similar to: Sweave function

Hi, Finland calling, Tinc, we have a problem:) have tried connect to a remote site overseas with tinc. I use w2K. I get following mesage: C:\Program Files\tinc>tincd -n vpn Cannot open config file C:\Program Files\tinc/vpn/tinc.conf: No such file or directory C:\Program Files\tinc> I have the directories and the files in correct places. Have compared to the ones at the other end.

Hi, I have a working Samba 4 AD which is used by Windows clients. I also have an LDAP server for use with Linux servers and web applications. What I really need is the Samba 4 AD to be the single maintained authentication database while providing an LDAP compatible server for web applications (and preferably Linux). I've looked at extending the Samba 4 schema, but that doesn't seem

Hello,   I could not find a clear solution for the follow question. please allow me to ask. thanks   mynames=cbind(c('a','b'),c(11,22)) lst=list(a=c(1,2), b=5) now I try to combine mynames and lst: a  1  11   a  2  11 b  5  22   thanks jian   [[alternative HTML version deleted]]

Hi, #make example data dat <- data.frame(matrix(rnorm(15),ncol=5)) colnames(dat) <- c("ab","cd","ef","gh","ij") If I want to get a subset of the data for the middle 3 columns, and I know the names of the start column and the end column, I can do this: mysub <- subset(dat,select=c(cd:gh)) If I wanted to do this just on the column names,

Let's say I have the data frame 'dd' below. I'd like to select one column from this data frame (say 'a') and keep its name in the resulting data frame. That can be done as in #2. However, what if I want to make my selection based on a vector of names (and again keep those names in the resulting data frame). My attempt is #4 but doesn't work. dd <- data.frame(a =

I have a list of file names, and a list of data frames contained in those files. mynames <- list.files() mydata <- lapply(mynames, read.delim) Every file contains two columns. > colnames(mydata[[1]]) [1] "Name" "NumReads" > colnames(mydata[[2]]) [1] "Name" "NumReads" I can set the colnames easily enough with a for loop. for (i in

Hi. i have an asterisk 11 installation that i run in my soho environment. My system has mysql to store all the cdrs. I would like make use of the mysql and store numbers and names. eg +4922123456789 "Atux Null". So when the +4922123456789 calls in my system the name "Atux Null" will pop up next to the number. at the moment i have a database called MyNames in mysql that has this

Hi, This code is trying to produce a series of graphics files, with plots of male and female disease rates by age, one plot per disease. The dataframe contains a variable 'Age' and a set of variables called 'Male_CVD, Female_CVD,Male_RTA,Female_RTA, and so on. For each disease, I want to pull out the column of data containing the word 'Male' and plot this against age, and then

Dee, No, I have not resolved the problem. But compiling with gcc seems to work "better" than C for AIX V6 I have the same problem as You when trying to start the executables. I get a core dump even when running "testparm". I also think that bad iconv support in AIX can be the problem, so I have tried to install GNU libiconv and GNU gettext after finding this hint on tng-samba

Hello! my data set has many variables. Unfortuantely, many of those variables contain spaces in their names. I need advice on: how to refer to variable names in the formula for "aggregate". See example below: ### Generating example data set: mydate = rep(seq(as.Date("2008-12-01"), length = 3, by = "month"),4) value1=c(1,10,100,2,20,200,3,30,300,4,40,400)

I am trying to use apply and a list to supply names to a set of tables I want to generate. Below is an example that I hope mimics the larger original problem. EXAMPLE aa <- c( 2,2,1,1,2) bb <- c(5,6,6,7,4) aan <- c("yes", "no") bbn <- c("a", "b", "c", "d") mynames <- c("abby", "billy") mylist <-

Thanks for all the help on my previous histogram problem. I intend to summarize the solutions back to the list Real Soon Now, but first, I've got another problem. I've made a bar chart that reports means. I'd like to put the number of observations on top of each bar. Here's what I've got: barplot((subset$x), col=grey(.5), ylab="Mean Engagement

Maybe there is a great website out there or white paper that discusses this but again my Google skills (or lack there of) let me down. I would like to know the best way to export several doubles from a function, where the doubles are not an array. Here is a contrived function similar to my needs: multipleoutput<-function(x) { squared<-x^2 cubed<-x^3 exponentioal<-exp(x)

I wanted to create a list with the names of variables and their values. So I wrote the following function. add.to.list.names.vars.1 <- function(lnv, vnv) { i <- 1 while (i < length(vnv)) { z <- as.character(eval(substitute(quote(vnv[i+1])))[[2]][[i + 2]]) lnv[[vnv[i]]] <- list(Name = z, Value = vnv[i+1]) i <- i + 2 } lnv } It works, but it is very

I have a dataframe with columns "ID",'date","estimate","actual" (but not necessarily in that order - I do a merge somewhere and that somehow messes up the order of the columns). How can I output it to a csv file with the columns in the order that I want? Thanks.

Hi, I have a very simple problem but I can't think how to solve it without using a for loop and creating a large logical vector. However given the nature of the problem I am sure there is a "1-liner" that could do the same thing much more efficiently. bascially I have a dataframe with characters in, eg >names.and.numbers (index) Name Fave.Number 1 John 7 2

Dear all, I have a data frame of dimension 720 columns by 360 rows, to which I am trying to add numerical row and column labels to, using the 'sequence' command. The original data, which I read in using 'read.table', had no such labels at all. I've got as far as successfully using the sequence command and getting the labels to display. However, I'm finding that for the

Hi Is it possible to plot values against strings, i.e. the x axis has people's names and the y axis as values, as shown below: 5 x 4 x x 3 x 2 x 1 0 Dave Tim Ian Steve Paul Sorry if this is a little primitive, but I think it gets the point across. regards Danny

As to call files of another softwares(as, Excel, minitab) to be manipulated inside of R-plus? Respectfully Regiane -------------- next part -------------- An HTML attachment was scrubbed... URL: https://stat.ethz.ch/pipermail/r-help/attachments/20011112/23b21666/attachment.html

Hi all, I would like to iterate through a list with named elements and access the names within an lapply / sapply call. One way to do this is iterate through the names and index the list with the name. Is there a way to iterate through the list elements themselves and access the element names within in the function? For example, mylist <-