similar to: R crashes with large vectors

You can just use the same code that I provided before but now use your dataset. Like this df <- read.csv(file="data2.csv",header=TRUE) dates <- as.Date(paste(df$year,"-01-01",sep="")) myXts <- xts(df,order.by=dates) head(myXts) #The last command "head(myXts)" shows you the first few rows of the xts object year cnsm incm wlth

oky.. thank you very much to all of you On Sat, Sep 16, 2017 at 2:06 PM, Eric Berger <ericjberger at gmail.com> wrote: > You can just use the same code that I provided before but now use your > dataset. Like this > > df <- read.csv(file="data2.csv",header=TRUE) > dates <- as.Date(paste(df$year,"-01-01",sep="")) > myXts <-

> On 15 Sep 2017, at 11:38, yadav neog <yadavneog at gmail.com> wrote: > > hello to all. I am working on macroeconomic data series of India, which in > a yearly basis. I am unable to convert my data frame into time series. > kindly help me. > also using zoo and xts packages. but they take only monthly observations. > > 'data.frame': 30 obs. of 4 variables:

Hello, I noticed something odd when working with data frames and xts objects. If I read in a CSV file, R creates a nice data.frame. This works well. If I then convert to an XTS object, I see that all the values in the data are now quoted. My data is a mix of numeric and character. This is usually seen when converting a data.frame to a matrix, as R will treat all the data as the same class.

hello to all. I am working on macroeconomic data series of India, which in a yearly basis. I am unable to convert my data frame into time series. kindly help me. also using zoo and xts packages. but they take only monthly observations. 'data.frame': 30 obs. of 4 variables: $ year: int 1980 1981 1982 1983 1984 1985 1986 1987 1988 1989 ... $ cnsm: num 174 175 175 172 173 ... $ incm:

Assuming the input data.frame, DF, is of the form shown reproducibly in the Note below, to convert the series to zoo or ts: library(zoo) # convert to zoo z <- read.zoo(DF) # convert to ts as.ts(z) # Note: DF <- structure(list(year = c(1980, 1981, 1982, 1983, 1984), cnsm = c(174, 175, 175, 172, 173), incm = c(53.4, 53.7, 53.5, 53.2, 53.3), with = c(60.3, 60.5, 60.2, 60.1, 60.7)),

Good afternoon everybody, I am sorry, this question might look trivial to some of you, but I read quite a lot of stuff about package creation and I would like a bit of you advices. I would like to develop a core library which I will be using both from R and from C#. I read that it was possible to import DLL to R. The thing is, I am not sure that the DLL created with C# will be compatible. I

Good morning, I am currently displaying a time series with the time on the Y axis, and the values on the X axis. The problem is that I wanted to reverse the Y axis (that is, to have the latest date the closest to the X axis). So I looked for a way to do this on this mailing list and I found a response: inverting the ylim parameter of the plot. I did it, the data are displayed correctly, but now

Hello, I apologize that I am cross posting here after getting no answer from my initial question on stack overflow <http://stackoverflow.com/questions/33492601/r-setoldclass-only-if-needed>. I should certainly have posted it first here.. I am using 3 packages: - xts - quantmod - 'myPackage' quantmod is creating a union class by doing: setOldClass("xts");

Hi I want to simplify my problem into a prototype, how to write a function to get all the object in your current environment, e.g. .GlobalEnv, and print their mode? For example, if I have object a,b,c... in my environment, a=1;b='test';c=matrix(0,3,3)..... I want to write a function myfun(), when I run myfun(), this retrieve all the objects in my environment automatically and print

Hi dear all, In my laptop(ubuntu 11.10 64bit), I maintained a released R (2.14) and a developmental R, I can specify qplot(..., alpha = ) in R 2.14 , but when I try to use transparency in developmental R, I got a warning message and the plot is clearly not I want. minimal example: > qplot(data = mtcars, x = mpg, y = cyl, alpha = cyl) Warning message: In grid.Call.graphics(L_points, x$x, x$y,

Hi dear all, In my laptop(ubuntu 11.10 64bit), I maintained a released R (2.14) and a developmental R, I can specify qplot(..., alpha = ) in R 2.14 , but when I try to use transparency in developmental R, I got a warning message and the plot is clearly not I want. minimal example: > qplot(data = mtcars, x = mpg, y = cyl, alpha = cyl) Warning message: In grid.Call.graphics(L_points, x$x, x$y,

Hi dear all I am currently using Ubuntu 9.10 (karmic) and R 2.10, I can find a R release that support "karmic" in cran under ubuntu directory, I plan to update my laptop to Ubuntu 10.04 after April 30, since I have to use some new features or new version in it, e.g. QT 4.6, I don't know if there is going to be a R release that will support this newly released Ubuntu? Thanks in

Hi dear all, I am wondering if there is a function existing in R that did the quadratic bezier curve interpolation? I hope to generate a bezier curve based on three sets of points: two end of the line and a control point. Thanks in advance. Tengfei -- Tengfei Yin MCDB PhD student 1620 Howe Hall, 2274, Iowa State University Ames, IA,50011-2274 [[alternative HTML version deleted]]

I am really new with R Graphical user interfacefunctions. I am developing a software package to calculate pKa (biochemistry) but I want to make it look aesthetically pleasing and make it user friendly. I have heard that R has some GUI (Graphical user interface) and you can do some really cool stuff out there. What are the limitations and what are some resources for help. I have found a couple of

Hi, list- ?? I've got a large list of multi-column data and I'd like to filter it according to a threshold, such as, "show me the values that are above 0.4 for each line." For instance, if the line of data were: > line v1 v2 v3 v4 v5 v6 v7 v8 v9 1 -0.32 0.66 -0.35 -0.82 0.38 0.66 -0.02 -0.11 -0.64 I can do this > line[,line >= 0.4]

Hello, I have a data.frame: name    col1    col2    col3    col4 AA    23    54    0.999    0.78 BB    123    5    1    0.99 AA    203    98    0.79    0.99 I want to get mean value data.frame in terms of name: name    col1    col2    col3    col4 AA    113.0000  76.0000   0.8945   0.8850 BB    123.00   5.00   1.00   0.99 I tried to use by function: >aa<-by(test[,2:5], feature, mean)

I recently started using ubuntu 9.10 and I am using gedit editor and R plugin for writing R code. To install any package I need to do: $ install.packages() //window pop-up for mirror selection //then another window pop up for package selection. After this as long as I am not exiting, the function of the newly installed packages are available. After I exit (i use to put 'no' in 'save

Hello, Can anyone please suggest any packages in R that can be used to overlay gene expression data on SNP (affymetrix) copy number ? Thanks, Ekta Senior Research Associate Bioinformatics Department Jubilant Biosys Pvt Ltd, #96, Industrial Suburb, 2nd Stage Yeshwantpur, Bangalore 560 022 Ph No : +91-80-66628346 The information contained in this electronic message and in any attachments to this

Hi dear all I am currently using Ubuntu 9.10 (karmic) and R 2.10, I can find a R release that support "karmic" in cran under ubuntu directory, I plan to update my laptop to Ubuntu 10.04 after April 30, since I have to use some new features or new version in it, e.g. QT 4.6, I don't know if there is going to be a R release that will support this newly released Ubuntu? Thanks Best