similar to: How to invert a list ?

I want to create a graph to express the idea of the area under a pdf curve, like http://r.789695.n4.nabble.com/file/n3032194/w7295e04.jpg Thank you for any help. ----- A R learner. -- View this message in context: http://r.789695.n4.nabble.com/How-to-plot-a-normal-distribution-curve-and-a-shaded-tail-with-alpha-tp3032194p3032194.html Sent from the R help mailing list archive at Nabble.com.

Hi all, >From a list of strings, I desire to filter out the followings: 1. Digits at the beginning of the strings 2. Character "SPE" following the digits (if it exists) 3. Any characters followed by hyphen The following produces the desired result, but would like to know whether this can be done more efficiently. Any suggestions would be much appreciated. dat <- c("2148

Hi, When I plot, the axis ticks are printed as "50.00 25.00 10.00 1.00 0.05 0.01", is there any way to print them as "50 25 10 1 0.05 0.01" instead? Thanks John

I don't know the real reason, but help("==") gives some clues. For numerical and complex values, remember == and != do not allow for the finite representation of fractions, nor for rounding error. Using all.equal with identical is almost always preferable. See the examples. x1 <- 0.5 - 0.3 x2 <- 0.3 - 0.1 x1 == x2 # FALSE on most machines

I have a data.frame as the following: var1 var2 9G/G09 abd89C/T90 10A/T9 32C/C 90G/G A/A . . . . . . 10T/C 00G/G90 What I want is to get the letters which are on the left and right of '/'. for example, for "9G/G09", I only want "G", "G", and for "abd89C/T90", I only want "C" and

Hi John, Here is my code practicing. Please give me some advises. Thank you. Wu Gong # Extract the function string f.str <- sub("y~","",exprtext) # Get arglist from the text sp1 <- paste("\\",c(getGroupMembers(Arith),"(",")"),sep="") sp2 <- getGroupMembers(Math) sps <-

Hi, there is a function Skewness() under fBasics package. If I type "skewness", I get followings: > skewness function (x, ...) { UseMethod("skewness") } <environment: namespace:timeDate> Would be great if someone tell me how to see the codes of this function. 2ndly suppose I create following function: fn1 <- function(x) return(x+2) How

dear: when I read a Excel file(exp-11),The R project give me a error ,Just like this: ??'datafile' > write.foreign("exp-11.xls") ???list(df = df, datafile = datafile, codefile = codefile) : ??'datafile' > write.foreign("exp-11.xls") ???list(df = df, datafile = datafile, codefile = codefile) : ??'datafile' >

Dear R helpers, I created a somewhat big database (+206,700 rows) in MySQL and have exported into a csv file, but I can't open the whole thing in R. I am using: > base<-read.csv("/path/to/file.csv", header=F, sep="," nrows=206720) R doesn't complain but it only opens 128,328 observations (the number of columns corresponds to the original database): >

Dear list, I have a vector of characters and a list of two named elements : i <- c("a","a","b","b","b","c","c","d") j <- list(j1 = c("a","c"), j2 = c("b","d")) I'm looking for a fast way to obtain a vector with names, as follows : [1] "j1" "j1"

Hello all, I try the follow test with an odf file. *INPUT: teste.odt* <teste, results=xml>>= x <- matrix(rnorm(6), nc=2) xst <- tableStyles(x, useRowNames = TRUE, header = NULL) odfTable(x, styles=xst, colnames = NULL, useRowNames = TRUE) @ and I get this error: *OUTPUT error:* Error: chunk 1 (label=teste) Error in matrixPaste(textStart, textName, textEnd, x, tagEnd, sep =

Dear all, I run a loop wrapped in try(), and for each of the rows where "try-error" is true I want to fill that row with NA (at the moment it is omitted). So I would expect to get a dataframe with 1000 rows some of which would be empty, but instead I get a dataframe with 995 rows. In this case missing 5 rows were omitted. Any suggestions? Thanks, Olga ----------------

Hi I wish to read a file from my local directory from inside a function. I am passing the filename as the argument but this does not work. Say for example function(dat) { dat1=read.csv("D:\\dat.csv",header=TRUE) } If I call funtion(dat) I get the following error. 'Intuitively' i understand this is a mistake but how do I overcome this and how can I read a file name passed as an

Hi all I have problems in accessing a mer object called model.01 from a workspace that was created with R 2.8.1 and saved with save into an .RData file (on Windows XP or Ubuntu 8.10, don't remember anymore). Now I want to open it in R 2.9.0 on Ubuntu 8.10. I use # load workspace load("name.RData") which seems to work: ls() # all objects in there [1] "all"

temp = "~aparch(" temp1 = paste(temp,1, sep = "") temp2 = paste(temp1,1, sep = ",") temp3 = paste(temp2, ")",sep = "") temp 3 is a character but I want to convert to formula object. How do I do this? -- View this message in context: http://r.789695.n4.nabble.com/how-to-convert-string-to-object-tp2999281p2999281.html Sent from the R help mailing

Hi, I need help to find an efficient way to transform a vector like: a<-c(1,1,0,1,0,0,0,1,1,1,1,0,1,0,1,1) in a vector that counts only di 1 elements, like: b<-c(1,2,0,1,0,0,0,1,2,3,4,0,1,0,1,2) Thank you! -- View this message in context: http://r.789695.n4.nabble.com/counts-of-a-vector-tp2232047p2232047.html Sent from the R help mailing list archive at Nabble.com.

Hi, I've got a quite tricky question. I have a txt file, named 'temp.txt', as the following: snp1 snp2 snp3 AA 00 00 GG GG 00 00 AA 00 I want to read the file into R. 1) when I use 'read.table' without 'header=T' option, > temp <- read.table('temp.txt') # I got > temp V1

This patch series introduces the tapback daemon, the user space daemon that acts as a device''s back-end, essentially most of blkback in user space. The daemon is responsible for coordinating the front-end and tapdisk. It creates tapdisk process as needed, instructs them to connect to/disconnect from the shared ring, and manages the state of the back-end. The shared ring between the

Dear list, I have a list of matrices : i1 <- matrix(1:10, nrow = 2, ncol = 5) i2 <- matrix(11:20, nrow = 2, ncol = 5) j <- list(i1 = i1, i2 = i2) I would like to attribute names to each dimension, for each matrix, as follows : $i1 B1 B2 B3 B4 B5 A1 1 3 5 7 9 A2 2 4 6 8 10 $i2 B1 B2 B3 B4 B5 A1 11 13 15 17 19 A2 12 14 16 18 20 However, I have to use lapply function and attribute

Hi, there, I have 2 machines ( running Linux Red Hat 8.0 and Windows Xp individually), which share a broadband Internet connection through a router. After installing Samba 2.2.7.a on Linux machine, I can use "smbclient" to access Windows machines, see the files and transfer files. Linux machine info: name: WINNY share folder name: gong ip: 192.168.123.153 valid