similar to: How to use lm() output for systemfit() 'Seemingly unrelated regression'

FYI, the same bug apears if one mounts the file system using "cifs": -rwxr----- 1 user 2532415 2000-04-02 00:34:50.000000000 -0800 fo1.mp3* -rwxr----- 1 user 3876671 2000-03-12 21:33:20.000000000 -0800 fo2.mp3* Linda W wrote: > Summary: > There appears to be a bug in the "time range" Samba is using on > dates where time is scheduled to "Spring Forward"

Dear list, I would like to do some calculation using different grouping variables. My 'df' looks like this: # Some data set.seed(345) id <- seq(200,400, by=10) ids <- sample(substr(id,1,1)) group1 <- rep(1:3, each=7) group2 <- rep(1:2, c(10,11)) group3 <- rep(1:4, c(5,5,5,6)) df <- data.frame(id, ids, group1, group2, group3) df <- rbind(df, df, df) df$time <-

Summary: There appears to be a bug in the "time range" Samba is using on dates where time is scheduled to "Spring Forward" from Standard to Daylight Savings time. Might want to review the code for "Falling back", as well... Details: This started out with my thinking it was an rsync problem, but it appears to be something to do with how samba is exporting the file

I am having following problem: I?m constructing model for calculation of area of triangle. I know sides a, b, and gamma angle. I wish to calculate the area using heron?s formula: S <- sqrt(s*(s-a)*(s-b)*(s-c)) where s <- (a+b+c)/2 and c is calculated using law of cosines: c <- sqrt(a^2 + b^2 -2*a*b*cos(gamma)) since i am calculating a regression model, i need derivation of this

I have found following problem: I have a vector: > a <- c(1.04,1.04,1.05,1.04,1.04) I want a mean of this vector: > mean(a) [1] 1.042 which is correct, but: > mean(1.04,1.04,1.05,1.04,1.04) [1] 1.04 gives an incorrect value. how is this possible? thanks, zbynek -- View this message in context: http://r.789695.n4.nabble.com/Incorrectness-of-mean-tp3327701p3327701.html Sent from the R

I've got the graphic with this: a=c(120,40,75,85,55,75,55,90,90,55,155) plot(ecdf(a)) How can I draw lines to show the lower quatile and upper quartil? I only know there is the argument lines(), but I don't know how to use it -- View this message in context: http://r.789695.n4.nabble.com/How-can-I-draw-a-line-in-empirical-distribution-function-tp3090675p3090675.html Sent from the R

Greetings R Users, I have a system of equations for which I would like to output all the R-squares. Assume there are four equations in my system, the only way I found to output all the R-squares is by calling them out one by one as this: summary(fitSUR$eq[[1]])$r.squared summary(fitSUR$eq[[2]])$r.squared summary(fitSUR$eq[[3]])$r.squared summary(fitSUR$eq[[4]])$r.squared But isn't there a

Hi, I have a dataset and I want to fit a function to it. The function is variogram model (http://en.wikipedia.org/wiki/Variogram) The variogram model is defined by three parameters and I want them to be automatically optimized for real time data. I tried to use gafit {gafit} for this, but there are some data configuration, where optimal results given by gafit() are negative, which is not correct

Hello to everyone, I have 2 problems and would be very pleased if anyone can help me: 1) When I use the package "systemfit" for SUR regressions, I get two different variance-covariance matrices when I firstly do the SUR regression ("The covariance matrix of the residuals used for estimation") and secondly do the OLS regressions. In the manual for "systemfit" on page

Hi I was trying to estimate simultaneous equation system in R using systemfit. I used the following commands >library(systemfit) > data(Kmenta) > attach(Kmenta) >eqDemand<-consump~price+income > eqSupply<-consump~price+farmprice+trend > fitsur<-systemfit("SUR",list(demand=eqDemand, supply=eqSupply)) and got the following error messege Error in

Dear List, With regard to the question I previously raised, here is the result I obtained right now, brglm() does help, but there are two situations: 1) Classifiers with extremely high AIC (over 200), no perfect separation, coefficients converge. in this case, using brglm() does help! It stabilize the AIC, and the classification power is better. Code and output: (need to install package:

Hi All, If given a dataframe (long form) with Year, Species, and Location, How would I write a function that would create a unique matrix of Species & Location for each Year? What I've tried doing is the following: data #dataframe dataT<-table(data$Species,data$Location,data$Year) #creates tables of Species vs Location for each Year But I'm encountering issues individually

I apologise for writing again about the problem with using stepAIC + multinom, but I think the reason why I had it in the first place is perhaps there may be a bug in either stepAIC or multinom. Just to repeat the problem, I have 126 variables and 99 cases. I don't know if the large number of variables could be the problem. Of couse the reason for doing a stepwise method is to reduce this

Thanks Cristoph, I have that code in my backend, but unless I do the following, the registers are never considered 'live' into the call. / Handle a function call let isCall = 1, Defs = [ R0, R1, R2, R3, R4, R5, R6, R7, R8, R9, R10, R11, R12, R13, R14, R15, R16, R17, R18, R19, R20, R21, R22, R23, R24, R25, R26, R27, R28, R29, R30, R31, R32, R33, R34, R35, R36, R37, R38, R39, R40, R41,

Hi Micah, > In X86InstrInfo.td for Call Instructions, it mentions that Uses for > argument registers are added manually. Can someone point me to the > location where they are added as the comment doesn't reference a > where or how? the register uses are added by the function X86TargetLowering::LowerCall() during the DAG Lowering phase. This is the relevant code segment: // Add

On 18/02/15 07:39, Steffen Kaiser wrote: > -----BEGIN PGP SIGNED MESSAGE----- > Hash: SHA1 > > On Wed, 18 Feb 2015, lejeczek wrote: >> On 17/02/15 19:36, Pascal Volk wrote: >>> On 02/17/2015 04:03 PM, lejeczek wrote: >>>> hi everybody. >>>> >>>> I wonder if such a scenario is possible. >>>> if yes would I configure multiple

Full_Name: Ulrich Poetter Version: 2.1.1 OS: i686-pc-linux-gnu FC2 Submission from: (NULL) (134.147.95.187) as.data.frame() segfaults on lists with very many elements: > dfn <- rep(list(rep(0,2)),198000) > test <- as.data.frame.list(dfn) Process R segmentation fault at Sun Sep 18 17:06:02 2005

It is clear, I think, that is.vector(o, mode = "any") should be TRUE whenever any of is.vector(o, mode = "<something>") is TRUE. This is not yet the case, however, see below. Consider the following examples which should be self-explaining. Besides the above bug, they also show you that -- for S compatibility -- the mode argument should really use strings as

A friend of mine sent me below so I am posting below. If it is not enough information, please just let me know and I will tell him. Thanks. -----Original Message----- Sent: Friday, April 13, 2007 3:58 PM To: Leeds, Mark (IED) Subject: R question I am using the "predict" function after I have done a simultaneous estimation of a system using "systemfit". fitsur is the output

Hello, I'm using samba 3.0.4, compiled with Kerberos 1.3.1-7, in an W2k3 ADS environment and Kerberos and the Winbind daemon are used for authentication. While checking a winbindd.log file I saw the following PANIC internal error: winbindd.log ========= [2004/07/21 12:15:00, 1] nsswitch/winbindd_group.c:winbindd_getgroups(1032) user 'root' does not exist [2004/07/21 12:15:00, 1]