similar to: function to compare numbers

Hi all, How to convert following simple python script to R if x in a_list: print x OR simply, how to test if a vector contain a value? Thank you in advance, Hyunchul [[alternative HTML version deleted]]

Hi, all how to get all filenames in a directory and its all subdirectories? something like filenames <- c(Sys.glob('/path/to/directory/*'), Sys.glob('/path/to/directory/*/*'), Sys.glob('/path/to/directory/*/*/*'), ...) Thanks in advance, Hyunchul [[alternative HTML version deleted]]

Hi, all I want to take a vector of component names of a list. list.a <- list('x'=1, 'y'=2) how to get a c('x','y') from list.a? Thanks in advance, Hyunchul [[alternative HTML version deleted]]

Hi, all, How to get a time as a number? While script is running, I want to print the elapsed time something like TIME_AS_SECOND() in the following script inittime <- TIME_AS_SECOND() for (i in 1:100){ do_something(i) curtime <- TIME_AS_SECOND() elapsedtime <- curtime-inittime print(paste(i, elapsedtime)) } Thanks in advance, Hyunchul [[alternative HTML version

Hi, all I made a simple R script to take the basename of a file without directory names. path.splitted <- strsplit('/path/to/a_basename', '/') path.length <- length(path.splitted[[1]]) basename <- path.splitted[[1]][path.length] # basename <- 'a_basename' Is there a simple function for this? something like os.path.basename(a_filename) of python? Thanks in

Hi, all I have a huge object that use almost all of available memory. R> rm(a_huge_object) R> gc() doesn't free memory and ?gc doesn't show anything. Are there any suggestion? Thanks in advance, Regards, Hyunchul [[alternative HTML version deleted]]

Dear users, My problem concerns save() within a for loop. Here is my code: for (i in 1:4) { temp <- data.frame(a=(i+1):(i+10), b=LETTERS[(i+1):(i+10)]) filename <- paste("file", i, sep="") assign(filename, temp) save(filename, file=paste(filename, ".rda", sep="")) } As you can see, save() doesn't work as I would like: (1) the object

Hey all, I am writing a function in which I will have a matrix of 4 columns and a variable amount of rows. The first to columns will always contain be of the Character type, the third and fourth columns can be a variation of data types, usually characters and integers, but sometimes lists or matrices. At one point the code makes, for each row, a copy of that row, then it makes some adjustments

Simple one here ... but can't get it to work ... for (i in 1:4){ paste("stuff",[i]),sep="") <- 3 + i } ls() rm(list=ls()) I just want it to create 4 new variables called stuff1, stuff2, stuff3, stuff4 with the corresponding assignments. I realise that there are more elegant functions but this is just a model of a bigger situation. Thanks Jim

Dear users, I would like all the ticks on a boxplot (x and y) to be labeled I have checked all the par() arguments but couldn't find what I'm looking for Here is an example to show it: df <- structure(list(SPECSHOR = structure(c(1L, 1L, 1L, 3L, 3L, 3L, 3L, 3L, 4L, 4L), .Label = c("cotau", "dibic", "eqgre", "gicam"), class =

Greetings, I am a very novice user with R, and in the course of running a linking procedure : P.old<- function (a, c, b, xi){ #a contains a parameters #c contains c parameters #b contains b parameters #xi is a one column vector containing quadrature points for xi(=theta-gamma)for one item tmp <- a*(xi-b)

Hi, all How to use elseif ? For example, like following short python examples. ********* x = 1 if x == 1: print 'same' *elif* x > 1: print 'bigger' else: print 'smaller' ********* Thanks in advance, Hyunchul Kim [[alternative HTML version deleted]]

Hello guys, I want to rbind the columns of a data frame but I don't know how to do it, let's say: A B C 1 2 3 1 2 3 I want to get 1 1 2 2 3 3 It seems very simple but I still didnt get a find of how to do it...Please help! -- View this message in context: http://r.789695.n4.nabble.com/bind-a-data-frame-columns-tp2318526p2318526.html Sent from the R help mailing list archive

Good morning, I have something like this: names(coint_tests) <- apply(b,2,paste, collapse="_") which prints 15 names like: A_B, C_D, E_F, ... AA,B,C,D.. Are time series. Then there is a vector called coint_tests of length 15 which yields "yes" or "no". I need to add a function to plot the time series Ai_Bi if the coint_tests vectors gives me a "YES".

Dear R-help list users, I have a huge vector of numbers, how I can invert orden? For example x <- 1:10000000 I would like to obtain x_r <- 10000000:1 Thanks, Sebastian.

Dear list, I have a question I'm trying to use the following command in R, but it gives me an error message.The command is: data<-ddply(data,c("year","name"), transform, check1=ifelse(check1==1 & check2==1, 1,NULL)) so in my data frame I already have the check1 variable, if the conditions (check1==1 & check2==1) is respected, check has to have 1 as value,

Hi I have two data frames that contains the same sort of data and I want do add them together to get one big data frame, anyone know how to do that? ex: data.frame1 A B C 1 2 3 4 5 6 7 8 9 and data.frame2 A B C 9 8 7 6 5 4 3 2 1 Would then become one big set: data.frame3 A B C 1 2 3 4 5 6 7 8 9 9 8 7 6 5 4 3 2 1 Thx for your help //Joel -- View this message in context:

Dear fellows, I am a novice in R. I would like to combine a matrix and a vector. Assume that we have the matrix a and the vector b with same length of column. a<-matrix(seq(1:10),nrow=2,ncol=5,byrow=TRUE) a= 1 2 3 4 5 6 7 8 9 10 b<-t(c(11,12,13,14,15)) b= 11 12 13 14 15 Then, I want to combine a and b as follows. c= 1 2 3 4 5 6 7 8 9

Hi, I have a list which looks like this... > str(y) List of 10 $ : chr [1:4] "ABCD" "5" "0" "1" $ : chr [1:4] "DEF" "15" "1" "16" $ : chr [1:4] "AAA" "2" "17" "8" $ : chr [1:4] "SSS" "15" "25" "1" $ : chr [1:4] "III"

Dear fellow R users, I am trying to conduct a regression analysis. I have thousands of variables. The names are V1, V2,........V2000 Is there an easy way to include these variables in the regression? my model is something like that: model<- lm(y~V1+V2+.....+V2000, data=data) Thanks so much in advance, Ozlem