similar to: Problem about zero

Hello everyone, I have been working on a code which simply repeatedly appends a number into a vector and write a file. However, it could not be properly implemented when I use it. It works when I run it line by line. I wonder what is the problem and I appreciate anyone who is willing to help. The function and the example code is attached. Any advice is appreciated! Best, Yen

Hello dear uesRs, I am working on modeling both level one and level two heteroscedasticity in HLM. In my model, both error variance and variance of random intercept / random slope are affected by some level two variables. I found that nlme is able to model heteroscedasticity. I learned how to use it for level one heteroscedasticity but don't know how to use it to model the level

Hello everyone, I know where is wrong. I forget to specify the parameters in my function. Thank you for anyone who was trying to help me! Best, Yen ?? b88207001 at ntu.edu.tw: > Hello everyone, > > It seems that I was not successfully attached the code. Here is the > code. I appreciate any help! > > Best, > Yen > > ?? b88207001 at ntu.edu.tw: > >> Hello

Hello everyone, It seems that I was not successfully attached the code. Here is the code. I appreciate any help! Best, Yen ?? b88207001 at ntu.edu.tw: > Hello everyone, > > I have been working on a code which simply repeatedly appends a > number into a vector and write a file. However, it could not be > properly implemented when I use it. It works when I run it line by

I would like to estimate the sigma matrix of multinormal distribution through ML. But I don't know how to optimize the parameter sigma. Could any one help me? Thank you so much~ Yen Lee

If you don't get a response it is because you did not read the Posting Guide which indicates that the R-sig-ME mailing list is where this question would have been on-topic. -- Sent from my phone. Please excuse my brevity. On August 16, 2017 6:17:03 AM PDT, b88207001 at ntu.edu.tw wrote: >Hello dear uesRs, > >I am working on modeling both level one and level two

A better place for this post would be on R's mixed models list: r-sig-mixed-models . Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Wed, Aug 16, 2017 at 6:17 AM, <b88207001 at ntu.edu.tw> wrote: > Hello dear

I'm new to post in R-help and my native language is not English. I apologize if my sentence is not fluent to read. I am doing a simulation study and I need to execute SAS and read a SAS code in R. I try the following code but it doesn't work. system('"c:\\program files\\SAS\\SAS 9.1\\sas.exe" "c:\\syntax.sas"') can anyone give me some help with this?

Dear all, I've written a function and repeated it for 5000 times with loops with different value, and the messages returned are the output I set and 15 warnings. I would like to trace the warnings by stopping the loop when warning came out. Does anyone know how to make it? Thanks a lot for your help. Yen [[alternative HTML version deleted]]

You could declare a matrix much larger than you intend to use. This works with a few megabytes of data. It is not very efficient, so scaling up may become a problem. m22 <- matrix(NA, 1:600000, ncol=6) It does not work to add a new column to the matrix, as in you get an error if you try m22[ , 7] but convert to data frame and add a column m23 <- data.frame(m22) m23$x7 <- 12 The only

Zapping a vector of small numbers to zero would cause problems when printing the results of summary(). For example, if zapsmall(c(2.220446e-16, ..., 2.220446e-16)) == c(0, ..., 0) then print(summary(2.220446e-16), digits = 7) would print Min. 1st Qu. Median Mean 3rd Qu. Max. 0 0 0 0 0 0 The same problem can also appear when

Isn?t that the correct outcome? The user can change the number of digits if they want to see small values? -- Change your thoughts and you change the world. --Dr. Norman Vincent Peale > On Dec 17, 2023, at 12:11?AM, Steve Martin <stevemartin041 at gmail.com> wrote: > > ?Zapping a vector of small numbers to zero would cause problems when > printing the results of summary().

I think what's been missed is that zapsmall works relative to the absolute largest value in the vector. Hence if there's only one item in the vector, it is the largest, so its not zapped. The function's raison d'etre isn't to replace absolutely small values, but small values relative to the largest. Hence a vector of similar tiny values doesn't get zapped. Maybe the line

x["V2"] is more efficient than using drop=FALSE, and perfectly normal syntax (data frames are lists of columns). I would ignore the naysayers, or put a comment in if you want to accelerate their uptake. As I understand it, one of the main reasons tibbles exist is because of drop=TRUE. List-slice (single-dimension) indexing works equally well with both standard and tibble types of data

I was quite suprised to discover that applying `zapsmall` to a scalar value has no apparent effect. For example: > y <- 2.220446e-16 > zapsmall(y,) [1] 2.2204e-16 I was expecting zapsmall(x)` to act like > round(y, digits=getOption('digits')) [1] 0 Looking at the current source code, indicates that `zapsmall` is expecting a vector: zapsmall <- function (x, digits =

Le 17/12/2023 ? 18:26, Barry Rowlingson a ?crit?: > I think what's been missed is that zapsmall works relative to the absolute > largest value in the vector. Hence if there's only one > item in the vector, it is the largest, so its not zapped. The function's > raison d'etre isn't to replace absolutely small values, > but small values relative to the largest.

>>>>> Serguei Sokol via R-devel >>>>> on Mon, 18 Dec 2023 10:29:02 +0100 writes: > Le 17/12/2023 ? 18:26, Barry Rowlingson a ?crit?: >> I think what's been missed is that zapsmall works relative to the absolute >> largest value in the vector. Hence if there's only one >> item in the vector, it is the largest, so its

I need to read csv files repeatedly, named data1.csv, data2.csv,? data24.csv, 24 altogether. That is, data<-read.csv(?data1.csv?) ? data<-read.csv(?data24.csv?) ? Is there a way to do this in a loop? Thank you. Steven from iPhone [[alternative HTML version deleted]]

Thanks to all. Very helpful. Steven from iPhone > On Jan 14, 2023, at 3:08 PM, Andrew Simmons <akwsimmo at gmail.com> wrote: > > ?You'll want to use grep() or grepl(). By default, grep() uses extended > regular expressions to find matches, but you can also use perl regular > expressions and globbing (after converting to a regular expression). > For example: >

Le 18/12/2023 ? 11:24, Martin Maechler a ?crit?: >>>>>> Serguei Sokol via R-devel >>>>>> on Mon, 18 Dec 2023 10:29:02 +0100 writes: > > Le 17/12/2023 ? 18:26, Barry Rowlingson a ?crit?: > >> I think what's been missed is that zapsmall works relative to the absolute > >> largest value in the vector. Hence if