similar to: left end or right end

> Suppose you have four lifetime operations on the same address in memory, > with loads and stores all around them: > > start1--end1 .. start2--end2 > > If you remove start1 then you have a bare pointer, the memory came from > somewhere and you lose the optimization that loads before start1 become > undef, but you don't miscompile. This is assuming no looping after

>> Oh, I was reading "precedes/following" as having static (dominance) >> meaning. That is, in the above example you could not delete the store >> since it is not true that >> llvm.lifetime.end dominates it. >> >> Nick, is this what you had in mind? If not, then we must delete a >> matching llvm.lifetime.end, but it is not clear how we define

On 12/27/2012 12:35 PM, Rafael Espíndola wrote: >>> Oh, I was reading "precedes/following" as having static (dominance) >>> meaning. That is, in the above example you could not delete the store >>> since it is not true that >>> llvm.lifetime.end dominates it. >>> >>> Nick, is this what you had in mind? If not, then we must delete a

Can you explain why you need them as 'integer', A floating point representation can hold a value upto ~4.5e15 as an "integer" keeping the precision that you might need. Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. On Tue, Apr 26, 2016 at 1:11 PM, Andr? Luis Neves <andrluis at

Dear all: I converted the columns (Baci, Meti, Fungii, Protozoai) into integers (using excel) and then imported the data (.txt) into R. Interestingly, the other three variables were loaded as INT, but the 'Baci' one continued as Num. I imported the data using the following command line: X <- read.delim(file.choose(), header = TRUE, dec =

Dear useRs, Thanks for any advices # I do not know where are the examples how to mark groups # based on signal occurence in the additional variable: cf. variable c2, # How to calculate different calculations for groups defined by (split by occurence of c2 characteristic data) #First example of simple data #mexample 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17

Dear R-users, Attach with is my data..what i want to do is finding a suitable distribution for my data..I want to run a few test like the poisson and the exponential distribution. Please help me on how to find the p-value for poisson as well as the exponential distribution without knowing the parameter. Is it possible?? Thanks in advance. love, Anisah -------------- next

Hi, I was trying to get a graph in lattice with the following data frame (7 rows, 5 cols): chr start1 end1 meth positive 1 1 10 20 1.5 y 2 2 12 18 -0.7 n 3 3 22 34 2.0 y 4 1 35 70 3.0 y 5 1 120 140 -1.3 n 6 1 180 190 0.2 y 7 2 220 300 0.4 y I wanted the panels to be organized by 'chr' -

On 12/28/2012 04:20 AM, Rafael Espíndola wrote: >> Suppose you have four lifetime operations on the same address in memory, >> with loads and stores all around them: >> >> start1--end1 .. start2--end2 >> >> If you remove start1 then you have a bare pointer, the memory came from >> somewhere and you lose the optimization that loads before start1 become

I've been using the following code to plot using Sweave in version 1.9.1 library(RODBC) library(lattice) channel <-odbcConnectExcel("h:/water.xls") data <- sqlQuery(channel,"select * from `Sheet1$` where Test = 'TOC' and (Valve='5010-05' or Valve='8030-V26' or Valve='1180-08' or Valve='5040-08')") odbcClose(channel) srt <-

Hello all, Could someone help me with the time zones in understandable & practical way? I got completely stucked with this. Have googled for a while and read the manuals, but without solutions... ------------------------------------------------------------------- When data imported from Excel 2007 into R (2.13) all time variables, depending on date (summer or winter) get (un-asked for

Dear All, How to calculate multiple correlation coefficient R, using R. regards, Sukumar [[alternative HTML version deleted]]

Hello All, My question is regarding the attached plot. I would like to have multiple transparent green bands running the length (yaxis) of the plot the width of which is determined by the green lines at y=0 in the plot. Can you suggest a way to do it? For those who can't or are unwilling to download the file the plot is at http://www.twitpic.com/ma8w0 Thanks!

fb_do_apertures_overlap is returning wrong value when one aperture is completely whithin the other. Add generic ranges_overlap macro (probably kernel.h candidate) and use it here. Signed-off-by: Marcin Slusarz <marcin.slusarz at gmail.com> Cc: Dave Airlie <airlied at redhat.com> Cc: Peter Jones <pjones at redhat.com> Cc: Andrew Morton <akpm at linux-foundation.org> ---

Dear R-ers, In my question there are no statistics involved - it's all about data manipulation in R. I am trying to write a code that should replace what's currently being done in SAS and SPSS. Or, at least, I am trying to show to my colleagues R is not much worse than SAS/SPSS for the task at hand. I've written a code that works but it's too slow. Probably because it's

Dear R People: I have the following code that I use to convert a monthly zoo object to a data.frame, and it works perfectly: library(tseries) z <- get.hist.quote(instrument=inst1, start=start1,end=end1, quote=quot1,comp = "m") y <- as.ts(aggregate(z, as.yearmon, tail, 1)) y.df <- data.frame(y=y,time=time(y)) y.df$x <- ts(y.df[,1]) tsp(y.df$x) <-

Ok. I`m trying to run a Poisson glmm with an observation-level random intercept. But I`m getting the following error for the 'Baci' variable: 'Error: (maxstephalfit) PIRLS step-halvings failed to reduce deviance in pwrssUpdate'. I guess this message is because the baci variable is not a an integer, and cannot be transformed into an integer as R has a threshold of 2x10^9 even in

Hello, I really wonder how to distinguish between secs and mins in the example below. In other terms, how can I access the time unit in variable d ? start1 <- Sys.time(); stop1 <- Sys.time(); d <- stop1-start1; print(d); v<-unlist(strsplit(as.character(d), split=" ")); print(v) Time difference of 3.024054 secs [1] "3.02405381202698" stop1 <- Sys.time(); d

Dear R-users I am using RPART package to get regression trees. However having trouble getting the text function to put the full splitting rule number on the plot, instead to puts it in scientific notation. When a covariate has 1e4 or greater number of digits then the splitting rule number displayed on the plot is in scientific notation. But print.rpart displays the splitting rules in full.

Harry Sukumar would like to recall the message, "[CentOS] VMWare Server Install Problem". -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://lists.centos.org/pipermail/centos/attachments/20080213/c89d62e8/attachment.html>