Displaying 20 results from an estimated 4000 matches similar to: "Fitting a polynomial using lrm from the Design library"
2010 Jun 19
1
Extracting P-values from the lrm function in the rms library
Hello again R users,
I have a devilishly hard problem, which should be very simple. I hope someone out there will have the answer to this on the tip of their tongue.
Please consider the following toy example:
x <- read.table(textConnection("y x1 x2
indv.1 bagels 4 6
indv.2 donuts 5 1
indv.3 donuts 1 10
indv.4 donuts 10 9
indv.5 bagels 0 2
indv.6 bagels 2 9
indv.7 bagels 8 5
indv.8
2010 Jun 20
1
"Unable to fit" error message from the lrm function in the rms library
Hi all,
I have another question about the lrm function (from the rms library) that I cannot find the answer to.
I get an error message when I try to fit a model, and I don't know what to make of it. Please forgive me for not having a toy example, but it appears the size and complexity of my data is somehow causing the error. The best I can do is show you what I type and what errors I get.
2010 Jul 12
3
Continuing on with a loop when there's a failure
Hi R sages,
Here is my latest problem. Consider the following toy example:
x <- read.table(textConnection("y1 y2 y3 x1 x2
indv.1 bagels donuts bagels 4 6
indv.2 donuts donuts donuts 5 1
indv.3 donuts donuts donuts 1 10
indv.4 donuts donuts donuts 10 9
indv.5 bagels donuts bagels 0 2
indv.6 bagels donuts bagels 2 9
indv.7 bagels donuts bagels 8 5
indv.8 bagels donuts bagels 4 1
indv.9
2010 Jun 16
2
Accessing the elements of summary(prcomp(USArrests))
Hello again,
I was hoping one of you could help me with this problem. Consider the sample data from R:
> summary(prcomp(USArrests))
Importance of components:
PC1 PC2 PC3 PC4
Standard deviation 83.732 14.2124 6.4894 2.48279
Proportion of Variance 0.966 0.0278 0.0058 0.00085
Cumulative Proportion 0.966 0.9933 0.9991 1.00000
How do I access the
2017 Sep 14
3
Help understanding why glm and lrm.fit runs with my data, but lrm does not
Dear all,
I am using the publically available GustoW dataset. The exact version I am using is available here: https://drive.google.com/open?id=0B4oZ2TQA0PAoUm85UzBFNjZ0Ulk
I would like to produce a nomogram for 5 covariates - AGE, HYP, KILLIP, HRT and ANT. I have successfully fitted a logistic regression model using the "glm" function as shown below.
library(rms)
gusto <-
2008 May 29
2
Troubles plotting lrm output in Design Library
Dear R-helpers,
I'm having a problem in using plot.design in Design Library. Tho
following example code produce the error:
> n <- 1000 # define sample size
> set.seed(17) # so can reproduce the results
> age <- rnorm(n, 50, 10)
> blood.pressure <- rnorm(n, 120, 15)
> cholesterol <- rnorm(n, 200, 25)
> sex <-
2005 Aug 22
1
How to add values on the axes of the 3D bi-variable lrm fit?
Dear r-list,
When I try to plot the following 3D lrm fit I obtain only arrows with labels
on the three axes of the figure (without values).
fit <- lrm(y ~ rcs(x1,knots)+rcs(x2,knots), tol=1e-14,X=T,Y=T)
dd <- datadist(x1,x2);options(datadist='dd');
par(mfrow=c(1,1))
plot(fit,x1=NA, x2=NA, theta=50,phi=25)
How can I add values to the axes of this plot? (axes with the
2011 May 18
1
logistic regression lrm() output
Hi, I am trying to run a simple logistic regression using lrm() to calculate a
odds ratio. I found a confusing output when I use summary() on the fit object
which gave some OR that is totally different from simply taking
exp(coefficient), see below:
> dat<-read.table("dat.txt",sep='\t',header=T,row.names=NULL)
> d<-datadist(dat)
> options(datadist='d')
2008 Apr 03
1
Design package lrm summary and factors
Hello, I have question regarding the lrm function and estimating the odds
ratio between different levels of a factored variable.
The following code example illustrates the problem I am having. I have a
data set with an outcome variable (0,1) and an input variable (A,B,C). I
would like to estimate the effect of C vs B, but when I perform the summary
I only get A vs B and A vs C, even though I
2004 Jan 29
2
Calculating/understanding variance-covariance matrix of logistic regression (lrm $var)
Hallo!
I want to understand / recalculate what is done to get
the CI of the logistic regression evaluated with lrm.
As far as I came back, my problem is the
variance-covariance matrix fit$var of the fit
(fit<-lrm(...), fit$var). Here what I found and where
I stucked:
-----------------
library(Design)
# data
D<-c(rep("a", 20), rep("b", 20))
V<-0.25*(1:40)
V[1]<-25
2017 Sep 14
0
Help understanding why glm and lrm.fit runs with my data, but lrm does not
> On Sep 14, 2017, at 12:30 AM, Bonnett, Laura <L.J.Bonnett at liverpool.ac.uk> wrote:
>
> Dear all,
>
> I am using the publically available GustoW dataset. The exact version I am using is available here: https://drive.google.com/open?id=0B4oZ2TQA0PAoUm85UzBFNjZ0Ulk
>
> I would like to produce a nomogram for 5 covariates - AGE, HYP, KILLIP, HRT and ANT. I have
2017 Sep 14
1
Help understanding why glm and lrm.fit runs with my data, but lrm does not
Fixed 'maxiter' in the help file. Thanks.
Please give the original source of that dataset.
That dataset is a tiny sample of GUSTO-I and not large enough to fit this
model very reliably.
A nomogram using the full dataset (not publicly available to my knowledge)
is already available in http://biostat.mc.vanderbilt.edu/tmp/bbr.pdf
Use lrm, not lrm.fit for this. Adding maxit=20 will
2004 Feb 16
1
Binary logistic model using lrm function
Hello all,
Could someone tell me what I am doing wrong here?
I am trying to fit a binary logistic model using the lrm function in Design.
The dataset I am using has a dichotomous response variable, 'covered'
(1-yes, 0-no) with explanatory variables, 'nepall', 'title', 'abstract',
'series', and 'author1.'
I am running the following script and
2009 Jul 09
2
datadist() in Design library
Hi I got an error message using datadist() from Design package:
> library(Design,T)
> dd <- datadist(beta.final)
> options(datadist="dd")
> lrm(Disease ~ gsct+apcct+rarct, x=TRUE, y=TRUE)
Error in eval(expr, envir, enclos) : object "Disease" not found
All variables inclduing response variable "Disease" are in the data frame
2011 May 05
7
Draw a nomogram after glm
Hi all R users
I did a logistic regression with my binary variable Y (0/1) and 2
explanatory variables.
Now I try to draw my nomogram with predictive value. I visited the help of R
but I have problem to understand well the example. When I use glm fonction,
I have a problem, thus I use lrm. My code is:
modele<-lrm(Y~L+P,data=donnee)
fun<- function(x) plogis(x-modele$coef[1]+modele$coef[2])
2009 Jun 17
2
djustment values not defined
Hello,
I am using
mod1 <- lrm(y~x1+x2,na.action=na.pass,method="lrm.fit")
summary(mod1)
and I've got the following error:
Error in summary.Design(mod1) : adjustment values not defined here or with datadist for x1 x2
Many thank,
Amor
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2008 Apr 17
1
Error in Design package: dataset not found for options(datadist)
Hi,
Design isn't strictly an R base package, but maybe someone can explain
the following.
When lrm is called within a function, it can't find the dataset dd:
> library(Design)
> age <- rnorm(30, 50, 10)
> cholesterol <- rnorm(30, 200, 25)
> ch <- cut2(cholesterol, g=5, levels.mean=TRUE)
> fit <- function(ch, age)
+ {
+ d <- data.frame(ch, age)
+
2010 Oct 04
2
i have aproblem --thank you
dear professor:
thank you for your help,witn your help i develop the nomogram successfully.
after that i want to do the internal validation to the model.i ues the bootpred to do it,and then i encounter problem again,just like that.(´íÎóÓÚerror to :complete.cases(x, y, wt) : ²»ÊÇËùÓеIJÎÊý¶¼Ò»Ñù³¤(the length of the augment was different))
i hope you tell me where is the mistake,and maybe i have
2011 Apr 12
1
Datadist error
Dear all,
I have performed a simple logistic regression using the lrm function from
the Design library. Now I want to plot the summary, or make a nomogram. I
keep getting a datadist error: options(datadist= m.full ) not created with
datadist.
I have tried to specify datadist beforhand (although I don't know why it
should be done):
ddist<-datadist(d) ##where d is my dataset
2011 Jun 23
2
Rms package - problems with fit.mult.impute
Hi!
Does anyone know how to do the test for goodness of fit of a logistic model (in rms package) after running fit.mult.impute?
I am using the rms and Hmisc packages to do a multiple imputation followed by a logistic regression model using lrm.
Everything works fine until I try to run the test for goodness of fit: residuals(type=c("gof"))
One needs to specify y=T and x=T in the fit. But