similar to: Continuing on with a loop when there's a failure

Hello all, I am trying to write a program in R in which I call a function multiple times within a loop. The problem is that sometimes the function breaks down while calling another function, and produces an error message that breaks my loop and the program stops. I would like to keep the loop running when this function breaks down, and just move on to the next iteration in the loop. Is there

Hello again R users, I have a devilishly hard problem, which should be very simple. I hope someone out there will have the answer to this on the tip of their tongue. Please consider the following toy example: x <- read.table(textConnection("y x1 x2 indv.1 bagels 4 6 indv.2 donuts 5 1 indv.3 donuts 1 10 indv.4 donuts 10 9 indv.5 bagels 0 2 indv.6 bagels 2 9 indv.7 bagels 8 5 indv.8

Hello again, How do I split a data frame into smaller, completely separate data frames (rather than separate data frames comprising a single "list")? Consider the following data, and my coding attempt: x <- read.table(textConnection("id type number indv.1 bagel 6 indv.2 bagel 1 indv.3 donuts 10 indv.4 donuts 9"), header = TRUE) closeAllConnections() x.split <-

Hi all, I am looking to fit a logistic regression using the lrm function from the Design library. I am interested in this function because I would like to obtain "pseudo-R2" values (see http://tolstoy.newcastle.edu.au/R/help/02b/1011.html). Can anyone help me with the syntax? If I fit the model using the stats library, the code looks like this: model <- glm(x$trait ~ x$PC1 +

Hi, I was hoping someone could help me with the following problem. Consider this toy example. For the input dataset there are four individuals (rows "indv.1" through "indv.4"), measured for two different variables (columns "var.1" and "var.2") at two different levels of a factor (column "factor.level"). I want to calculate a matrix that has the

Hi I have the followed code for which I am writing a loop pass. int main() { int i = 0; for (i=0; i<20; i++) { printf ("hello world %d\n", i); } return 0; } In the function runOnLoop, I have the following instruction PHINode *indv = NULL; indv = L->getCanonicalInductionVariable(); However, when I check indv is always set to NULL. Since the code has a canonical

Hi, What does your LLVM IR look like. Are you sure the loop hasnt been optimized away? Arushi On Sat, May 21, 2011 at 5:52 PM, Malveeka Tewari <mtewari at eng.ucsd.edu>wrote: > Hi > > I have the followed code for which I am writing a loop pass. > > int main() { > int i = 0; > for (i=0; i<20; i++) { > printf ("hello world %d\n", i); > }

Dear All, I'm using apply to do some genetic association analysis along a chromosome, with many thousands markers. For each marker the analysis is the same, so I was planning to use apply(chrom, 2, somefunction) In the specific case I do: my.results = apply(chr, 2, function(x){anova(lrm( cpstc.f ~ x + time.cpstc + age + sex + mri))[1,3]}) This is all good and well in theory, but in

Hi all, I have a very simple problem that I cannot seem to find the answer to. Consider the following toy dataset: x <- read.table(textConnection("V1 apples bananas cherries indv.1 7 8 4 3 indv.2 7 7 4 9"), header = TRUE) How would I change the column name of ONLY the first column, not the others? Surely I should not have to re-specify the names of ALL the columns -- e.g.,

Hello R listserve, I would appreciate someone's help with this problem. Consider the following toy dataset: x <- read.table(textConnection("worldclim.1 worldclim.2 cru.1 cru.2 indv.1 7 8 32 658 indv.2 7 7 39 422"), header = TRUE) How could I create a subset of the data based on the column prefix? For instance, let's say I wanted to subset only the columns with the

Hi, I turn to you, the R Sages, once again for help. You've never let me down! (1) Please make the following toy files: x <- read.table(textConnection("var.1 var.2 var.3 var.1000 indv.1 1 5 9 7 indv.210000 2 9 3 8"), header = TRUE) y <- read.table(textConnection("var.3 var.1000"), header = TRUE) write.csv(x, file = "x.csv") write.csv(y, file =

Is there a way to combine two columns within a data frame? Example data: id snp AL1 AL2 1500 30 A B 1510 30 A A 1520 30 A B This is what I would like: indv snp AL1AL2 1500 30 AB 1510 30 AA 1520 30 AB Any help is greatly appreciated. Alysta

Greetings from Austin - Home of the Lone Star Ruby Conference. This year we are catering to your every desire. In addition to the customary luxuries you have come to expect at LSRC, like the awesome food or the power strips at every table for your hungry laptops, this year you will also be greeted with: * the new conference center sound system. * bagels, yogurt, fruit and donuts for every

Hello I am trying to run equations with different combinations of explanatory variables. I have managed to figure?out how to generate?the different combinations, and am trying to set up equations where I use these combinations. And this is where I?am getting stuck. I have searched several R websites but with no success. This is how I generate the different combinations of my explanatory variables

dear professor: I have a problem about the nomogram.I have got the result through analysing the dataset "exp2.sav" through multinominal logistic regression by SPSS 17.0. and I want to deveop the nomogram through R-Projject,just like this : > n<-100 > set.seed(10) > T.Grade<-factor(0:3,labels=c("G0", "G1", "G2","G3")) >

I am cleaning up the rms package to not export functions not to be called directly by users. rms uses generic functions defined in other packages. For example there is a latex method in the Hmisc package, and rms has a latex method for objects of class "anova.rms" so there are anova.rms and latex.anova.rms functions in rms. I use:

Hi Group, I have a question about obtaining the bias-corrected c-index using validate from the Design library. As an example, consider the example from help page: library(Design) ?validate.lrm n <- 1000 age <- rnorm(n, 50, 10) blood.pressure <- rnorm(n, 120, 15) cholesterol <- rnorm(n, 200, 25) sex <- factor(sample(c('female','male'),

Dear List, Given, y <- matrix(c(0,1,1,1,0,0,0,4,4), ncol = 3, byrow = TRUE) rownames(y) <- c("a","b","c") colnames(y) <- c("1","2","3") y y2 <- y[2:3, ] rownames(y2) <- c("x","z") y2 how can I stop merge(y, y2, all = TRUE, sort = FALSE) squishing the extra rows? Ideally I want the same as: rbind(y,

Hi - I'm up against a complicated reshape problem. I have data of the form X1,Y1,hr1,hr2,hr3 X1,Y2,hr1,hr2,hr3 X1,Y3,hr1,hr2,hr3 X2,Y1,hr1,hr2,hr3 X2,Y2,hr1,hr2,hr3 X2,Y3,hr1,hr2,hr3 where X and Y are factors and the hr(1,2,3) are values. I need it as ,X1, X2 Y1,hr1,hr1 Y1,hr2,hr2 Y1,hr3,hr3 Y2,hr1,hr1 Y2,hr2,hr2 Y2,hr3,hr3 .., Any hints? I've been at it for hours. p -- View

I wish to rearrange the matrix, df, such that all there are not repeated x values. Particularly, for each value of x that is reated, the corresponded y value should fall under the appropriate column. For example, the x value 3 appears 4 times under the different columns of y, i.e. y1,y2,y3,y4. The output should be such that for the lone value of 3 selected for x, the corresponding row entries