similar to: Regular Expression

Dear list, I have a list, as follows : a <- 5 names(a) <- "a" b <- 9 names(b) <- "b" c <- 15 names(c) <- "c" x <- list("i" = a, "j" = b, "j" = c) I want to invert the list, like this : $a i 5 $b j k 9 15 I do not find a clean solution. Could anyone give me elegant ideas ? Thanks in advance, Carlos

I want to create a graph to express the idea of the area under a pdf curve, like http://r.789695.n4.nabble.com/file/n3032194/w7295e04.jpg Thank you for any help. ----- A R learner. -- View this message in context: http://r.789695.n4.nabble.com/How-to-plot-a-normal-distribution-curve-and-a-shaded-tail-with-alpha-tp3032194p3032194.html Sent from the R help mailing list archive at Nabble.com.

I don't know the real reason, but help("==") gives some clues. For numerical and complex values, remember == and != do not allow for the finite representation of fractions, nor for rounding error. Using all.equal with identical is almost always preferable. See the examples. x1 <- 0.5 - 0.3 x2 <- 0.3 - 0.1 x1 == x2 # FALSE on most machines

Hi, When I plot, the axis ticks are printed as "50.00 25.00 10.00 1.00 0.05 0.01", is there any way to print them as "50 25 10 1 0.05 0.01" instead? Thanks John

Hi John, Here is my code practicing. Please give me some advises. Thank you. Wu Gong # Extract the function string f.str <- sub("y~","",exprtext) # Get arglist from the text sp1 <- paste("\\",c(getGroupMembers(Arith),"(",")"),sep="") sp2 <- getGroupMembers(Math) sps <-

I have a data.frame as the following: var1 var2 9G/G09 abd89C/T90 10A/T9 32C/C 90G/G A/A . . . . . . 10T/C 00G/G90 What I want is to get the letters which are on the left and right of '/'. for example, for "9G/G09", I only want "G", "G", and for "abd89C/T90", I only want "C" and

Hello, I am relatively new to R and I am working through the code that is provided in the book Numerical Ecology with R and I have run across an error message that I can't seem to figure out. I am using the vegan, ade4, gclus and cluster packages. The code is as follows: # Ordered community table # Species are ordered by their weighted averages on site scores or <- vegemite(spe,

Dear all, I have run the confint() function according to below and I get the following error message: > confint(stepAIC.glm.spe.var.konn2.abund, level=0.95) Waiting for profiling to be done... Error: missing value where logical needed In addition: Warning message: NaNs produced in: sqrt((fm$deviance - OriginalDeviance)/DispersionParameter) or > confint(stepAIC.glm.spe.var.konn2.abund,

Dear list, I want to calculate SPE (squared prediction error) in x-space, can someone help? Here are my codes: fit.pls<- plsr(Y~X,data=DAT,ncomp=3,scale=T,method='oscorespls',validation="CV",x= T) actual<-fit.pls$model$X pred<-fit.pls$scores %*% t(fit.pls$loadings) SPE.x<-rowSums((actual-pred)^2) Am I missing something here? Thanks in advance. Stella Sim

Dear R-gurus, Just supose I have a dara.frame that looks like myDF<-read.table(stdin(),head=T,sep=",") codID,namesp,k1,k2,k3,k4 1,spA,2,5,6,3 2,spB,4,5,4,6 3,spC,2,1,5,6 4,spC,5,4,3,2 5,spD,1,2,3,4 6,spE,2,4,3,1 I need to update the columns k1-k4 with the namesp, but considering the math between Kx and codID. My desired output must looks like: codID,namesp,k1,k2,k3,k4

Dear all, Is there any function for calculating confidence limits for coefficients in an lm() object? I know of the confint() function in the MASS library working very well on my binomial GLMs and I have tried it (using glm () , family=gaussian) but it gives NAs according to below. Does the confint() function not accept gaussian GLMs? Could there be convergence problems in the GLM? Note the

Hello, I am using vegan to do an NMDS plot and I would like to suppress the labels for the loading vectors. Is this possible? Alternatively, how can I avoid overlap? Many thanks for the help. Example code: #perform NMDS using metaMDS() function spe.nmds<-metaMDS(data, distance='bray',k=2 , engine = "isoMDS", autotransform=F, trymax=1000) #calculate the loading (i.e.,

Hello when my code executes I receive the message that were some warnings. I want to catch warning messages at run time so to print some local variables and try to understand why this warning happens. I searched on internet and I tried withCallingHandlers( which seems to work but as I used Rkward the result is awful. I get a prompt to copy paste a value only while at the same time my background

Hello, I've got an ISDN PRI circuit terminating in a Cisco AS5350, which in turn is talking to an Asterisk server via SIP for call origination and termination. Seems simple enough, and it works for the most part, but: 1) Caller ID name data comes in on the PRI, but doesn't appear to get handed off to the Asterisk server via SIP, at least not in any format that Asterisk

Hi, I am a new R user and am trying to construct a palaeoenvironmental transfer function (weighted averaging method) using the package rioja. I've managed to insert the two matrices (the species abundance and the environmental data) and have assigned them to the y and x values respectively. When I try and enter the 'WA' function though, I get an 'Error in FUN' message (see

Hello, I am making some use of ROC curve analysis. I find much help on the mailing list, and I have used the Area Under the Curve (AUC) functions from the ROC function in the bioconductor project... http://www.bioconductor.org/repository/release1.5/package/Source/ ROC_1.0.13.tar.gz However, I read here... http://www.medcalc.be/manual/mpage06-13b.php "The 95% confidence interval for

Hi, I am trying to fit a logarithmic trendline to a scatterplot of a species accumulation curve. I've tried abline, lines, curve and scatter.smooth but none of these work. Can anyone help please, Kyran

Full_Name: Xiaobao Wang Version: R 1.7.1 OS: Windows XP Submission from: (NULL) (24.45.25.102) accidentally done the following: rpt.dir <- paste("c:/report/testR","bestsub",spe="/") dir.create(rpt.dir) (spe should be sep). Now the directory "c:/report/testR bestsub " cannot be removed. I tried to remove it from Windows Explorer and got the message

Dear R helpers I have a data frame as given below df = data.frame(A = c(776,827,836,995,855,1026,1203,1363,965,1195),                        B = c(806,953,1049,1056,1243,764,1148,1162,948,1154),                        C = c(959,1155,1193,1163,863,1070,1087,877,1132,944),                        D = c(906,760,978,1170,1009,883,1007,960,828,113)) # Actually the real data has number of vectors and

Dear list, I am new to lattice plots. I want to make a barchart with 10 and more levels. I need to use a grey scale for printing purposes. The problem is that with 10 or more levels in factors it is very difficult to distinguish each level in the plot and legend, since the greys are very similar (some levels have value of zero and don't appear). Here is an example of my problem: df <-