similar to: Need Help .RData in Mac OS X, Please

Hi R users, I google the website and I found that there are three ways to perform repeated measure ANOVA: aov, lme and lmer. http://www.mail-archive.com/r-help at stat.math.ethz.ch/msg58502.html But the questions are which one is good to use and how to do post-hoc test? I use the example that is provided in the above link and I try > tt<-aov(p.pa~group*time+Error(subject/time),data=P.PA)

Hi R users, Is is possible for me to use the try function with boot? I would to do the bootstraping with a nonlinear model(it works well when R < 1000). But it does not work very well (when R is large) thus I try to use "try" to resolve. I put the try function in two cases: case1: put the try in front of the boot > c1.try<-try(boot(c1data, statistic = c1.fun,

Hi R users Is there anything wrong in "is" function? (R 2.7.2) I believe that everyone will agree that "7" is an integer, right? but why R shows 7 is not an integer > is.integer(7) [1] FALSE > is(7,"integer") [1] FALSE > is(as.integer(7), "integer") [1] TRUE Thank you very much in advance Chunhao

Hi R users Is there anything wrong in "is" function? (R 2.7.2) I believe that everyone will agree that "7" is an integer, right? but why R shows 7 is not an integer > is.integer(7) [1] FALSE > is(7,"integer") [1] FALSE > is(as.integer(7), "integer") [1] TRUE Thank you very much in advance Chunhao

Hi R users, I have one simple question but I really don't know why I can't get it work. The data was adopted from Efron's An introduction to the bootstrap book. > nlaw LSAT GPA [1,] 576 3.39 [2,] 635 3.30 [3,] 558 2.81 [4,] 578 3.03 [5,] 666 3.44 [6,] 580 3.07 [7,] 555 3.00 [8,] 661 3.43 [9,] 651 3.36 [10,] 605 3.13 [11,] 653 3.12 [12,] 575 2.74

First thanks for Jinsong's suggestions I would like to do a bootstrap in a nonlinear model. But it fails to converge in most of time. (it did converge if I just use nls without boot). Thus, I use "try" function to resolve my problem. This following code is from Jinsong's suggestion. h1a.nls<-nls(density~nmf(time, alpha, delta, psi, tau, gamma),data=h1a,

Dear R users, Something is strange in summary and IQR. Suppose, I have a data set and I would like to find the Q1, Q2, Q3 and IQR. x<-c(2,4,11,12,13,15,31,31,37,47) > summary(x) Min. 1st Qu. Median Mean 3rd Qu. Max. 2.00 11.25 14.00 20.30 31.00 47.00 > IQR(x) [1] 19.75 However, I test the same data set in SAS "proc univariate", and SAS shows that

Hi R users, I try to build a function to compute odds ratio and relative risk however something wrong. I stuck for many hours but I really don't know how to solve it. Would someone please give me a hint? > OR.RR<-function(x){ + x <- as.matrix(any(dim(x)==2)) + OR<-(x[1,1]*x[2,2])/(x[1,2]*x[2,1]) + RR<-(x[1,1]/(sum(x[1,])))/(x[2,1]/(sum(x[2,]))) +

Hi R users, My question is, If I have 3 groups, A, B, C and I know mean of A =20, B=21, and C=20.5 and I also know the standard error of A =1.1, B=2.2, C=3.2. Plus, I know A has 30 observations, B has 78, C has 45. But I do not have the raw data. Can I use pairwise.t.test to conduct a Bonferroni test? If yes, Could you give me a hint? Thank you so much Chunhao -- View this message in

Hi Rers, I have a silly question. I don't know how to express the loglikelihood function of 1/(x!) where x=x1,x2,....xn in R. Could anyone give me a hint? Thank you in advance. Chunhao Tu

Dear R users, I have a question how to use 2 "ifelse" to sort my data. Such as from 11 to 20 assign to A; 6 to 10 assign to B, and the rest of them assign to C a<-1:20 tt<-ifelse(a>10, "A",no=ifelse( 5< a <=10, "B", "C")) Many Thanks Chunhao -- View this message in context:

Dear R Helpers, I try to write a small package that based on nlme however my code does not work. R always appears this message: Error in eval(expr, envir, enclos) : object "y" not found where y is the response variable. Please help me out! This is my code: require(nlme) AMPmixed<-function(y, x, S1=c("asymptotic","logistic"), random,data,

Hi R users, I have a question. How can I use for loop to do pair comparisons. For example, > x<-c(1,2,3) > result<-matrix(data=NA, nrow=choose(3,2), ncol=1) > for(i in 1: length(x)) + { result[i,]<-ifelse(x[i] > x[i+1], yes="Big", no="Small") + result} > result [,1] [1,] "Small" [2,] "Small" [3,] NA

Hi List, I have to compare a relationship between y and x for two locations. I found logistic regression fits both datasets well, but I am not sure how to test if relationships for both sites are significantly different. I searched the r site, however no answers exactly match the question. I used Tukey's HSD to compare two means, but the relationship in my study was not simply linear. So I

hi All, I''m new on the list. System: Distributor ID: Ubuntu Description: Ubuntu 13.04 Release: 13.04 Codename: raring Linux ctu 3.8.0-19-generic #30-Ubuntu SMP Wed May 1 16:35:23 UTC 2013 x86_64 x86_64 x86_64 GNU/Linux The symptom is the same with Saucy 3.9 kernel. ii btrfs-tools 0.20~git20130524~650e656-0daily13~raring1 amd64 Checksumming Copy on

Dear Josh, Thanks for your help! Does your answer mean, that you agree the two methods should do the same, and what I was guessing, despite the small differences? What I prefer about ci.pd is, that the help clearly says which method is implemented, which is not the case for prop.test. But I do not know who has programmed the function. Best wishes Steffi Stefanie von Felten, PhD Statistician

Hello, Does anyone know which method from Newcombe (1998)* is implemented in prop.test for comparing two proportions? I would guess it is the method based on the Wilson score (for single proportion), with and without continuity correction for prop.test(..., correct=FALSE) and prop.test(..., correct=TRUE). These methods would correspond to no. 10 and 11 tested in Newcombe, respectively. Can

has anyone played with the securelevel variable in the kernel and the immutable flags in the ext2 file system? The only way I have found to change the flag is by patching sched.c from int securelevel=0 to int securelevel=1 The sysctrl code seems to allow the setting of the flag only by init (PID=1) and only upwards (0->1, etc). The problem is that I haven''t found a way to get init

Greetings everyone; I am not an R user; however, I am attempting to install R 2.7.0 on a multi-user server for use by students and faculty in the Statistics department here. I have an old version of R installed on the same server, and it works fine; however, I am running into a problem installing this new version. Is this the appropriate forum for posting installation problems? If not,

my samba is working good, only a problem with the classic pdf printer I get this message from testparm Warning: Service pdf-printer defines a print command, but print command parameter is ignored when using CUPS libraries. Server role: ROLE_STANDALONE Press enter to see a dump of your service definitions and this is my .conf [global] workgroup = RSA netbios name = RSA-INTRANET