similar to: rbind() overwriting data.frame()

Dear List, I am using plot for homework. The x-axis covered from 0 to 80, with 4 intervals. However, the plot only showed 0, 40, 80. 20 and 60 disappeared. Please kindly advise how to show 0, 20, 40, 60, 80 for the axis interval. Thank you. Elaine [[alternative HTML version deleted]]

Hi everybody, I would like to compute the mean for 1 variable between the rows with the same levels. For example, with the dataset below: Factor1 Factor2 Value A X 1 A X 2 A Y 3 A Y 4 B X 5 B X 6 B Y

Hi, I have a list which looks like this... > str(y) List of 10 $ : chr [1:4] "ABCD" "5" "0" "1" $ : chr [1:4] "DEF" "15" "1" "16" $ : chr [1:4] "AAA" "2" "17" "8" $ : chr [1:4] "SSS" "15" "25" "1" $ : chr [1:4] "III"

Hi, I used the command ggplot as follows... p<-ggplot(a,aes(x=a$V1,colour=a$V2,fill=a$V2)) p + geom_density(alpha = 0.2,xlim=c(-10,10),ylim=c(0,0.5)) when I say, dev.print(device=postscript,file="/alpha/dct.pdf") I get Warning message: In grid.Call.graphics("L_polygon", x$x, x$y, list(as.integer(1L:length(x$x)))) : semi-transparency is not supported on this device:

I have a dataset named DM with p1, p2, ...., p9 (9 columns, numerical values) I would like to calculate to multify each pair of columns (p1p2, p1p3,... p1p9, p2p3, p2p4.... p8p9) and assign them in p1p2, p1p3,... p1p9, p2p3, p2p4.... p8p9 In SAS, l=0; p_int_sum=0; do i=1 to 8; do j=(i+1) to 9; l=l+1; p{i}p{j}=p{i}*p{j}; end; end; I would like to know how to assign them in R I tried for

Hey all, I am writing a function in which I will have a matrix of 4 columns and a variable amount of rows. The first to columns will always contain be of the Character type, the third and fourth columns can be a variation of data types, usually characters and integers, but sometimes lists or matrices. At one point the code makes, for each row, a copy of that row, then it makes some adjustments

Hi, I am trying to do a multiple regression on the dataset "Hdma", available in the Ecdat package. The data looks like this: > str(Hdma) 'data.frame': 2381 obs. of 13 variables: $ dir : num 0.221 0.265 0.372 0.32 0.36 ... $ hir : num 0.221 0.265 0.248 0.25 0.35 ... $ lvr : num 0.8 0.922 0.92 0.86 0.6 ... $ ccs : num 5 2 1 1 1 1 1 2 2 2

Dear all, I have a list of n matrices which all have the same dimension (r x s). What would be a fast/elegant way to calculate the element wise average? So result[1, 1] <- mean(c(raw[[1]][1, 1] , raw[[2]][1, 1], raw[[...]][1, 1], raw[[n]][1, 1])) Here is my attempt. #create a dummy dataset n <- 3 r <- 5 s <- 6 raw <- lapply(seq_len(n), function(i){ matrix(rnorm(r * s), ncol =

It looks from str(SA) that Response IPS1 is a data.frame of class "anova", which probably cannot be coerced to vector. Maybe you can use unlist() instead of as.vector() Or something like SA[["Response IPS1"]]["as.factor(WSD)",] ## to select the first row only, even maybe with unlist() Without a better REPRODUCIBLE example, I cannot tell more (maybe some others

Dear group, I am trying to write functions, but as a beginner, everything is not so obvious. Let's say I want the results in a list of elemts like this : tot1, tot2, etc Here is a function: toto <- function(x,y) { for(i in x:y){ paste(c("tot",i),collapse="")<-(i*2) } } If I type this : >toto(1,5) I get this message error: Error in paste(c("tot",

Dear users, My problem concerns save() within a for loop. Here is my code: for (i in 1:4) { temp <- data.frame(a=(i+1):(i+10), b=LETTERS[(i+1):(i+10)]) filename <- paste("file", i, sep="") assign(filename, temp) save(filename, file=paste(filename, ".rda", sep="")) } As you can see, save() doesn't work as I would like: (1) the object

Dear fellows, I am a novice in R. I would like to combine a matrix and a vector. Assume that we have the matrix a and the vector b with same length of column. a<-matrix(seq(1:10),nrow=2,ncol=5,byrow=TRUE) a= 1 2 3 4 5 6 7 8 9 10 b<-t(c(11,12,13,14,15)) b= 11 12 13 14 15 Then, I want to combine a and b as follows. c= 1 2 3 4 5 6 7 8 9

Hello, I have a number of files output1.dat, output2.dat, ... , output20.dat, each of which monitors several variables over a fixed number of timepoints. From this I want to create a data frame which contains the mean value between all files, for each timepoint and each variable. The code below works, but it seems like I should be able to do the second part without a for loop. I played

Hello guys, I want to rbind the columns of a data frame but I don't know how to do it, let's say: A B C 1 2 3 1 2 3 I want to get 1 1 2 2 3 3 It seems very simple but I still didnt get a find of how to do it...Please help! -- View this message in context: http://r.789695.n4.nabble.com/bind-a-data-frame-columns-tp2318526p2318526.html Sent from the R help mailing list archive

Dear list, I would generate a loop: a<-c(1:98) for (i in a ) { cbind(vor.tile[[i]]$x, vor.tile[[i]]$y)->p rbind(p,c(p[1,]))->p.c Polygon(p.c)->pc.p Polygons(list(pc.p),sprintf("p%s",i))->pc.ps sprintf("pc.ps%s",i)<-pc.ps } I need to obtain 98 pc.ps objects (like: pc.ps1, pc.ps2....pc.ps98) but I d'ont use sprintf for it. How can made it? many

Hello everyone, I have versions 2.7.2 and 2.10.1 installed on a machine that has no access to internet. In 2.7.2 I can use ? to get help on functions, which in 2.10.1 that does not work, all I see is "starting httpd help server...done" and then nothing. Have I downloaded 2.10.1 incorrectly (=forgot to tick some box for local help file repository) or is the internet help now the

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sorry I had a mistake sending my question without a subject. I do resend again. Please excuse me. > Hello > I have a data array with soil variables (caperf), in which the variable "clay" is factor (as I see entering str(caperf)) . I need to do a regression model, so I need to have arcilla (=clay) as a numeric variable. For that I have entered > >

Hello, How can I read a xlsx file using xlsx package? Thanks Albert [[alternative HTML version deleted]]

Dear users, I would like all the ticks on a boxplot (x and y) to be labeled I have checked all the par() arguments but couldn't find what I'm looking for Here is an example to show it: df <- structure(list(SPECSHOR = structure(c(1L, 1L, 1L, 3L, 3L, 3L, 3L, 3L, 4L, 4L), .Label = c("cotau", "dibic", "eqgre", "gicam"), class =