similar to: Help on Select.list

Hi, I am seeking help with an error when running the example from R Documentation for TukeyHSD. The error occurs with any example I run, from any text book or website. thank you... > plot(TukeyHSD(fm1, "tension")). Error in plot(confint(as.glht(x)), ylim = c(0.5, n.contrasts + 0.5), ...) : error in evaluating the argument 'x' in selecting a method for function

I am wondering if anyone might know why the package clim.pact won't install properly. I have tried many URL sites and the same thing happens. I get the error message below. I also tried downloading the ZIP from the CRAN site and extracting the file myself, but an error message (something like, "not an archive file") appears. I operate through Windows. Thanks. Gary Nelson.

Hi folks, I am confused whether the following is a bug or it is fine Here is the explanation a <- zoo(c(NA,1:9),1:10) Now If I do rollapply(a,FUN=mean,width=3,align="right") I get > rollapply(a,FUN=mean,width=3,align="right") 3 4 5 6 7 8 9 10 NA NA NA NA NA NA NA NA But I shouldn't be getting NA right ? i.e for index 10 I should get (1/3)*(9+8+7)

Hi R, If x=c(1,3,5) y=c(2,4,6) I need a vector which is c(1,2,3,4,5,6) from x and y. How do I do it? I mean the best way.... Thanks, Shubha This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hi R, This is a very trivial one.... C=0.1 I want to check whether my value of C is between 0 and 1 exclusively.... I don't want to use (C>0 & C<1). And I can't use a single statement like (0<C<1). Is there a between function? Or how do we specify from 0 to 1? Does %in% help me? Many Thanks, Shubha This e-mail may contain confidential and/or

Hi R, I need to generate 50 random numbers (preferably poisson), such that their sum is equal to 100. How do I do this? Thank you, Shubha This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hi R, Let, x=1:80 I want to sum up first 8 elements of x, then again next 8 elements of x, then again another 8 elements..... So, my new vector should look like: c(36,100,164,228,292,356,420,484,548,612) I used: aggregate(x,list(rep(1:10,each=8)),sum)[-1] or rowsum(x,group=rep(1:10,each=8)) But without grouping, can I achieve the required? Any other ways of doing

Hi R, A quick question: How do we find the number of words in a string? Example: C="Have a nice day" And the number of words should be 4. any built in function or?... Thanks, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain

Hi R, Please solve my problem........... I am extracting Bloomberg data from R, in a loop. R is getting fatigued by doing this process and gives some errors. I introduced sleep function. Doing this sometimes I get the results and sometimes not. I even noticed that if I give complete rest for R (don't open R window) for 1 day and then run my code with the sleep function, then the

Hi Experts, I want to see my object as below: 'C:\Program Files\R\R-2.4.0\bin\Rgui.exe' So I use the paste command. None of the below is working. Could anyone help me on this? > paste("'C:\Program Files\R\R-2.4.0\bin\Rgui.exe'") [1] "'C:Program FilesRR-2.4.0\binRgui.exe'" > paste("'C:","\","Program

Hi, Suppose a=matrix(1:9,3,3) > a [,1] [,2] [,3] [1,] 1 4 7 [2,] 2 5 8 [3,] 3 6 9 Now, > class(a[1:2,]) [1] "matrix" > class(a[1:3,]) [1] "matrix" > class(a[,1:2]) [1] "matrix" > class(a[,1:3]) [1] "matrix" But, > class(a[1,]) [1] "integer" > class(a[,1]) [1]

Hi R, I was experimenting with the CA package for correspondence analysis. data(author) ca(author) plot(ca(author)) How can I get the values used by the plot for the two axis for biplot? In other words, how will I be able to obtain the scores in the dimensions (which are obtained by PCA) of the graphs? Thanks. Thanks and Regards, Shubha This e-mail may contain

Hi, I wanted the DICE coefficient (similarity measure for binary variables) to be calculated in R and found that the "igraph" package has the option of "similarity.dice" to do this. But, for this command, the input object should be an igraph object. But, I have a dataframe of columns containing 1's and 0's. Can I convert this dataframe into an igraph object, so that

Hi R, Can we download Reuters (3000 Xtra) data from R? Does ODBC package help me in this? Or otherwise, is there a way to extract daily closing prices data of Reuters from R? Thank you very much, Shubha This e-mail may contain confidential and/or privileged i...{{dropped:13}}

On 5/13/2008 10:27 AM, Yukihiro Ishii wrote: > Hi Rusers! > > I am ashed of asking such a simple question. > > X<-matrix(rnorm(24), 4) > X0<-apply(X,2,mean) > > What I want is a matrix which consists of colums such as X[,1]--X0[1]. > > X-X0 doesn't work. > > Perhaps apply function? scale(X, scale=FALSE) ?scale > Thanks in advance. > >

Hi R-Experts, I'm currently using R 2.4.0 in Windows XP. I'm trying to download data from Bloomberg using the package "RBloomberg", but it fails to install the three needed packages "zoo", "chron" and 'Rbloomberg". Moreover I am not able to find "RBloomberg" package as windows binary in CRAN site as only for MAC it's given. Please

Hi R, I have the data frames, data1, data2....data50. Now I want to put all of these in a single list. But, >list(data1, data2,.........data50) is very big to write. How do I then do it? Thanks, Shubha This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hi R users, Is there a function in R, which does some calculation only for the month end in a daily data?... In other words, is there a command in R, equivalent to "last." function in SAS? BR, Shubha [[alternative HTML version deleted]]

Hello dear R help group, I am trying to read a .txt file, with Hebrew column names, while keeping the column names looking well in R - but without success. I uploaded an example file to: http://www.talgalili.com/files/aa.txt And am trying the command: read.table("http://www.talgalili.com/files/aa.txt", header = T, sep = "\t") This returns me with: X.....ª X...ª......

Hi R, I have a list, l=list(list(c(1,2),c(4,5),c(6,7)),list(c(11,22,33),c(44,55,66))) > l [[1]] [[1]][[1]] [1] 1 2 [[1]][[2]] [1] 4 5 [[1]][[3]] [1] 6 7 [[2]] [[2]][[1]] [1] 11 22 33 [[2]][[2]] [1] 44 55 66 How do I know the dimensions of this list?... In other words, how many sub-lists, sub-sub-lists etc...are there in l? How do I know this?