 1900-01-01 1900-01-01 01:01:01 5 2.5 829737.4 d j u w 1900-01-01 6 3.0

I'm a great fan of read.table(), but this time the data had a lot of cruft. So I used readLines() and editted the char vector to eventually get something like this: " 23.4 1.5 4.2" " 19.1 2.2 4.1" and so on. To get that into a 3 col numeric table, I first just used: writeLines(data,"tempfile")

Hi, when i run the following code i get this massege: "The instruction at 0x######## reference memory at 0x#######, the memory cannot be "read". and then i have to close R. what is the problem and how can i solve it? thanks in advance Avi my code # frailtypack library(frailtypack) cgd.ag <- read.csv("C:/rfiles/RE/cgd.csv") cgd.nfm <-frailtyPenal(Surv(TStart,