similar to: Help With ANOVA (corrected please ignore last email)

Displaying 20 results from an estimated 600 matches similar to: "Help With ANOVA (corrected please ignore last email)"

2010 Jul 06
2
Help With ANOVA
Hi I needed some help with ANOVA I have a problem with My ANOVA analysis. I have a dataset with a known ANOVA p-value, however I can not seem to re-create it in R. I have created a list (zzzanova) which contains 1)Intensity Values 2)Group Number (6 Different Groups) 3)Sample Number (54 different samples) this is created by the script in Appendix 1 I then conduct ANOVA with the command >
2010 Mar 09
3
Help with ANOVA in R
Hi I am attempting Anova analysis to compare results from four groups (Samp1-4) which are lists of intensities from the experiment. I am doing this by first creating a structured list of the data and then conducting the ANOVA (Script provided below). Im an R beginner so am not sure if I am using this correctly. Two major questions I have are: 1) Is using the code (zzz.aov <- aov(Intensity ~
2009 Apr 14
1
Help with ANOVA p-values
Hi I have done ANOVA on a dataset (See Below) but am having problems retreiving the p-value. I am assuming that Pr(>F) is the p-value but cannot get this value or in fact any other value (e.g. DF) from the summary.Any suggestions?? I have tried sum<-summary(zzz.aov) > sum$Pr(>F) Error: unexpected '>' in "sum$Pr(>" > sum$"Pr(>F)" NULL >
2009 Jul 15
1
Help with averaging
Hi I am using the following script to average a set of data 0f 62 columns into 31 colums. The data consists of values of ln(0.01) or -4.60517 instead of NA's. These need to be averaged for each row (i.e 2 values being averaged). What I would I need to change for me to meet the conditions: 1. If each run of the sample has a value, the average is given 2. If only one run of the sample has a
2005 Mar 21
1
rpart memory problem
Hi everyone, I have a problem using rpart (R 2.0.1 under Unix) Indeed, I have a large matrix (9271x7), my response variable is numeric and all my predictor variables are categorical (from 3 to 8 levels). Here is an example : > mydata[1:5,] distance group3 group4 group5 group6 group7 group8 pos_1 0.141836040224967 a c e a g g pos_501
2007 Oct 30
2
flexible processing
Hello, unfortunately, I don't know a better subject. I would like to be very flexible in how to process my data. Assume the following dataset: par1 <- seq(0,1,length.out = 100) par2 <- seq(1,100) fac1 <- factor(rep(c("group1", "group2"), each = 50)) fac2 <- factor(rep(c("group3", "group4", "group5", "group6"), each =
2011 Oct 30
1
Normality tests on groups of rows in a data frame, grouped based on content in other columns
Dear R users, I have a data frame in the form below, on which I would like to make normality tests on the values in the ExpressionLevel column. > head(df) ID Plant Tissue Gene ExpressionLevel 1 1 p1 t1 g1 366.53 2 2 p1 t1 g2 0.57 3 3 p1 t1 g3 11.81 4 4 p1 t2 g1 498.43 5 5 p1 t2 g2 2.14 6 6 p1 t2 g3 7.85 I
2011 Jul 11
2
Help! permission denied when accessing folder
Hi all, Running samba 3.5.5 in a Solaris non-global zone. I have created a folder (StudentJobApplications) on a share which I want to make accessible only to members of a Unix group (studempl). I have added myself to the group but when I or other group members try to access the folder via Windows Explorer I get the following: I:\StudentJobApplications is not accessible Access is denied Here
2005 Jun 06
1
Problem listing group membership from Windows
I planned using ifmember.exe from Windows 2000 resource kit to map the right drive-mappings to the right shares with logon-scripts. Unfortunately it seems as ifmember simply doesnt report the right groups for the users. Even tho "id user1" shows the right groups; "uid=2082(user1) gid=1002(Group1)roups=1002(Group1),545(Users),1000(Group0)", User is a member of group
2020 Feb 09
0
wbinfo -r reports strange gids on AD member
On 24.01.2020 14:01, Christian wrote: > On 23.01.2020 10:26, L.P.H. van Belle via samba wrote: >> Hai Christian, >> >>>>> Thism, this is just strange, Christian, did you already >>> run and if not, can you run it and post the ouputs. : >>>>> net cache flush >>>>> systemctl stop samba winbind >>>>> systemctl
2013 May 01
3
grep help (character ommission)
Hello, Banging my head against a wall here ... can anyone light the way to a pattern modification that would make the following TRUE? identical( grep( "^Intensity\\s[^HL]", c("Intensity","Intensity L", "Intensity H", "Intensity Rep1")), as.integer(c(1,4))) Thank you for your time. Sincerely, Joh
2003 Mar 25
2
Re: Bar plot with variable width (down a drill hole) - now missing intervals?
Hi again, Thanks Ted and Marc its works. But of course after pulling in in some real life data I discoverd one hitch. Often there are missing intervals. For example: from <- c(0, 1.2, 4.0, 4.2, 5.0, 25.0, 30.1, 45) to <- c(1.2, 4.0, 4.2, 5.0, 25, 30.1, 36.2, 50) intensity <- c(0, 1, 3, 2, 1, 0, 2, 5) barplot(intensity, width = -(to - from), space = 0, horiz = TRUE, ylim =
2010 Aug 06
2
Pausing script to allow user input from keyboard.
Hi all, I have written a simple R script to help me analyze a large data set. I would like to have the script pause to allow the user to input a character string that is subsequently used as a filename when saving tables. I have tried to use the "readline" command - this seems to work fine when entering commands one by one, but when I copy and paste the entire script into R,
2011 Aug 11
2
Extract values from a data frame
Hi everyone, I have a data frame that looks *sort of* like this: name <- letters[1:5] signal.1 <- c("12", "bad signal", "noise", "10", "X") length.signal.1 <- 5:9 intensity.signal.1 <- 3:7 signal.2 <- c("13", "noise", "19.2", "X", "V") length.signal.2 <- 2:6 intensity.signal.2
2006 Aug 28
7
Time plots
Hello all and thank you, I will try to make this as clear as I can. I have a matrix, at the top of the matrix are 4 time points, the first col describes the sample, then under each time point I have the intensity values of that sample. So : Samples 0 10 30 120 <- time A 200 300 400 1000 <- data B 100 400 200 100 C 500 400 200 1000 ^ | samples I would like to plot these however, all I
2007 Oct 02
2
plot question
Hello, I have a question about how to plot a series of data. The folloqing is my data matrix of n > n 25p 5p 2.5p 0.5p 16B-E06.g 45379 4383 5123 45 16B-E06.g 45138 4028 6249 52 16B-E06.g 48457 4267 5470 54 16B-E06.g 47740 4676 6769 48 37B-B02.g 42860 6152 19276 72 35B-A02.g 48325 12863 38274 143 35B-A02.g 48410 12806 39013 175 35B-A02.g 48417 9057 40923
2011 Oct 10
3
Superposing mean line to xyplot
Dear R-users, I'm using lattice package and function xyplot for the first time so you will excuse me for my inexperience. I'm facing quite a simple problem but I'm having troubles on how to solve it, I've read tons of old mails in the archives and looked at some slides from?Deepayan Sarkar but still can not get the point. This is the context. I've got data on 9 microRNAs, each
2024 Feb 13
2
[PATCH v2 3/8] fbdev: Do not include <linux/backlight.h> in header
Forward declare struct backlight_device and remove the include statement. Signed-off-by: Thomas Zimmermann <tzimmermann at suse.de> Reviewed-by: Jani Nikula <jani.nikula at intel.com> --- include/linux/fb.h | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/include/linux/fb.h b/include/linux/fb.h index 2ce2f5c2fca9a..7380d959c5d53 100644 --- a/include/linux/fb.h +++
2011 Oct 03
2
intensity map / plot
Dear R-list, I would like to generate an intensity map based on a x * y matrix. Each point in the matrix should get plotted at the coordinate: x = column / y = row with a color-intensity (for example gray-value) based on the actual value of this point. Is there a convenient package / function for this kind of plot? example data: x <- matrix(rnorm(100*100, 0, 2), 100, 100) thanks!
2009 Feb 14
2
superscript
Dear R-users. I'm struggeling to fix the superscript of a label of a figure axis. For some reason R doesn't recognize the "hat" symbol. plot(1,1,xlab="ligth intensity (PAR)",ylab=expression("mass Pteridium rhizomes" (gr/0.25m^2))) A very similiar scriptline does not give any problem at all: plot(1,1,xlab=expression("balsa plot basal