similar to: bind a data frame columns

Dear users, My problem concerns save() within a for loop. Here is my code: for (i in 1:4) { temp <- data.frame(a=(i+1):(i+10), b=LETTERS[(i+1):(i+10)]) filename <- paste("file", i, sep="") assign(filename, temp) save(filename, file=paste(filename, ".rda", sep="")) } As you can see, save() doesn't work as I would like: (1) the object

Hey all, I am writing a function in which I will have a matrix of 4 columns and a variable amount of rows. The first to columns will always contain be of the Character type, the third and fourth columns can be a variation of data types, usually characters and integers, but sometimes lists or matrices. At one point the code makes, for each row, a copy of that row, then it makes some adjustments

Dear group, I am trying to write functions, but as a beginner, everything is not so obvious. Let's say I want the results in a list of elemts like this : tot1, tot2, etc Here is a function: toto <- function(x,y) { for(i in x:y){ paste(c("tot",i),collapse="")<-(i*2) } } If I type this : >toto(1,5) I get this message error: Error in paste(c("tot",

Greetings, I am a very novice user with R, and in the course of running a linking procedure : P.old<- function (a, c, b, xi){ #a contains a parameters #c contains c parameters #b contains b parameters #xi is a one column vector containing quadrature points for xi(=theta-gamma)for one item tmp <- a*(xi-b)

Simple one here ... but can't get it to work ... for (i in 1:4){ paste("stuff",[i]),sep="") <- 3 + i } ls() rm(list=ls()) I just want it to create 4 new variables called stuff1, stuff2, stuff3, stuff4 with the corresponding assignments. I realise that there are more elegant functions but this is just a model of a bigger situation. Thanks Jim

Hi guys, here is a list of names that I have: MyList: > myList<-list("A", "B","C","D") > myList [[1]] [1] "A" [[2]] [1] "B" [[3]] [1] "C" [[4]] [1] "D" I want to turn this list into a matrix of 1 row and 4 columns with those four components (A, B, C, D) so here is what I do: myDataFrame <-

Hello everyone, I have versions 2.7.2 and 2.10.1 installed on a machine that has no access to internet. In 2.7.2 I can use ? to get help on functions, which in 2.10.1 that does not work, all I see is "starting httpd help server...done" and then nothing. Have I downloaded 2.10.1 incorrectly (=forgot to tick some box for local help file repository) or is the internet help now the

Good morning, I have something like this: names(coint_tests) <- apply(b,2,paste, collapse="_") which prints 15 names like: A_B, C_D, E_F, ... AA,B,C,D.. Are time series. Then there is a vector called coint_tests of length 15 which yields "yes" or "no". I need to add a function to plot the time series Ai_Bi if the coint_tests vectors gives me a "YES".

Dear R-help list users, I have a huge vector of numbers, how I can invert orden? For example x <- 1:10000000 I would like to obtain x_r <- 10000000:1 Thanks, Sebastian.

Dear list, I have a question I'm trying to use the following command in R, but it gives me an error message.The command is: data<-ddply(data,c("year","name"), transform, check1=ifelse(check1==1 & check2==1, 1,NULL)) so in my data frame I already have the check1 variable, if the conditions (check1==1 & check2==1) is respected, check has to have 1 as value,

Hi I have two data frames that contains the same sort of data and I want do add them together to get one big data frame, anyone know how to do that? ex: data.frame1 A B C 1 2 3 4 5 6 7 8 9 and data.frame2 A B C 9 8 7 6 5 4 3 2 1 Would then become one big set: data.frame3 A B C 1 2 3 4 5 6 7 8 9 9 8 7 6 5 4 3 2 1 Thx for your help //Joel -- View this message in context:

Hello, How can I read a xlsx file using xlsx package? Thanks Albert [[alternative HTML version deleted]]

Dear fellows, I am a novice in R. I would like to combine a matrix and a vector. Assume that we have the matrix a and the vector b with same length of column. a<-matrix(seq(1:10),nrow=2,ncol=5,byrow=TRUE) a= 1 2 3 4 5 6 7 8 9 10 b<-t(c(11,12,13,14,15)) b= 11 12 13 14 15 Then, I want to combine a and b as follows. c= 1 2 3 4 5 6 7 8 9

Hi, I have a list which looks like this... > str(y) List of 10 $ : chr [1:4] "ABCD" "5" "0" "1" $ : chr [1:4] "DEF" "15" "1" "16" $ : chr [1:4] "AAA" "2" "17" "8" $ : chr [1:4] "SSS" "15" "25" "1" $ : chr [1:4] "III"

Dear fellow R users, I am trying to conduct a regression analysis. I have thousands of variables. The names are V1, V2,........V2000 Is there an easy way to include these variables in the regression? my model is something like that: model<- lm(y~V1+V2+.....+V2000, data=data) Thanks so much in advance, Ozlem

Hi there, I have been trying to use the "pvclust" package but have been having some difficulties. This is the first time I have used R so I am sure the mistake I am making is a basic one. The data I have is a distance matrix and I have been using the command; fit <- pvclust(cluster, nboot=1000, method.dist="euclidean") to try and perform hierarchical clustering with

sorry I had a mistake sending my question without a subject. I do resend again. Please excuse me. > Hello > I have a data array with soil variables (caperf), in which the variable "clay" is factor (as I see entering str(caperf)) . I need to do a regression model, so I need to have arcilla (=clay) as a numeric variable. For that I have entered > >

Hi all, can anyone please tell me what is the key-word to clear the screen? I am aware of the "cont+L", however I need some R-syntax, that can be typed into the console to clear the screen.   Thanks [[alternative HTML version deleted]]

Hi, I have tried looking at the archives but havent found any answer that works till now (Sorry if i have missed anything) I am a newbie to R and i am trying to carry out hierarchical clustering using hclust -> as.dendrogram and then plotting the results as a dendrogram using the plot function plot(object). My question is : In the function "plot", can one decrease the leaf label

Hi, all is there a built-in function to compare two numbers? something like following function cmp <- function(x, y){ value <- 0 if (x > y){ value <- 1 }else if (x == y){ value <- 0 }else { value <- -1 } return(value) } Thanks in advance, Hyunchul [[alternative HTML version deleted]]