similar to: Weired problem when passing arguments using ...?

Dear Colleagues: I would like to write a front end for a modeling function, but run into trouble when passing a weights argument. y <- 1:5 x <- c(1,3,2,5,4) w <- function(formula, ...) lm(formula, ...) lm(y ~ x, weights=c(1,1,1,2,2)) w(y ~ x) w(y ~ x, weights=c(1,1,1,2,2)) Error in eval(expr, envir, enclos) : ..1 used in an incorrect context, no ... to look in w <-

Hello, How would you go about handling the following situation? This is on R 2.12.0 on Ubuntu 32-bit. I have a wrapper function to lm. I want to pass in a subset argument. First, I just thought I'd use "...". ## make example reproducible set.seed(123) df1 <- data.frame(age = rnorm(100, 50, 10), bmi = rnorm(100, 30, sd = 2)) ## create a wrapper using

Hi. I am getting an "unexpected symbol" error, which I haven't gotten before. I have checked my data and searched the FAQ. I hoping someone has a suggestion on what I might be doing wrong? Thanks! A. Gray Fisheries Consultant Here's the code I'm using and the error: > 0708smolts <- read.csv("C:\Documents and Settings\ayesha\My

Dear R wizards, I have a folder containing 1000 files. For each file, I need to extract the first row of each file, paste it to a new file, then write out that file. Then I need to repeat this operation for each additional row (row 2, then row 3, etc) for 23 rows in each file. I can do this with a for loop (as below). Is there a way to use some of the indexing power of R to get around this

I'm looking for a way to improve code that's proven to be inefficient. Suppose that a data source generates the following table every minute: Index Count ------------ 0 234 1 120 7 11 30 1 I save the tables in the following CSV format: time,index,count 0,0:1:7:30,234:120:11:1 1,0:2:3:19,199:110:87:9 That is, each line represents a table, and I

hello, i have been trying to convert my data frames to matrices in the hopes of speeding up some of my more complicated scripts. to assist with this, i am trying to create a "matrix column operator" like $: "%$%" = function(data,field) { as.numeric(data[,grep(field,unlist(dimnames(data)[2]))]) } the idea here is that you can use a matrix like a dataframe:

Hi, I'm heaving difficulties with a dataset containing gene names and positions of those genes. Not such a big problem, but each gene has multiple exons so it's hard to say where de gene starts and where it ends. I want the starting and ending position of each gene in my dataset. Attached is the dataset: http://www.nabble.com/file/p21312449/genlistchrompos.csv genlistchrompos.csv Column

Dear All I am trying to fit a multinomial logistic regression to a data set with a size of 94279 by 14 entries. The data frame has one "sample" column which is the categorical variable, and the number of different categories is 9. The size of the data set (as a csv file) is less than 10 MB. I tried to fit a multinomial logistic regression, either using vglm() from the VGAM package or

Hi, I know this is a simple question, but I've been having problems passing additional arguments through '...'. It is not matching the arguments correctly if the permanent argument of the function begins with the same letter as the additional argument. The following example will help show what I mean: fun.tester <- function(abc,...){ + print(abc) + } But if I input:

AFAIK a script run through source() does not have any legit way to learn about it's own location. I need this to make sure that the script will find its datafiles after I move the whole directory. (The datafiles are in the same directory.) Here is a hack I invented to work around it: print(getwd()) source_pathname = get("ofile",envir = parent.frame()) source_dirname =

Dear R users, As substitute() help page points out: Substituting and quoting often causes confusion when the argument is 'expression(...)'. The result is a call to the 'expression' constructor function and needs to be evaluated with 'eval' to give the actual expression object. And indeed I am confused. Consider: > dat <- data.frame(x=1:10,

Dear R users, As substitute() help page points out: Substituting and quoting often causes confusion when the argument is 'expression(...)'. The result is a call to the 'expression' constructor function and needs to be evaluated with 'eval' to give the actual expression object. And indeed I am confused. Consider: > dat <- data.frame(x=1:10,

Dear R users, I have a large individual-level dataset (~700,000 records) which I am performing a conditional logistic regression on. Key variables include the dichotomous outcome, dichotomous exposure, and the stratum to which each person belongs. Using this individual-level dataset I can successfully use clogit to create the model I want. However reading this large .csv file into R and running

I have a data frame with two factors (sampling 'unit', 'species'). I want to calculate the number of unique 'species' per 'unit.' I can calculate the number of unique values for each variable separately, but can't get a count for each ?unit?. > data=read.csv("C:/Desktop/sr_sort_practice.csv") > attach(data) > data[1:10,] unit species 1

Dear R community, I am running some rather large scripts either by executing single blocks of them separately or by executing them at once via source('script.R') Now there is a lot of code in those scripts that I only want to run when I run them manually, so I wonder whether there is any way to automatically find out whether the script is run manually stepwise or whether it is run via

Hello all, I'm using the following scan() parameters on a tab-separated text file that was generated by R. temp_file <- scan(file = outfile, sep="\t", what = character(), skip = 1, nlines = 1) The problem is that within some cells, there are cases where there are three frontslashes ( /// ). However, the file itself is tab-separated, and the exact problem is that even if I

Hi All, The last line if the following code returns the error right below this paragraph. Essentially, I use the operator %:% to retrieve a variable in a nested frame. Then I want to use the same operator (with '<-') to change its value. I'm not sure if this is possible in R with %:% operator. Would you please help and let me how to correct the code if it is possible? Error in

Hello, I have a question about how R can run automatically. Here is the story: A file called "data.csv" will be generated every couple of minutes in a folder (overwrite itself). What I want R to do is: 1) scan the folder to find the file. 2) if the file is a newly generated file, process the file 3) output some file identifier on the screen, such as the time when the file was

Hi, How can I check if a certain ... argument has been passed on to my user-defined function or not? foo <- function(data, ...) { ### here I want to check whether xlab was passed with the ... arguments ### or if the ... arguments did not contain an xlab argument } I tried missing(xlab) , exists(xlab) and several other things but did not find a solution. TIA, Mark

Hi, If I want to import the contents of a R file into another one, I can do source("foo.R") However, this imports everything from foo.R, including all functions and global variables. Is there a way of selectively importing individual functions etc., in a similar fashion to Python's from foo import bar ? Thanks in advance. Please cc me on any reply.