Displaying 20 results from an estimated 10000 matches similar to: "when all I have is a contingency table...."
2010 Oct 15
2
feed cut() output into goodness-of-fit tests
Hello,
My question is assuming I have cut()'ed my sample and look at the
table() of it, how can I compute probabilities for the bins? Do I have
to parse table's names() to fetch bin endpoints to pass them to
p[distr-name] functions? i really don't want to input arguments to PDF
functions by hand (nor copy-and-paste way).
> x.fr <- table(cut(x,10))
> x.fr
(0.0617,0.549]
2010 Jun 08
2
constructing a contingency table (ftable, table)
Dear all,
an hopefully quick table question.
I have the following data:
Two objects that are 2*9 matrix with nine column names (Dis1, ...,
Dis9) and the row names (2010,2020). The content are frequencies
(numeric).
In want to create a table that is along the lines of
ftable(UCBAdmissions) and should looks like this:
Dis1 | ...| Dis9
2010|2020|....|2010|2020
(first row,first column is the value
2012 Dec 01
4
Getting all possible contingency tables
Hello all,
Let say I have 2-way contingency table:
Tab <- matrix(c(8, 10, 12, 6), nr = 2)
and the Chi-squared test could not reject the independence:
> chisq.test(Tab)
Pearson's Chi-squared test with Yates' continuity correction
data: Tab
X-squared = 1.0125, df = 1, p-value = 0.3143
However I want to get all possible contingency tables under this
independence
2010 Mar 30
4
list index rules evaluation behavior
I have what may be a simple/foolish question, but I've done the due diligence
and looked through pages of posts here as well as several of the PDFs on the
CRAN site, but haven't been able find what I'm after.
I am working with a list of say 3 histogram objects A, B & C, and each
histogram is a list of 7 elements. I would like to access $name, the 6th
element, of histograms A,B and
2005 Feb 21
4
49 histograms on one page
Hi,
I want to do something like this:
par(mfrow=c(7,7))
for (i in 1:49)
hist(RATDACOM[SUBJNO==i],breaks=0.5+(0:6),
main="",xlab="",ylab="",xaxt="n",yaxt="n")
(Don't think about what RATDACOM and SUBJNO are.)
I get an error
Error in plot.new() : Figure margins too large.
36 histograms with mfrow=c(6,6) work.
But the 36 histograms
2009 Jun 04
3
Understanding R Hist() Results...
Think I'm missing something to understand what is going on with hist(...)
http://n2.nabble.com/What-is-going-on-with-Histogram-Plots-td3022645.html
For my example I count 7 unique years, however, on the histogram there only 6. It looks like the bin to the left of the tic mark on the x-axis represents the number of entries for that year, i.e. Frequency.
I guess it looks like the bin for
2003 Dec 08
2
Character graphics
Does anyone else miss email-friendly character graphics such as the
following example, produced using Minitab?
Histogram of C6 N = 478 N* = 21
Each * represents 2 observation(s)
Midpoint Count
-12 16 ********
-11 53 ***************************
-10 63 ********************************
-9 83
2006 Sep 28
0
mx2 contingency tables or (2^(m-1)-1)'s 2x2 contingency tables in the context of feature selection for random forest
Dear Listers:
I have a categorical feature selection problem for random forest.
Suppose I have a multiple-leveled category variable A, which has m=3
levels: red, green, and blue and the final target is binary
classification.
I want to evaluate its power in discrimination between 2 classes. We
know rf splits multiple-leveled category variable by considering all
combinations of its levels. So
2011 Nov 10
2
Listing tables together from random samples from a generated population?
.
HI there,
I'd like to show demonstrate how the chi-squared distribution works, so I've come up with a sample data frame of two categorical variables
y<-data.frame(gender=sample(c('Male', 'Female'), size=100000, replace=TRUE, c(0.5, 0.5)), tea=sample(c('Yes', 'No'), size=100000, replace=TRUE, c(0.5, 0.5)))
And I'd like to create a list of 100
2003 Nov 18
5
Histogram
Hi,
I have what should be a simple question. I would like to generate a
histogram of
x <- c("a","b","c","b","c","c")
where the first bar to be labeled 'c' with height 3, second bar to be
labeled 'b' with height 2 and third bar to be labeled 'a' with height 1.
This should be an easy task in R but I think I
2009 Feb 24
2
Simulating contingency table (Basic question, help please)
I'd like to carry out a Monte Carlo simulation test where given data is a
contingency table. I think this is something to do with using rmultinonom(),
but I'm not sure how to code this, to simulate contingency tables. Could
anyone please help with how to use R to simulate contingency tables like
this?
--
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2012 May 19
1
Contingency table and mean(sd)
Hi All,
I have a question regarding contingency tables. I would like to calculate the mean and standard deviation of a continuous variable from my own dataset based on the percentages of a contingency table I obtained from a scientific article.
dataset<- data.frame(cbind(case=rep(0:1,5), x1=c(1:10), x2=c(0:9)))
contingency_table<- matrix(c(100, 75, 65, 85, 90, 87), nrow=3, ncol=3)
In
2009 Dec 09
1
Exporting Contingency Tables with xtable
Dear R-philes:
I am having an issue with exporting contingency tables with xtable().
I set up a contingency and convert it to a matrix for passing to
xtable() as shown below.
v.cont.table <- table(v_lda$class, grps,
dnn=c("predicted", "observed"))
v.cont.mat <- as.matrix(v.cont.table)
Both produce output as follows:
observed
predicted uh uh~
uh 201
2013 Mar 04
1
package ‘contingency.tables’ is not available (for R version 2.15.2)
I am trying to create contingency tables (to evaluate prior to performing
Pearson's Chi-Squared test for independence). I would like to see column
and row totals as well as expected and observed values and cell counts.
I tried to use the package "contingency. tables" but get the following
warning:
package ‘contingency.tables’ is not available (for R versions 2.15.2)
Is there
2008 Feb 14
3
contingency table
Hello!
May you help me? I'm trying to do a contingency table using this
> data(iris)
> library(rpart)
> modelo <- rpart(Species ~., iris)
> prev <- predict(modelo, iris)
Finally the contingency table
> table(iris$Species, prev)
But an error occurs:
Error in table(iris$Species, prev) :
all arguments must have the same length
And I do not understand why, may you
2011 Feb 24
1
reshaping list into a contingency table
Hi all,
I have been struggling with this problem for a few days.
I have a data table like this:
gene rpkm1 diff1 rpkm2 diff2
gene1 23 50 13 120
gene2 111 220 827 1200
gene3 75 998 71 910
And I want to re-format it so that, for each gene, I have a 2x2 contingency
table, such as:
gene rpkm diff
gene1 23 50
gene1 13 120
gene2 111 220
gene2 827
2000 Aug 23
1
3D perspective of a contingency table
How can I draw a 3D perspective of a contingency table, that is
showing 3D bars whose height is in proportion of the table cells?
---------------
Charles RAUX,
Laboratoire d'Economie des Transports
CNRS-Universit? Lumi?re Lyon 2-ENTPE
email : charles.raux at let.ish-lyon.cnrs.fr
http://www.ish-lyon.cnrs.fr/let
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2003 Apr 24
3
Detailed contingency tables
Is there any existing function for creating contingency tables that will
display counts, row, column, and cell percentages in the same
tables....anything similar to crosstabs in S?
Marc W. Zodet, MS
Health Statistician
Center for Cost and Financing Studies
Division of Statistical Research and Methods
2101 East Jefferson Street, Suite 500
Rockville, Maryland 20852
Phone: 301-594-7072
Fax:
2010 May 24
1
high-dimensional contingency table
Dear Friends.
I am just starting to use R. And in this occasion I want to construct a
high-dimensional contingency table, because I want to crate a mosaic plot
with the vcd package.
My table is in this format:
año ac.rep cat.gru conteos
1 2005 R parejas 253
2 2005 N parejas 23
3 2006 R parejas 347
4 2006 N parejas 39
5 2007 R
2008 Mar 18
1
ask for help how to get accumulate contingency table?
Hi, I post the question again.
x<-rep(c(2,3,4),20)
y<-sample(rep(c(0,1),30))
tr<-rep(c(1:5),6)
data1<-data.frame(x,y,tr)
data1<-data1[order(data1$tr),]
> data1
x y tr
2 1 1
4 0 1
3 1 1
2 1 1
4 1 1
3 1 1
2 0 1
4 0 1
3 0 1
2 0 1
4 0 1
3 1 1
3 0 2
2 0 2
>table(data1)
tr = 1
y
x 0 1
2 2 2
3 1 3
4 3 1
tr = 2
y
x 0 1
2 2 2
3 2 2
4 1 3