similar to: grep with search terms defined by a variable

Greetings: I am looking for some help (probably really basic) with looping. What I want to do is repeatedly sample observations (about 100 per sample) from a large dataset (100,000 observations). I would like the samples labelled sample.1, sample.2, and so on (or some other suitably simple naming scheme). To do this manually I would >smp.1 <- sample(100000, 100) >sample.1 <-

Hi, I have just noticed an undesired behavior when using rsync when disk quota is exceeded. I do not know how to avoid it (or maybe it can be considered as a bug). The following is a scenario that leads to the undesired behavior: 1) I normally execute two following commands to synchronize folders between a local host and a remote host: rsync -aCPvu --existing <dir1>

Dear R forum Suppose I have a data.frame df = data.frame(id = c(1:6), x = c(15, 21, 14, 21, 14, 38), y = c(36, 38, 55, 11, 5, 18), x.1 = c(15, 21, 14, 21, 14, 38), z = c("D", "B", "A", "F", "H", "P")) > df   id  x  y    x.1 z 1  1 15 36  15 D 2  2 21 38  21 B 3  3 14 55  14 A 4  4 21 11  21 F 5  5 14  5  14 H 6  6 38 18  38 P

Dear R forum I have one stupid question, but I have no other solution to it in sight? Suppose some R process creates graphs etc alongwith main output as data.frame e.g output1 = data.frame(bands = c("A", "B", "C"), results = c(74, 108,  65)) I normally save this output as some csv file. But I need to save this output as some image (I understand this is weird,

Dear R forum I have a data.frame df = data.frame(dates = c("4/15/2013", "4/14/2013", "4/13/2013", "4/12/2013"), values = c(47, 38, 56, 92)) I need to to create a vector by repeating the dates as "Current_date", 4/15/2013, 4/14/2013, 4/13/2013, 4/12/2013,  "Current_date", 4/15/2013, 4/14/2013, 4/13/2013, 4/12/2013, Current_date,

Apologies if this has been asked before. I am having trouble understanding the R mailing list never mind R! I am relatively new to R having migrated from Minitab and SPSS. I have managed to do some more complicated statistics such as hierarchical partitioning of variance on an 80,000 record dataset but have to admit that drawing a simple bar plot I could do by hand is proving extremely

Dear R forum, I have a data.frame as defied below - df = data.frame(names = c("C", "A", "A", "B", "C", "B", "A", "B", "C"), dates = c("4/15/2013", "4/13/2013", "4/15/2013", "4/13/2013", "4/13/2013", "4/15/2013", "4/14/2013",

Hi Geoff, Geoff Shang wrote: > Hi, > > That's what fallback-override is meant to do. Are you saying that it's not > working for you? Not working. But what is wrong? I've added the second mount to icecast.xml and tested whether it switch back to the original mount point. The mount part of icecast.xml: <mount>

Dear R forum I have a data.frame df = data.frame(currency_type = c("EURO_o_n", "EURO_o_n", "EURO_1w", "EURO_1w", "USD_o_n", "USD_o_n", "USD_1w", "USD_1w"), rates = c(0.47, 0.475, 0.461, 0.464, 1.21, 1.19, 1.41, 1.43))   currency_type     rates 1      EURO_o_n   0.470 2      EURO_o_n   0.475 3       EURO_1w   0.461

Dear Forum, I have a data frame as  mydat = data.frame(basel_asset_class = c(2, 8, 8 ,8), defa_frequency = c(0.15, 0.07, 0.03, 0.001)) > mydat   basel_asset_class defa_frequency 1                 2          0.150 2                 8          0.070 3                 8          0.030 4                 8          0.001 I need to get the subset of this data.frame where no of records for the

Dear Forum, I have a data frame as  mydat = data.frame(basel_asset_class = c(2, 8, 8 ,8), defa_frequency = c(0.15, 0.07, 0.03, 0.001)) > mydat   basel_asset_class defa_frequency 1                 2          0.150 2                 8          0.070 3                 8          0.030 4                 8          0.001 I need to get the subset of this data.frame where no of records for the

Hi, I hope somebody can help me with this issue: I am doing population pyramids using the barplot command, so in the left side I have male age structure and in the right side the female age structure. To plot the male age structure I put the data in negative numbers. Now, I want to change the sign in the bar plot in such way that I have no-sign numbers, both in left and right side of the graph. I

Dear R forum I have a following vector of random no.s x = runif(100, 0.01, 0.99)  [1] 0.47212037 0.77867992 0.33947474 0.93369035   [5] 0.03720073 0.79307831 0.81801835 0.92710688 ................................................. I need to count the random no. falling in the range (0 - 0.10), (0.10 - 0.20), (0.20 - 0.30)..upto (0.90 - 1) Thus, I need to have a data frame as

Hello, i guess this question appeared before, but I haven't found anything by searhing the whole morning. I know that some web radio stations use icecast2. They also have a web application that makes it possible to request songs, add items to the playlist of the source client and so on. Most of the web radios have developed the web application by itself (i guess so). I'm not able to

Dear R forum, (Pl note this is not a finance problem) I have two data.frames as currency_df = data.frame(current_date = c("3/4/2013", "3/4/2013", "3/4/2013", "3/4/2013"), issue_date = c("27/11/2012", "9/12/2012", "14/01/2013", "28/02/2013"), maturity_date = c("27/04/2013", "3/5/2013",

I have a data set that has student test scores along with several categorical variables. I would like to generate a set of summary stats (mean, variance, n) for the data grouped by school authority and by exam topic. I have tried the by() function but that seems to only be able to handle one level of grouping. In particular what I would like is something like the following Board Subject Mean

Dear R forum I have a vector say as given below df = c("F", "C", "F", "B", "D", "A", "D", "D", "A", "F", "D", "F", "B",    "C") I need to find (1) how many times each element occurs? e.g. in above vector F occurs 4 times, C occurs 2 times etc. (2)

Dear R forum, The example below is just an indicative one and I have constructed it. My real life data and conditions are different. I have a data.frame as given below mydat = data.frame(A = c(19, 20, 19, 19, 19, 18, 16, 18, 19, 20), B = c(19, 20, 20, 19, 20, 18, 19, 18, 17, 16)) if (length(mydat$A) > 10) { stop("A has length more than 10") }else if (max(mydat$B) > 18) {

Hello icecast user, That's my first post to this list, because everything works fine :) But now I'm missing a feature and I'm not sure if it is possible to realise. I have two mounts. Only one defined in the configuration: <mount> <mount-name>/gast.ogg</mount-name> <fallback-mount>/offline.ogg</fallback-mount>

Hi I am testing Ruby 1.9.2 and Rails 3. Has anybody encountered this error: web katz$ gem install rspec-rails ************************************************** Thank you for installing rspec-rails-1.3.2 If you are upgrading, do this in each of your rails apps that you want to upgrade: $ ruby script/generate rspec Please be sure to read History.rdoc and Upgrade.rdoc for useful