similar to: how to get row name of matrix when result is a vector

Hi, I have a list which looks like this... > str(y) List of 10 $ : chr [1:4] "ABCD" "5" "0" "1" $ : chr [1:4] "DEF" "15" "1" "16" $ : chr [1:4] "AAA" "2" "17" "8" $ : chr [1:4] "SSS" "15" "25" "1" $ : chr [1:4] "III"

Hi, imagine the following matrix/data.frame Letter Number a 1 a 1 b 1 b 0 c 0 c 1 d 0 d 0 If the numbers for two identical letters are also identical then I want to remove either the first or the second row of that letter. If for a letter the numbers are 1 and 0 I want to remove the row with the 0. That means if the code works I would and up with the following matrix/data.frame Letter

Dear R users, I've already asked this question yesterday, but, though I had answer for the other ones (and they helped a lot, thanks), for some reason didn't get an answer for this one (I would also appreciate to know why, so that I can improve the quality and clarity of my future questions). Here it is again: I'm trying to use RODBC to export dataframes to xls files. When I run

Hello everyone, I have a data set like this: > head( fish_transect) ID_TRANSECT ID_PROJECT DE_ZONE DE_LOCALITY DE_SECTOR MES 1 42 MB Tarragona Creixell Control I 9 2 42 MB Tarragona Creixell Control I 9 3 42 MB Tarragona Creixell Control I 9 4 42 MB Tarragona Creixell Control I 9 5 42

Hi, I've looked through the posts but couldn't find a solution to this. I'd be really grateful if someone could help, I'd like to convert a data file of mutual information that is formatted as a matrix:             TF1    TF2    TF3    TF200... Gene1    0.0    0.2    0.2 Gene2    1.4    0.0    2.8 Gene3    0.3    0.6    1.7 Gene6000.... To a list: Gene1    TF1    0.0 Gene1   

Greetings, My goal is to create a Markov transition matrix (probability of moving from one state to another) with the 'highest traffic' portion of the matrix occupying the top-left section. Consider the following sample: inputData <- c( c(5, 3, 1, 6, 7), c(9, 7, 3, 10, 11), c(1, 2, 3, 4, 5), c(2, 4, 6, 8, 10), c(9, 5, 2, 1, 1) ) MAT <- matrix(inputData,

Hello, I'd like to ask you something again. I have a database and it has a column which looks like this one here: small_factor <- factor(c("d_variable1","d_variable2","d_variable3")) small_factor Now the thing is that I would like to convert each element of this factorized column. Basically I want to rewrite the words in it without the first two characters:

Dear all, I have searched the forums for an answer - and there is plenty of questions along the same line - but none of the paproaches shown worked to my problem: I have a data frame that I get from a csv: summarystats<-as.data.frame(read.csv(file=f_summary)); where I have the columns Dataset, Class, Type, Category,.. Problem1: I want to find a subset of this frame, based on values in

Readers, I have entered a file into r: ,column1,column2 row1,0.1,0.2 row2,0.3,0.4 using the command: dataframe<-read.table("/path/to/file.csv",header=T,row.names=1) When I try the command: dataframe[,2] I receive the response: NULL I was expecting: row1 0.2 row2 0.4 What is my error with the syntax please? Yours, r251 mandriva2009

Dear users, My problem concerns save() within a for loop. Here is my code: for (i in 1:4) { temp <- data.frame(a=(i+1):(i+10), b=LETTERS[(i+1):(i+10)]) filename <- paste("file", i, sep="") assign(filename, temp) save(filename, file=paste(filename, ".rda", sep="")) } As you can see, save() doesn't work as I would like: (1) the object

Hello everyone, I have versions 2.7.2 and 2.10.1 installed on a machine that has no access to internet. In 2.7.2 I can use ? to get help on functions, which in 2.10.1 that does not work, all I see is "starting httpd help server...done" and then nothing. Have I downloaded 2.10.1 incorrectly (=forgot to tick some box for local help file repository) or is the internet help now the

Hey all, I am writing a function in which I will have a matrix of 4 columns and a variable amount of rows. The first to columns will always contain be of the Character type, the third and fourth columns can be a variation of data types, usually characters and integers, but sometimes lists or matrices. At one point the code makes, for each row, a copy of that row, then it makes some adjustments

sorry I had a mistake sending my question without a subject. I do resend again. Please excuse me. > Hello > I have a data array with soil variables (caperf), in which the variable "clay" is factor (as I see entering str(caperf)) . I need to do a regression model, so I need to have arcilla (=clay) as a numeric variable. For that I have entered > >

Hello, How can I read a xlsx file using xlsx package? Thanks Albert [[alternative HTML version deleted]]

Dear users, I would like all the ticks on a boxplot (x and y) to be labeled I have checked all the par() arguments but couldn't find what I'm looking for Here is an example to show it: df <- structure(list(SPECSHOR = structure(c(1L, 1L, 1L, 3L, 3L, 3L, 3L, 3L, 4L, 4L), .Label = c("cotau", "dibic", "eqgre", "gicam"), class =

Hi, I have tried looking at the archives but havent found any answer that works till now (Sorry if i have missed anything) I am a newbie to R and i am trying to carry out hierarchical clustering using hclust -> as.dendrogram and then plotting the results as a dendrogram using the plot function plot(object). My question is : In the function "plot", can one decrease the leaf label

Dear R users, I've learned today about RODBC package in order to import xls file to dataframes and export the dataframes to xls files. However I have some problems. Please excuse me if these are basic but as I said, I've just begun with this package. Also this email is quite long, but everything is related, so I don't think it would be better to split it. Moreover, there's a

It looks from str(SA) that Response IPS1 is a data.frame of class "anova", which probably cannot be coerced to vector. Maybe you can use unlist() instead of as.vector() Or something like SA[["Response IPS1"]]["as.factor(WSD)",] ## to select the first row only, even maybe with unlist() Without a better REPRODUCIBLE example, I cannot tell more (maybe some others

Dear users, I have looked on different sources and found different functions to prompt the user to provide input. However, I couldn't find one that does exactly what I'm looking for. select.list() and menu() are nice because a graphic window appears to prompt the user. However, the user can only choose from a predefined list of choices. readline() and scan() are more free in the

Greetings, I am a very novice user with R, and in the course of running a linking procedure : P.old<- function (a, c, b, xi){ #a contains a parameters #c contains c parameters #b contains b parameters #xi is a one column vector containing quadrature points for xi(=theta-gamma)for one item tmp <- a*(xi-b)